Alkanes/Haloalkanes Flashcards

1
Q

Define Ozone

A

O3 in atmosphere - absorbs UV

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2
Q

Outline the danger of Holes in the Ozone

A

O3 decrease = increase UV & skin cancer

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3
Q

Define CFCs and outline their impact on Ozone

A

Chlorofluorocarbons - decrease in O3

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4
Q

Outline the 2 reactions of how CFCs reduce Ozone

A
  1. Cl* + O3 -> ClO* + O2
  2. ClO* + O3 -> Cl* + 2O2
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5
Q

Outline the overall reaction of CFC Ozone reduction

A

203 -> 3O2

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6
Q

Why is alkane combustion important?

A

Hi energy release

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7
Q

Outline Complete combustion

A

(Enough O2 present) X + O2 -> CO2 + H2O

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8
Q

Outline incomplete combustion

A

(Not enough O2) X+O2 -> CO+C+H2O

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9
Q

Outline the purpose of Catalytic converters

A

Removes CO & NOx (toxic)

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10
Q

Outline the process inside a catalytic converter

A

HC, CO, NOx (from air N2) + rhodium catalyst -> N2, H2O, CO2

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11
Q

Outline the danger of S impurities

A

H in H2O in atmosphere = H2SO4

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12
Q

What’s used in Flue Gas Desulfurisation?

A

CaO + gypsum

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13
Q

Identify the importance of Flue Gas Desulfurisation?

A

Pollutants -> global warming, H+ rain, health issues

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14
Q

Define Cracking

A

C-C-C-C-C-C -> C-C C-C C-C (more useful)

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15
Q

Outline the conditions and products of Thermal Cracking

A

Conditions: 1200K & 7000 kPa
Products: Mixture of CnH2n+2 & CnH2n

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16
Q

Outline the Conditions and Products of Catalytic Cracking

A

Conditions: 720K, Normal Pa, Zeolite catalyst
Products: Aromatic Compounds and C rings

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17
Q

Define Chlorination of Alkanes

A

Alkanes + Halogens ->(UV)-> Halogenoalkanes

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18
Q

Outline how Alkane Chlorination works

A

UV breaks down Halogen bonds -> Free Radicals & initiation, propagation & termination

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19
Q

Outline the Initiation in Chlorination (define and reaction)

A

Halogen broken down
Cl2 ->(UV)-> 2Cl*

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20
Q

Outline the 2 Propagation steps in Chlorination (define and both reactions)

A

H replaced and Cl* reformed as a catalyst
Cl* + CH4 -> *CH3 + HCl
CH3 + Cl2 -> CH3Cl + Cl

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21
Q

Outline the Termination step of Chlorination (define and 3 reactions)

A

2 free radicals join to form stable product
CH3 + CH3 -> C2H6
OR
Cl
+ * CH3 ->CH3Cl
OR
Cl
+ Cl
-> Cl2

22
Q

Define Fractional Distillation

A

Process used to separate hydrocarbons of different lengths from crude oil through different boiling points

23
Q

Outline the 3 steps of Fractional Distillation

A
  1. Crude Oil vaporised
  2. Vapours rise, cool, condensed
  3. Proucts siphoned off
24
Q

Outline how the hydrocarbons are separated when vapourised

A

Depends on boiling points
Long C Chain = condense low
Short C chain = condense high
Mushroom trays - collect can’t go back down

25
Define Haloalkane
Alkane bonded to Halogen atom(s)
26
Define Nucleophile
e- pair donor - attracted to areas of low e- density
27
Define Electrophile
e- pair acceptor - attracted to areas of hi e- density
28
Define Electronegativity
Ability 4 atom to attract e- in covalent bond
29
Outline the 3 types of Haloalkane
Primary = 2 or 3 H Secondary = 1 H Tertiary = No H
30
Outline the 3 physical properties of Haloalkanes
1. C Chain increase=boiling point + VDW forces increase 2. Down group 7 = boiling point increase 3. If < room temp state is (g)
31
Outline the 3 factors affecting haloalkane boiling point
1. C chain length (more VDW) 2. Type of Halogen (more e-=stronger VDW) 3. Primary, Secondary or Tertiary
32
Outline why there are permanent dipole forces in Haloalkanes
Electronegativity diff with C & Halogen C is + dipole Halogen is - dipole
33
Outline the outlier to Haloalkane permanent dipoles
Iodine (so big)
34
Why don't permanent dipoles impact the boiling points?
Due to increasing strength of VDW Forces the hi e- Number outweighs loss of permanent dipole
35
Outline the 3 types of Haloalkanes
Primary = 2/3 H Secondary = 1 H Tertiary = No H
36
Outline the trend in BP for the type of Haloalkane
Primary highest: Closer together -> stronger VDW = more energy to break
37
Why are Haloalkanes only slightly soluble in water?
Must break VDWs & H bonds between H2O molecules
38
What does the reactivity of Haloalkanes depend on?
Bond length: C-F < C-Cl < C-Br < C-I Bond strength: C-I < C-Br < C-Cl < C-F Molecule size: F < Cl < Br < I
39
Define Nucleophilic substitution
Nucleophile replaces a group/atom in OG Molecule
40
Describe the general mechanism for Haloalkane Nucleophilic Substitution
1.-ve Nucleophile attacks Chiral C 2. C has 5 bonds 1 bond breaks 3. Halogen removed, becomes -
41
Outline the nucleophilic substitution of Haloalkanes with Hyrdoxide Ions
Haloalkanes + OH- boiled under reflux + (aq) NaOH/(aq) KOH Forms alcohols
42
Describe the mechanism for Nucleophilic Substitution of Haloalkanes with Hydroxide Ions
OH- (nucleophile) attacks + dipole C from behind Halogen leaves - becomes Halide ion
43
Outline the nucleophilic substitution of Haloalkanes with Cyanide Ions
Haloalkanes + CN- boiled under reflux + (aq) ethanol Forms Nitriles
44
Outline the reaction for the nucleophilic substitution of Haloalkanes with Hydroxide ions.
R-X + OH- -> R-OH + X-
45
Outline the reaction for the nucleophilic substitution of Haloalkanes with Cyanide ions.
R-X + CN- -> R-CN + X-
46
Describe the mechanism for the nucleophilic substitution of Haloalkanes with Cyanide ions.
Same as Hydroxide ions
47
Outline the conditions of the nucleophilic substitution of ammonia and alkanes
Ethanolic ammonia in a sealed tube - primary amine formed
48
Outline the 4 steps of the nucleophilic substitution of ammonia and alkanes
1. e- pair on NH3 attacks + dipole C 2. NH3 must remove a H atom & Halide ion forms 3. H atom forms +NH4 with another NH3 molecule 4. +NH4 attracted to -Halide ion
49
Outline the 3 conditions for the elimination of Haloalkanes
1. NaOH/KOH as a base 2. No H2O present ethanol needed as a solvent 3. Heat needed
50
Describe the mechanism of the elimination reaction of Haloalkanes
1. :OH- attacks H atom on C adjacent to C atom with Halogen to form H2O 2. H breaks off forming a C=C - Halogen atom breaks off = Halide ion
51
Outline how the type of halogenoalkane determines either an elimination or nucleophilic substitution
Primary = Nucleophilic Substitution Secondary = Both Tertiary = Elimination