acid-base titrations Flashcards
What are titrations?
A form of volumetric analysis :
- known volume and concentration of a solution is reacted with a measured volume of a solution
- can be used to find chemical unknowns.
What chemical unknowns can be investigated through titrations?
Concentration, molar mass, formula, water of crystallization
What are used in titrations?
Solutions with a known concentration (standard solution)
What is the process of titrations?
Using a pipe tote add a measured/suitable volume of x into a conical flask (base). Then add 3 drops of a suitable indicator to the flask (phenolphthalein, methyl orange etc). Fill the burette with a suitable volume of y solution (acid usually). Open the valve on the burette to allow a small quantity of y to flow into the flask of x and gently swirl the conical flask containing x solution so that the color change in the indicator would be more accurate. Repeat the process until the end-point is reached. Measure the volume of y that has been added to solution x and then calculate the unknowns.
What are standard solutions?
- solutions of a known concentration, allows us to calculate unknowns
What is concentration?
How much solute is dissolved in a given volume of solvent
What is the method of making a standard solution?
- carefully weigh out the required mass of the solute
- dissolve the solute into the chosen solvent in a beaker.
- transfer the solution into a volumetric flask, rinse the beaker with the initial solvent and add washings to the volumetric flask.
- add some of the solvent to the volumetric flask and make sure not to fill up to the graduation line.
- add solvent, drop by drop until the bottom of the meniscus is sitting on the line, do not allow the solution to fill above the line.
- mix the solution thoroughly and invert the flask multiple times.
What are the steps for the initial calculations of a standard solution?
- work out the number of moles required.
- calculate the molar mass of the required substance
- calculate the mass of the substance that is required.
Example: the process of the initial calculations with the below info.
- 250 cm^3 solution of NaOH
- 0.1 mol/dm^3
N= cxv =0.1 x 0.25 ->0.025 moles required Mr of NaOH \: 23+1+16 ->40 Mass = moles x mr 0.025 x 40 = 1g
In general, the calculations can follow certain steps. What are the calculations used to find?
Concentration of the solution, molar mass, etc
25 cm3 of 0.1 mol/dm3 of a base NaOH is titrated with 22.5 cm3 of an acid HCl.
What is the concentration of the acid involved in this titration?
HCl + NaOH -> NaCl + H2O
V= 0.025 dm3 C= 0.1mol/dm3 … 0.025 x 0.1 = 0.0025 moles of base ‘ Moles of acid: 1:1 ratio So HCl = 0.0025 moles
0.0025 = 0.0225 x c
C=0.1111….mol/dm3
.. 0.1mol/dm3
1.5G of an acid was dissolved in water in order to make a solution with a volume of 250 cm3. 25 cm3 of a solution this acid HX was titrated with 22.5cm3 of a base NaOH which had a concentration of 0.1mol/dm3
What is the Mr of the acid involved in this titration?
Reaction equation: HX + NaOH -> NaX + H2O Calculate the amount in mol of base has reacted: C=0.1 V= 0.0225 Mol= 0.1 x 0.0225 -> 0.00225 moles. Calculate the amount in mol of acid that was used to make the initial solution:
1:1
… 0.00225 moles of HX in 25 cm3
250/25=10
0.00225 x10
=0.0225mol
Calculate the mr of the acid:
Mr=m/n
1.5/0.0225
=66.667g/mol
A student decides to make up a standard solution of sodium hydroxide. She carefully measures out 10 g directly onto a balance. She adds this to a conical flask with 100 ml of water using a glass stirring rod.
- the student made a number of errors in her method. How could she improve her method?
She could use a weighing boat.
She could use a volumetric flask
She could invert the flask rather than stirring
A student decides to make up a standard solution of sodium hydroxide. She carefully measures out 10 g directly onto a balance. She adds this to a conical flask with 100 ml of water using a glass stirring rod
— having learnt the correct way of making up a standard solution the student decides to are up a standard solution of Mg(OH)2 the student wants to obtain 1l of 0.1mol/dm3. What mass of Mg(OH)2 should she use?
Mol of Mg(OH)2 = 0.1 x1 =0.1 mol N=0.1 Mr= 58.3 Mass = 0.1 x 58.3 = 5.83 g
A titration between sulphuric acid and sodium hydroxide is carried out:
H2SO4(aq) +2NaOH (aq) -> Na2SO4(aq) +2H2O (l)
25 cm3 of 0.0440 mol/dm3 NaOH is neutralized by 17.5cm3 of dilute H2SO4 (aq).- -calculate the amount in moles of NaOH used in the titration.
C= 0.0440
V=0.025
N=0.0440x0.025
=0.0011mol