Exam 2 Lecture 13 Enzyme Kinetics Flashcards

1
Q

A linear kinetic trend describes:

A

“Wishful thinking” as v = k[S]

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2
Q

A hyperbolic kinetic trend describes:

A

Michaelis-Menton Model

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3
Q

A sigmoidal kinetic trend describes:

A

Cooperative binding

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4
Q

Was is the equation for irreversible rxn and what does it allude to?

A

v = k[S]^n

Alludes to reaction rate as n indicates reaction order ie how many things have to come together to make product

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5
Q

1S—>P describes:

A

First order kinetics: v = k[S]^1

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6
Q

2S—>P or Sa + Sb —> P describes:

A

2nd order kinetics: v = k[S]^2 or k[Sa][Sb]

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7
Q

S—>P describes:

A

Zero order kinetics: v = k[S]^0 = k
Is a unimolecular rxn because an internal change. No breaking of bonds or do not an enzyme (uncatatalyzed) or enzyme is saturated ie all active sites are full

(Irreversible rxn)

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8
Q

S —>k1—>P; and the reverse from P to S (k-1)

A

REVERSIBLE rxn

Substrate is being both used and created

v = k1[S]^n - k-1[P]^m

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9
Q

At EQUILIBRIUM by definition, the forward rate equals

A

The reverse rate

v= k1[S] - k-1[P] = 0

k1[S] = k-1[P]

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10
Q

For a reversible rxn at equilibrium, we now can redefine our 2 equilibrium constants which are:

A

K(A) = association constant; making product k1/k-1

K(D) = dissociation constant; unmake product 1/K(A)

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11
Q

T/F: catalysis is not a 1st order rxn?

A

True

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12
Q

MM enzymes follow _ order kinetics

A

1st order kinetics

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13
Q

Km

Name and definition

A

Michaelis Constant
[S] where rxn rate is half maximal or half of the active sites are full
Related to the affinity of the enzyme for the substrate

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14
Q

Vmax

Name and definition

A

Maximum velocity

Maximum rate possible for a given concentration of enzyme

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15
Q

Kcat

Name and definition

A

Turnover number
How fast ES complex proceed to E + P
Number of substrate molecules converted per active site per time (first order rate constant sec-1)

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16
Q

Ks

Name and definition

A

N/A

A dissociation constant for substrate binding

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17
Q

Kcat/Km

Name and definition

A

Specificity constant

Measure of enzyme performance by predicting the fate of E*S (ability to convert substrate to product)

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18
Q

Laboratory condition:

[S] is much less than Km:

A

At very low substrate concentration :
Vo = (Vmax/Km)*[S]; that is, the reaction is first order with the rate directly proportional to the substrate concentration.

19
Q

Laboratory condition:

[S] is much greater than Km:

A

At high substrate concentration, when [S] is much greater than Km, Vo = Vmax;

that is, the rate is maximal. The reaction is zero order, independent of substrate concentration.

20
Q

Laboratory condition:

[S] = Km

A

When [S] = Km, then Vo = Vmax/2

Thus, Km is equal to the substrate concentration at which the reaction rate is half its maximal value.

21
Q

What is the specificity constant?

A

(Kcat/Km)

22
Q

A good enzyme would have:

A

Kcat much greater than k-1 and
Kcat/Km = k1

good enzyme will take enzyme substrate complex and go to product

23
Q

A poor enzyme would have?

A

Kcat much less than k-1 and
Kcat/Km = 1/Km

bad enzyme we are falling apart and going back to substrate

24
Q

Multiple binding site enzymes CAN follow Michaelis-Menten kinetics as long as they are __

A

NONCOOPERATIVE

  • cooperative enzyme = sigmoidal shape bc active sites are not equivalent; they’re not independent
  • If each active site is independent of its neighbor, we get hyperbolic curve we expect of MM enzyme (kinetics) noncooperative
25
Q

Inhibitors can be either:

A

Irreversible (tightly bound to the enzyme) or reversible (rapid dissociation of the enzyme-inhibitor comples)

26
Q

Reversible inhibitors use what type of interaction to bind?

A

Noncovalent interactions

27
Q

Reversible inhibitors result in one of the following types of inhibition:

  1. Competitive
  2. Noncompetitive
  3. Uncompetitive

Which are allosteric inhibitors?

A

Noncompetitive and uncompetitive

28
Q

Competitive inhibition:

Vmax is _
Km is _

A

Vmax is CONSTANT
Km is VARIABLE

no effect on Vmax but increase Km. Diminishes the rate of catalysis by reducing the proportion of enzyme molecules bound to substrate; takes longer to get to Vmax

29
Q

Noncompetitive inhibition:

Vmax is _
Km is _

A

Vmax is VARIABLE
Km is CONSTANT

Km is unaltered and Vmax is decreased. Inhibitor and substrate can bind simultaneously to an enzyme at different binding sites; inhibitor lowers the conc of functional enzyme as it can bind to free enzyme or the enzyme-substrate complex

30
Q

Uncompetitive inhibition:

Vmax is _
Km is _

A

Vmax is VARIABLE
Km is VARIABLE

Vmax and Km are reduced by equivalent amounts. Inhibitor binds only to the enzyme-substrate complex. The enzyme-substrate-inhibitor complex does not form any product

31
Q

Irreversible inhibitors _ enzymes

A

Inactivate enzymes

32
Q

Group-specific irreversible enzyme:

What it does:

A

Target a specific amino acid

33
Q

Group-specific irreversible enzyme:

Specificity for active site:

A

Low

34
Q

Group-specific irreversible enzyme:

Textbook example:

A

DIPF targets Serines

35
Q

Substrate Analogs irreversible enzyme:

What it does?

A

Substrate mimic, modifies enzyme

36
Q

Substrate Analogs irreversible enzyme:

Specificity for active site?

A

High

37
Q

Substrate Analogs irreversible enzyme:

Textbook example?

A

TPCK looks like Phe to chymotrypsin

38
Q

Suicide inhibitors irreversible inhibitor:

What it does?

A

Modified a substrate so is unable to form products

39
Q

Suicide inhibitors irreversible inhibitor:

Specificity for active site?

A

Very high

40
Q

Suicide inhibitors irreversible inhibitor:

Textbook example?

A

N,N-Dimethylpropargylamine inactivates FAD

41
Q

Km that is low (small number)

A

Reaches Vmax at a lower [S]; tight binding

42
Q

Km that is high (large number)

A

Reaches Vmax at a higher [S]; lower affinity ie higher [S] required to reach 1/2 Vmax

43
Q

Km=

A

(k-1 +k2)/k1