2.3 acid-base and redox reactions Flashcards
strong acids will:
fully dissociate in solution
acid-base titration calculations: Neutralisation calculation
26.25.0 cm3 of 0.050 dm-3 sodium carbonate was completely neutralised by 20.00 cm3 of dilute hydrochloric acid.
Calculate the concentration in mol dm-3 of the hydrochloric acid.
Step 1: Write the balanced symbol equation
Na2CO3 + 2HCl → 2NaCl + H2O + CO2
Step 2: Calculate the amount, in moles, of sodium carbonate reacted by rearranging the equation for amount of substance (mol) and dividing the volume by 1000 to convert cm3 to dm3amount (Na2CO3) = 0.025 dm3 x 0.050 mol dm-3 = 0.00125 mol
Step 3: Calculate the moles of hydrochloric acid required using the reaction’s stoichiometry
1 mol of Na2CO3 reacts with 2 mol of HCl, so the molar ratio is 1 : 2 Therefore 0.00125 moles of Na2CO3 react with 0.00250 moles of HCl
Step 4: Calculate the concentration, in mol dm-3, of hydrochloric acid using conc = mol/vol = 0.0025/0.0200concentration (HCl) (mol dm-3) = 0.125 mol dm-3
weak acids will:
partially dissociate in solution
strong acid examples:
HCl
HNO3
H2SO4
weak acid examples:
HCOOH
CH3COOH
strong base examples:
- NaOH
- KOH
- Ba(OH)2
weak base examples:
- NH3
- CH3
- NH2
acid + metal →
salt + hydrogen
acid + metal oxide →
salt + water
acid + metal hydroxide
salt + water
acid + metal carbonate
salt + water + carbon dioxide
apparatus for titration
*Beaker
*Burette
*Volumetric Pipette
*Conical Flask
*Volumetric Flask
how to make a standard solution
- weigh out precise amount of solid
- add to small amount of water and dissolve the solid with a glass rod
- transfer to a conical flask
- rinse the beaker with distilled water
- make up to the scratch mark with more water and add stopper
how to work out conc of a standard solution:
concentration of a solution is the amount of solute dissolved in a solvent to make 1 dm3 of solution
oxidation number of an ion
same as its charge
oxidation number of hydrogen
+1 except in metal hydrides (NaH) when its -1
oxidation number of oxygen
-2 except when in peroxides (H2O2) or bonded to fluorine
oxidation number of fluorine
-1
oxidation number of chlorine
-1 except when its bonded to oxygen or fluorine
oxidation number of group 1 + 2
1+, 2+
disproportionation reaction
reaction where the same element is both reduced and oxidised
what happens to the reducing agent
it has been oxidised
what happens to the oxidising agent
it has been reduced
orbitals in each subshell:
s = 1
p = 3
d = 5
f = 7