Lecture 19 Flashcards
What is an Euler Product
Let f be a multiplicative arithemetical function such that the series ∑f(n) is absolutely convergent. Then the sum of the series can be expressed as an absolute convergent
infinite product
- ∑_(n=1)^∞ f(n) = ∏_p (1 + f(p) + f(p^2) + . . . )
extended over all primes
Euler product for completely multiplcative function
∑_(n=1)^∞ f(n) = ∏_p 1/(1 − f(p))
∑_(n=1) f(n)/n^s
If f is multiplicative express as an Euler product
∏_p (1 + f(p)/p^s + f(p^2)/p^(2s) + . . . ) if σ > σa
∑_(n=1) f(n)/n^s
If f is completely multiplicative express as an Euler product
∏_p (1 − f(p)/p^s)^(−1) if σ > σa.
Let s0 = σ0 + it0 and assume that the Dirichlet series ∑f(n)/n^(s_0) has bounded partial sums, say
- ∣∑_(n≤x) f(n)/n^(s_0)∣ ≤ M, for all x ≥ 1. Then for each σ > σ0, give the bound of
- ∣ ∑_(a<n≤b) f(n)/n^s∣
∣ ∑_(a<n≤b) f(n)/n^s∣ ≤ 2M a^(σ_0−σ) (1 + ∣s − s0∣/(σ − σ_0))
If the series ∑ f(n)/n^s coverges for s = σ0 +it0 what can be said about convegrence of σ > σ0
It converges for all σ > σ0
If the series ∑ f(n)/n^s diverges for s = σ0 +it0 what can be said about convegrence of σ < σ0
It diverges for these values
What is the abscissa of convergence
Different to the abscissa of absolute convergence
If the series ∑f(n)/n^s does not converge everywhere or diverge everywhere, then there exists a real number σc, called the abscissa of convergence, such that the series converges
for all s in the half-plane σ > σ_c and diverges for all s in the half-pane σ < σ_c
Give the bounds of inequality for σ_a − σ_c
For any Dirichlet series with σ_c finite, we have
0 ≤ σ_a − σ_c ≤ 1