hess' law Flashcards

1
Q

What is hess’s law?

A

The enthalpy change of a reaction is independent of the route taken

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2
Q

What are enthalpy cycles?

A

An enthalpy cycle is a pictorial representation showing the alternative routes of reaction between reactants and products

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3
Q

Why do we use enthalpy cycles?

A

The enthalpy change of a reaction can’t always be direct;y measured so we use enthalpy cycles to help us indirectly calculate the enthalpy change

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4
Q

What are some conditions of enthalpy cycles?

A
  • they are triangular
  • in each corner there should be the same umber of each atom as well as energy, matter is also conserved .
  • the sides of the triangle are arrows
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5
Q

What is the enthalpy cycle (combustion) using the equation below?
[enthalpy change of the reaction]
6C(s)+ 3H2(g)-> C6H6(l)

A

Carbon and hydrogen can be combusted to form CO2 +H2O
Benzene can be combusted to form CO2+H2O

                       Delta H 6C(s)+ 3H2(g)→→→ C6H6(l)

[pretend there are arrows here, A and B, A from the 6c to the 6co2 and B from the C6 to the 3h2o]
6CO2(g)+3H2O(l)

Delta H= A-B (vectors) 
KJ/mol
C6H6 : -3267
C:-394
H2: -286

Calculating A, you know what just look at 4:19 of

https://www.youtube.com/watch?v=f0B3zPJPk2U&list=PLkocNW0BSuEFvnpnhj8fKN-KFUOlnKiT0&index=16&t=183s

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6
Q

What are enthalpy cycles basically

A

Vectors but not fun

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7
Q

What is the standard enthalpy of formation (define)

A

The enthalpy change when one mole of a substance is formed from it’s constituent elements in their standard states under standard conditions

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8
Q

The experimentally determined values for the enthalpy change of combustion does not always agree with values in the data booklet. Suggest 2 reasons why?

A

This could be because non-standard conditions were used, incomplete combustion of the glucose may have also occurred

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9
Q

Glucose can be formed according to the equation below: 6C+6H2+3O2→C6H12O6
The enthalpy change of formation of glucose cannot be determined directly.
Suggest a reason why this is the case.

A
  • Rate is too slow
  • activation energy too high
  • CO2 and H2O formed instead
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