Lec 4 Flashcards
What is the Goldman Equation (simplified):
Ex = 58mV / z * log10 ([X]out / [X]in)
Membrane Potential (Vm) is dependent primarily on its ________ to ions and thus the membrane potential will always fall between two equilibrium potentials. *Except* during electrophysiological experiment
a. Nernst potential E(k)
b. Permeability
c. neither
Permeability (Goldman Equation)
Goldman Equation: If Px increases what will happen to the Vm?
increase or decrease?
increase
- Goldman Equation: Resting membrane potentials depend on the ionic gradients for what 3 ions?
- Which is most important and, which is least important?
K+ – Most important
Na+
Cl- – Least Important
When Vm = Ex , the net flow…
a. increases
b. decreases
c. is equal to 0
d. equal to infinity
C. Equal to zero
no driving force
As Vm moves farther from Ex net flow will…
a. increase
b. decrease
c. stay the same
d. equal to 0
a. increase
driving force increases
What is the equation for Driving Force?
Vm - Ex = Driving force
(part of Ohm’s law)
Ix = Gx(Vm-Ex)
What would happen to EK if we increased the external concentration of KCl ?
EK would move closer to 0
*Note: high K+ inside the cell.
out - in would be closer to zero
What would happen to EK if we decreased external concentration of KCl?
EK would become more negative
nernst Ek = -95 mV
out - in = more inside and greater difference
What would happen to resting Vm if we decreased external concentration of KCl?
Vm will increase in negativity
* Ek will increase in negativity and so will Vm
What would happen to EK if we increase external concentration of KCl?
Vm will move closer to zero
*EK will move closer to zero so will Vm
What would happen to EK and Vm if we increased the number of K+ leak channels?
Vm would become more negative (increased Permeability)
and Ek would be unchanged
What would happen to the EK and Vm if we decreased the number of K+ leak channels?
Vm would become more positive (decrease K+ permeability)
EK would be unchanged
Which of these ions has the greatest driving force?
K+, Na+, Cl-
Na+
Vm - ENa = -64mV - +65 = 100 mV