3.1.8.1 - born-haber cycles Flashcards
if starting from LiCI (s) how do you create born haber cycles going up
then going down
enthalpy of formation (exo) -> Li(S) + 1/2CL2(g)
enthalpy of atomisation of chlorine Li(s) + cl(g)
enthalpy atomisation of lithium Li(g) + cl (g)
1st ionisation energy of lithium li+(g) + cl(g) + e-
going down..
1st electron affinity of chlorine (exo)
Li+(g) + Cl-(g)
lattice enthalpy of formation of lithium chloride
LiCI (s)
steps going up __ ____ ____ as the steps going down
steps going up is the same as the steps going down
when calculating born haber cycles
when you go w the arrow you …
when you go agianst the arrow you…
when you go with the arrow, keep the sign the same
when you go against the arrow change the sign
down arrows are ..
exo
up arrows are ..
endo
if calc enthalpy for 1/2 cl2 and values given is for cl2 what do you do
half the enthalpy
is lattice enthalpy exo or endo
exo
is enthalpy of formation exo or endo
exo
is enthalpy of atomisation endo or exo
endo
is ionisation energies endo or exo
endo
is first e- affinity endo or exo
exo
every other e- affinity apart from 1st
endo
we represent atomisation steps …
first w metal
second non metal
The greater the value of the lattice enthalpy, the ….
stronger the ionic bonds
Smaller ions and higher charge ions give stronger ionic bonding
because
Smaller ions are more closely packed in the lattice, so are more
attracted to each other, resulting in high lattice enthalpy.
* Ions with high charge have stronger electrostatic forces of attraction
between the ions which results in high lattice enthalpy