Lecture 25 Flashcards

1
Q

Central dogma of molecular biology

A

DNA (dna replication)
to RNA through transcription
To proteins through translation

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2
Q

Gene expression

A

Genes encode for messenger RNA (mRNA) which code for proteins (central dogma)

Genes encode for functional RNAs such as transfer RNAs (tRNA) and rinosomal RNAs (rRNA)

Generally activity of proteins produce the inherited traits of organism

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3
Q

Can flow of genetic information be reversed?

A

No

Unless it’s an RNA virus whose rna can be used to code for DNA in a host cell (these viruses have the enzyme reverse transcriptase)

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4
Q

Gene expression is the process by which

A

Information from a gene is used in the synthesis of a functional gene product

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5
Q

Gene products

A

Often coded for by messenger RNAs /mRNAs but they can also be functional RNAs such as transfer RNAs (tRNAs) or ribosomal RNAs (rRNAs)

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6
Q

Transcriptome

A

Totality of RNA transcripts expressed by a cell or an organism

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7
Q

Proteome

A

Entire set of proteins that is/ or can be expressed by a genome, cell, tissue, or organism at a certain time

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8
Q

Transcription

A

Synthesis of RNA molecule complementary to a portion of a strand of DNA acting as a template

Thousands of transcripts are being produced every second in cells

Occurs in 3 stages
Occurs in the nucleus in eukaryotes and cytoplasm in prokaryotes

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9
Q

3 transcription stages

A

Initiation
Elongation
Termination

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10
Q

Where does transcription occur in a eukaryote and prokaryote

A

Eukaryote- nucleus

Prokaryote- cytoplasm

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11
Q

Gene consists of what? In terms of transcription

A

Promoter and a transcription unit

Specific sequences of nucleotide in prokaryote and eukaryote promoters differ

Eukaryotes have a TATA box within their promoter consisting of 30 bases pairs of Ts and As located upstream from the transcription start point

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12
Q
A
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13
Q

Transcription unit

A

Stretch of DNA that transcribes a primary transcript (the RNA molecule)

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14
Q

Initiation steps

A

Transcription factor proteins bind to the promoter in the areas of the TATA box

Transcription factors recruit RNA polymerase.
- combination of transcription factors and RNA polymerase forms the transcription initiation complex
- only 1 of the strands to be transcribed is the template strand

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15
Q

Elongation steps

A

As RNA polymerase slides along the transcription unit, it separates the DNA strands and opens the transcription bubble

RNA polymerase breaks the H bonds between the nitrogenous bases of the 2 DNA strands

This allows in of the DNA strands to function as a template for RNA synthesis

RNA is transcribed via complementary base pairing (just like dna except it’s AU/CG in RNA)

RNA transcribed from 5 to 3’ ends adding new RNA nucleosides to the 3’ end. Using triphosphate ribonucleosides

DNA left behind by RNA polymerase recoils back into double helix (note: newly synthesized RNA molecules consist of a single strand. Not a double helix)

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16
Q

4 different ribonucleoside triphosphates used to form RNA molecule

A

Contain a 5 carbon ribose sugar instead of a deoxyribose sugar that is used in DNA nucleotides (note the hydroxyl OH group on the 2’ carbon)

This means an A encountered on the DNA template strand with result in uracil (U) nucleotide added to the growing RNA molecule

Instead of Thymine

Uracil is a pyrimidine like thymine

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17
Q

Which RNA sequence below is complementary to the given DNA sequence 5’ TTAAGGCC3’

A

Because RNA transcription is antiparallel, we rewrite the DNA sequence to

3’CCGGAATT5’
Then follow the AC/TG rule

5’GGCCUUAA3’

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18
Q

Termination

A

When RNA polymerase reaches the end of a gene it encounters a terminator sequence of nucleotides

This signals termination of transcription

RNA polymerase and the RNA transcript are released from the DNA

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19
Q

Recap

DNA to RNA

A

initiation to
Elongation to
Termination

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20
Q

mRNA

A

A long polynucleotide strand possessing the code for a particular polypeptide chain on it

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21
Q

mRNA code

A

Only 4 letters

A. G. C. U

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22
Q

How many amino acids and what are they

A

Building blocks of protein

20 amino acids

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23
Q

mRNA codes of length 1,2,3 could code for

A

4 amino acids

Length 1 4^1=4

Length 2 4^2 =16
Length 3. 4^3=64

24
Q

Codons

A

3 letter words (ex. 3 nucleotide bases in a row) are called codons

As we saw this means there are 4^3 =64 possible codons that make up the genetic code

25
Q

Genetic code

A

Start codon (AUG) starts translation but also encodes for amino acid methionine

26
Q

Start codon

A

AUG
Typically

27
Q

Stop codons examples

28
Q

Stop codons

A

Stop translation

Don’t code for any amino acids

29
Q

When can bacterial mRNAs be translated

A

They can be immediately translated into polypeptides once they are transcribed in the cytoplasm

30
Q

Where are eukaryote mRNAs synthesized

A

In the nucleus and have to be processed or packaged for release into cytoplasm

31
Q

Eukaryotic packaging

A

Initial mRNA transcribed in the nucleus is called pre-mRNA (precursor mRNA)

After processing in nucleus RNAs are called mature mRNAs

32
Q

RNA processing involves 3 steps

A

Additional of a guanine cap

Addition of a poly (A) tail

Removal of introns by splicing

33
Q

Addition of a guanine cap stage in RNA processing

A

A guanine (or methylated) cap is added to 5’ end of a pre-mRNA
by a capping enzyme while the mRNA is still being transcribed in the nucleus

  • protects mRNAs from degradation by RNA exonucleases once the mRNAs enter the cytosol
  • facilitates the transport of mRNAs from the nucleus, out through the nuclear pores, and into the cytosol
  • is the site where ribosomes attach to mRNA at the beginning of translation in the cytosol
34
Q

Addition of poly (A) tail
Stage in RNA processing

A

Polyadenylation signal allows enzyme poly(A) polymerase in the nucleus to attach to pre-mRNAs and add 50-250 adenine nucleotides one at a time to the 3’ end of the pre-mRNAs

This forms a poly(A) tail at the 3’ end of each pre-mRNA

35
Q

Why is the poly (A) tail important in RNA processing

A

To allow for export through nuclear membrane

Makes translation of mRNA into amino acids and proteins easier

Length of the tail may determine the number of times an mRNA is translated before it is enzymatically degraded in the cytosol by RNA exonucleases.

36
Q

Removing of introns by splicing in translation of RNA

A

Pre-mRNAs contain alternating sections of introns and exons

Introns are spliced out of the mRNA and the exons are connected together such that mRNA includes only exons

Therefore all introns are excluded from mature mRNAs

37
Q

Exons

A

Expressed sequences

Exit nucleus

RNA processing

38
Q

Introns

A

Intervening sequences

Staying in the INterior of the nucleus

In RNA processing

39
Q

Summary of packaging RNA

A

Transcription->
Addition of poly (A) tail and RNA splicing ->
Mature mRNA

40
Q

mRNA mature

A

Consists of a protein coding region, 2 untranslated regions (UTRs), 5’ cap and a 3’ poly(A) tail

41
Q

Transfer RNA (tRNA)

A

No affinity between amino acids and mRNAs, so u need something that can connect them

Like a code reader

tRNAs are the code readers

Small RNAs made in the nucleus (74-95 nucleotides in length) that are highly folded. Having both secondary and tertiary structure in addition to their primary structures

42
Q

Primary structure

A

Sequence of nucleotides making up the RNA molecule

43
Q

tRNA secondary structure

A

Like a clover leaf with 3 stem loops where they are double stranded due to complementary base pairing

At one end of the tRNA there is a site that can associate with an amino acid

Complementary base pairing between nucleotides in a stem loop

At the end is a region of 3 nucleotide called an anticodon that is complementary to one of the mRNA codons

44
Q

Add amino acids to the tRNA

A

Aminoacyl-tRNA synthetase enzymes in the cytosol add the correct amino acid into the tRNA with the appropriate anticodon

45
Q

Translation

A

Synthesis of a polypeptide on a ribosome using the code from an mRNA (translated from DNA)

Occurs in cytosol in both eukaryotes and prokaryotes

3 stages. Initiation, elongation, termination

46
Q

Where does translation occur
In prokaryotes? Eukaryotes?

A

Cytosol for both

47
Q

3 stages of translation

A

Initiation

Élongation

Termination

48
Q

Initiation translation

A

1st step. Binding together an initiator tRNA carrying the amino acid methionine, the mRNA and small ribosomal subunit

Initiator tRNA has anticodon UAC
Small ribosomal subunit with its tRNA binds initially to the mRNA at the mRNAs 5’ end

Small subunit scans along the mRNA until it lines up over the start codon on the mRNA

Base pairing occurs between the tRNA anticodon and the start codon AUG on the mRNA. This pairing establishes the correct reading frame for translation of the codons along the rest of the mRNA. Essential as there isn’t “punctuation” along the mRNA that separates one codon from the next

Code is “commaless “

Large subunit binds onto small subunit, completing initiation stage of translation

Completed ribosomal has 3 sites that can accommodate tRNAs: E,P, and A sites

49
Q

Ribosomal subunits consist of

A

Molecules of both ribosomal RNA ( rRNA ) and proteins

Although only a few rRNA are present in each ribosome, they make up about half the mass of the ribosome

50
Q

Where are ribosomal subunits synthesized in eukaryotes

A

Nucleolus in nucleus

Leave the nucleus and become functional in cytoplasm

51
Q

Methionine represents the

A

First of many amino acids joined together one at a time by the ribosome to form a long polypeptide chain

52
Q

Translation key

A

E=exit site
P= peptidyl site
A= aminoacyl site

53
Q

Elongation cycle adds

A

One new amino acid at a time

To the new forming polypeptide chain

54
Q

Elongation

Translation

A

At the begging of each cycle. Polypeptide chain is held by the tRNA in the P site

At the end of the it’s held again by a new tRNA in the P site

Chain increases in length by one amino acid during each cycle

At the beginning of the first elongation cycle the P site is occupied by a charged tRNA with methionine attached to it. (E and A sites are empty)

A tRNA with a new amino acid enters the empty A site with an anticodon complementary to the codon exposed in the A site (charged tRNA is entering the empty A site)

Peptidyl transferase in the large subunit catalyzes the formation of a peptide bond between the 2 amino acids attached to the 2 tRNAs held in P and A sites

Ribosome now translocates along the mRNA a distance of 3 nucleotides in the 5’ to 3’ direction

This shifts the uncharged tRNA in the P site to the E site and the charged tRNA in the A site to the P site. A site left empty

Uncharged tRNA in the E site exits ribosome

Empty A site is no ready to receive a new tRNA bringing in the next amino acid to be added to the polypeptide chain

This ends one elongation cycle with the polypeptide chain again held by a new tRNA in the P site

Cycle is repeated over and over. Growing polypeptide chain 1 amino acid at a time.

The genetic code is non overlapping. This means successive triplet codons are read in order to not successive nucleotides