STR Analysis Flashcards
for heterozygous loci (equation)
P = 2pq
P
probability
p & q
frequencies of alleles in a given population
find the probability: for the locus D3S1358 & individual is 15,18 with frequencies of 0.2825 & 0.1450 respectively
P = 2(0.2825)(0.1450) = 0.0819
3 steps in data interpretation
- asses the internal size standards (ISS), allelic ladders & controls
- assess each sample for the presence of extraneous peaks & determine if they may interfere with the interpretation process
- assess the data from each sample
Internal Size Standards (ISS)
- contains DNA fragments of known sizes that provide reference points determining the length of a samples DNA fragments
- in general, the peaks or bands from as ISS are uniformity or miscalled peaks cans indicate problems with the sample, injection &/or run
allelic ladder
contain the more common alleles in general population for specific chromosomal locations
positive control
- positive controls are included in most commercial DNA analysis kits
- amplified with each batch of samples
- show the expected alleles
- if no peaks are seen, this may indicate problem with amplification or injection
ISS negative control
see nothing
ISS data evaluation
peak height percentage
Peak Height Percentage
- heterozygous peaks within a locus should be similar in height to each other
- heterozygous alleles have peak heights that are within 70% of each other
peak height percentage: degraded DNA
may have peak height percentages much lower than 70%
how to calculate Peak Height Percentage
(small/big) * 100
sex identification with Amelogenin
6 bp deletion on the X chromosome
the following may indicate a mixture:
- the presence of more than 2 alleles at any one locus
- imbalanced &/or unexpected peak height percentage