AAMC 3 - Chem/Phys Flashcards
The relative thermodynamic stability of isomeric organic compounds can be inferred from which of the following types of experimental data?
A. Boiling points
B. UV–visible absorption spectra
C. Mass spectroscopic fragmentation patterns
D. Heats of combustion
D. Heats of combustion
AAMC Solution: The answer to this question is D because the relative thermodynamic stability of isomers can be determined based on the amount of heat produced when the compounds are combusted;
less heat, greater stability.
Why does boiling point fail to measure thermodynamic stability of isomers?
The thermodynamic stability of a compound is determined by the INTRAmolecular forces.
Boiling points are a measure of the strength of INTERmolecular forces that hold molecules together.
What determines thermodynamic stability?
The thermodynamic stability of a compound is determined by the INTRAmolecular forces.
Will a more thermodynamically stable isomer produce more or less heat than a less stable isomer upon combustion?
A more thermodynamically stable isomer will produce LESS heat upon combustion.
Heats of combustion measures the heat produced when compounds are combusted, or burned in oxygen. If less heat is produced, the compound is _____ stable; when more heat is produced, the compound is _____ stable to begin with. This is a great way to determine the thermodynamic stability of a compound.
Heats of combustion measures the heat produced when compounds are combusted, or burned in oxygen. If less heat is produced, the compound is more stable; when more heat is produced, the compound is less stable to begin with. This is a great way to determine the thermodynamic stability of a compound.
Radioactive tritium (3H) labeled guanine has been used to measure the rate of biochemical processes that involve its binding or incorporation.
Given that water is the solvent for this type of experiment, what is the best site for tritium labeling?
A. I
B. II
C. III
D. IV
A. I
AAMC: The answer to this question is A, because the best site for tritium labeling would not exchange the tritium ions for protons in water. All of the N−H sites (II−IV) would readily exchange tritium protons due to their lone pair-facilitating protonation and subsequent tritium exchange with water, but the C−H site (I), lacking a lone pair, would retain its tritium label.
Consider the following data.
Substance
- K*a
- K* w /Ka
H2CO34.3 × 10–72.3 × 10–8HCO3–5.6 × 10–111.8 × 10–4
Based on these data, HCO3– is best categorized as:
A. a base since Ka > Kb for this ion.
B. a base since Kb > Ka for this ion.
C. an acid since Ka > Kb for this ion.
D. an acid since Kb > Ka for this ion.
B. a base since Kb > Ka for this ion.
AAMC: The answer to this question is B because Kb for HCO3– is larger than Ka for this ion. The value of Kb is given as Kw/Ka for H2CO3. By comparing Ka to Kb, it is clear that amphoteric HCO3– is more basic than acidic in water.
In its lowest-energy electron configuration, zinc has a:
A. filled 3d energy level and a filled 4s energy level.
B. half-filled 3d energy level and a filled 4s energy level.
C. filled 3d energy level and a half-filled 4s energy level.
D. half-filled 3d energy level and a half-filled 4s energy level.
A. filled 3d energy level and a filled 4s energy level.
AAMC Solution: The answer to this question is A, based on subshell filling rules, the 12 valence electrons occupy 4s and 3d subshells, which are completely filled. Zn is element number 30 and in Group 12 of the Periodic Table.
In some complexes, the central cation can be bonded to the same ligand in multiple places. This is called ________, and it generally requires large organic ligands that can double back to form a second (or even third) bond with the central cation.
________ therapy is often used to sequester toxic metals (lead, arsenic, mercury, and so on).
In some complexes, the central cation can be bonded to the same ligand in multiple places. This is called chelation, and it generally requires large organic ligands that can double back to form a second (or even third) bond with the central cation.
Chelation therapy is often used to sequester toxic metals (lead, arsenic, mercury, and so on).
Define the period of a wave
The period is the amount of time from the beginning of a wave or signal to the beginning of the next wave or signal.
What is the maximum energy of the UV photons generated by this plasma pencil? (Note: Speed of light is c = 3.0 × 108 m/s; Planck’s constant is h = 6.63 × 10–34 J•s; wavelength emitted is 200-300 nm)
A. 7 × 10–16 J
B. 5 × 10–17 J
C. 3 × 10–17 J
D. 1 × 10–18 J
D. 1 × 10–18 J
AAMC Solution: The answer to this question is D because the energy of a photon is given by E = hf. The passage gives the wavelength of the UV radiation. Inserting this into the formula for photon energy yields:
E = hc/λ
= 6.6 × 10-34 J × (3 × 108 m/s)/(200 × 10-9 m)
≅ 1 × 10-18 J.
That the electric field is uniform between the electrodes means that the electric field lines:
A. are more closely spaced at the positive electrode than at the negative one.
B. intersect halfway between the electrodes.
C. are more closely spaced at the negative electrode than at the positive one.
D. are equally spaced at both electrodes and between them.
D. are equally spaced at both electrodes and between them.
AAMC Solution: The answer to this question is D because, by definition, electric field lines are equally spaced in a uniform field.
When two amino acids are joined via a peptide bond, what is the mass of the byproduct of this reaction? (Note: Assume that the amino acids were not modified by protecting groups.)
A. 17 amu
B. 18 amu
C. 32 amu
D. 44 amu
B. 18 amu
Peptide bonds are formed via a dehydration reaction.
The product of a dehydration reaction is water. What is the atomic mass of water?
Atomic mass H2O = 2(mass of H) + mass of O = 2(1)+16=18 amu
What is an acetylation reaction?
The addition of a carbonyl bound to a methyl onto something else.
What is the concentration of hydroxide ion for a solution with pH = 10?
A. 10–10
B. 10–6
C. 10– 4
D. 10–2
C. 10– 4
What is the resistivity of something with a maximum conductivity of 5.0 × 10–3 (Ω∙cm)–1?
A. 0.002 Ω•cm
B. 50 Ω•cm
C. 200 Ω•cm
D. 500 Ω•cm
Resistivity is the inverse of the conductivity
1/5.0 × 10–3 (Ω∙cm)–1 = 200 Ω∙cm.
What aspect of a sigmoidal graph can help you measure its cooperativity?
The steepness of the curve
Which halogen has the highest first ionization energy?
A. Iodine
B. Bromine
C. Chlorine
D. Fluorine
D. Fluorine
AAMC Solution: The answer to this question is D, because fluorine is the smallest halogen and appears at the top of the column of Group 17. With fewer electrons to shield the valence electron from the nucleus, fluorine will exhibit the highest first ionization energy.
Jack Westin Advanced Solution:
Fluorine is the halogen with the smallest radius and the fewest shielding electrons. It will have the highest first ionization energy and is the correct answer.
Which of the following properties of a 2.3 MHz ultrasound wave remains unchanged as it passes into human tissues?
A. Frequency
B. Wave speed
C. Amplitude
D. Wavelength
A. Frequency
AAMC Solution: The answer to this question is A because the frequency of a wave is not affected by the medium through which it propagates.
Jack Westin Advanced Solution:
The frequency is determined by the source, not the medium through which the wave travels. It remains unchanged when a wave changes mediums and is the correct answer.
Assume that in a study of rat tissues, fluid flows at a speed of 0.30 mm/s through a typical capillary opening of ~2.5 × 104 μm2 caused by a burst microbubble. Given this, which of the following is closest to the volume flow rate of fluid passing through the opening?
A. 4.5 × 106 μm3/s
B. 7.5 × 106 μm3/s
C. 1.2 × 107 μm3/s
D. 4.5 × 107 μm3/s
B. 7.5 × 106 μm3/s
The answer to this question is B because the volume flow rate is given by velocity*area:
2.5 × 104 µm2 × 0.30 mm/s = 7.5 × 106 µm3/s.
Given that the speed of sound in the rat tissues was 1500 m/s with a frequency of 2.3 MHz, the wavelength of the ultrasound wave used in the study was closest to:
A. 34.5 mm.
B. 6.5 mm.
C. 1.5 mm.
D. 0.65 mm.
D. 0.65 mm
The answer to this question is D because the wavelength is given by v/f=wavelength
(1500 m/s)/(2.3 MHz) = 0.65 mm.
What is the group name of these elements?
The post-transition metals
What is the group name of these elements?
The Metalloids
What is the group name of these elements?
The reactive non-metals
If a reaction is spontaneous, the value of K must be:
A. greater than 1.
B. equal to ΔG.
C. less than 1.
D. equal to zero.
A. greater than 1.
The answer to this question is A, because a spontaneous reaction is one that exhibits ΔG < 0.
Since ΔG= –RTln(Keq), this means that Keqmust be > 1 in a spontaneous reaction.