2.3 acid-base and redox reactions Flashcards
strong acids will:
fully dissociate in solution
acid-base titration calculations: Neutralisation calculation
26.25.0 cm3 of 0.050 dm-3 sodium carbonate was completely neutralised by 20.00 cm3 of dilute hydrochloric acid.
Calculate the concentration in mol dm-3 of the hydrochloric acid.
Step 1: Write the balanced symbol equation
Na2CO3 + 2HCl → 2NaCl + H2O + CO2
Step 2: Calculate the amount, in moles, of sodium carbonate reacted by rearranging the equation for amount of substance (mol) and dividing the volume by 1000 to convert cm3 to dm3amount (Na2CO3) = 0.025 dm3 x 0.050 mol dm-3 = 0.00125 mol
Step 3: Calculate the moles of hydrochloric acid required using the reaction’s stoichiometry
1 mol of Na2CO3 reacts with 2 mol of HCl, so the molar ratio is 1 : 2 Therefore 0.00125 moles of Na2CO3 react with 0.00250 moles of HCl
Step 4: Calculate the concentration, in mol dm-3, of hydrochloric acid using conc = mol/vol = 0.0025/0.0200concentration (HCl) (mol dm-3) = 0.125 mol dm-3
weak acids will:
partially dissociate in solution
strong acid examples:
HCl
HNO3
H2SO4
weak acid examples:
HCOOH
CH3COOH
strong base examples:
- NaOH
- KOH
- Ba(OH)2
weak base examples:
- NH3
- CH3
- NH2
acid + metal →
salt + hydrogen
acid + metal oxide →
salt + water
acid + metal hydroxide
salt + water
acid + metal carbonate
salt + water + carbon dioxide
apparatus for titration
*Beaker
*Burette
*Volumetric Pipette
*Conical Flask
*Volumetric Flask
how to make a standard solution
- weigh out precise amount of solid
- add to small amount of water and dissolve the solid with a glass rod
- transfer to a conical flask
- rinse the beaker with distilled water
- make up to the scratch mark with more water and add stopper
how to work out conc of a standard solution:
concentration of a solution is the amount of solute dissolved in a solvent to make 1 dm3 of solution
oxidation number of an ion
same as its charge