Electrochemistry Flashcards

1
Q

Redox reactions involves the movement of _________ from one substance to another

A

Electrons

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2
Q

Oxidation is the _______ of electrons

A

Loss

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3
Q

Reductions is the _______ of electrons

A

Gain

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4
Q

A voltaic Cell (Galvanic Cell)

A

Uses a spontaneous redox reaction (ΔG < 0) to generate electrical energu where the system does work on the surroundings

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5
Q

An electrolytic Cell

A

Uses Electrical energy to drive a nonspontaneous redox reaction (ΔG > 0) where the surroundings do work on the system

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6
Q

What are the two types of electrode?

A
  1. Anode
  2. Cathode
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7
Q

What type of half reactions occurs at the anode?

A

The oxidatio, the anode has a negative charge

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8
Q

What type of reaction occurs at the Cathode?

A

Reduction, the cathode has a positive charge

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9
Q

What direction does electron flow between the two electrode?

A

Flow from left ot right ( from the anode to the cathode)

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10
Q

Cell potential (Ecell)

A

Is the difference in electrical potiental between the two electrode (or the two half reaction)

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11
Q

Electrons flow spontaneously from the _______ to _______

A

From the anode to cathode

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12
Q

The cell potential is ________ for a reaction to be spontaneous

A

Positive (Ecell > 0)

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13
Q

For a nonspontaneous reaction the cell potential is _________

A

Negative (Ecell < 0)

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14
Q

When the cell potential is __________ the reaction is at equilibrium

A

Equal to zero

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15
Q

The standard cell potential (Eocell)

A

Is the sum of the sum of the electrical potential of the half reaction

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16
Q

Standard cell potential are only used for a __________ reaction

A

Reduction reaction so if its an oxidation reaction just flip the sign

17
Q

What the formula for calculating the Eocell

A

Eocell = Eoreduction - Eooxidation

18
Q

A strong oxidizing agent forms a ________ reducing agent & vice versa

A

Weak

19
Q

Equation used to relate ΔGo & Eocell

A

ΔGo = -nFEocell

20
Q

Equation used for Eocell when not using standard concentration (1M)

A

Ecell = Eocell - 0.0592V / n log Q

21
Q

What the equation used when Eocell is at equilibrium and using standard condition such as 1M (& 298.15K)

A

Eocell = 0.0592 V/ n log K

or

log K = nEocell / 0.0592V