Chapter 12 Review

Question 1

Competitive Inhibition

Answer 1

Vmax = same
Km = increasing

Question 2

Uncompetitive Inhibition

Answer 2

Vmax = decreasing
Km = decreasing

Question 3

v0 =

Answer 3

k2 [ES]

Question 4

vmax =

Answer 4

k2 [E]T

Question 5

v0= ?/?

Answer 5

vmax[S]/Km+[S]

Question 6

_____ and _____ are specific for specific systems

Answer 6

Km and kcat

Question 7

kcat is

Answer 7

the rate of catalysis (aka turnover #) ; tells you how fast it is working. Dependent on how much enzyme

Question 8

Km is

Answer 8

k-1 +k2/k1 ; Michaelis constant

Question 9

v0 =

Answer 9

initial velocity (where t = 0) ; v0 = (vmax [S])/(Km+[S])

Question 10

vmax =

Answer 10

the max velocity of a reaction occurs at high substrate concentration when the enzyme is saturated (when it is entirely in the ES form)

Question 11

kcat/Km can’t be greater than

Answer 11

1

Question 12

kcat/Km is the

Answer 12

second-order rate constant of enzymatic reaction ; the measure of an enzyme’s catalytic efficiency

Question 13

Ordered Bidistribution Reaction

Answer 13

Fosfomycin must bind first then L-cys will bind and product will be

Question 14

Random Bisubstrate Reaction

Answer 14

It can bind in any order but both must be bound to get products

Question 15

Double Displacement Bisubstrate Reaction

Answer 15

Don’t encounter each other until enzyme is present