Solvents Flashcards

1
Q

strength of london dispersion forces

A

weak intermolecular force

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2
Q

strength of dipole-dipole forces

A

intermediate strength

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3
Q

strength of hydrogen bonding

A

strong interaction

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4
Q

solute

A

This is the substance that gets
dissolved. It can be a solid, liquid, or even a gas. Think of it as the “guest” in the mixture.

A substance dissolved in a solvent to form a solution

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5
Q

solvent

A

This is the substance that does the
dissolving. It’s usually present in a larger amount compared to the solute and acts as the “host” in the mixture, providing the medium for dissolving
the solute.

The dissolving medium of a solution

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6
Q

polarity of hydrocarbons

A

In general hydrocarbons are non polar

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7
Q

Aprotic solvent definition

A

incapable of donating a proton

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8
Q
A

In general compounds containing ketones (C=O) and ethers
(C-O-C) are polar ———- Dipole-Dipole interactions

Organic Compounds
Containing-Ketones,
Aldehydes and Ethers

From the electronegativity table C-O bond is polar covalent bond

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9
Q
A

Polar protic solvents tend to have high dielectric constants and high dipole moments.

Furthermore, since they possess O-H or N-H bonds, they can also participate in hydrogen bonding.

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10
Q
A

Polar compounds dissolve in Polar compounds and

Non-Polar compounds dissolve in Non-polar compounds

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11
Q
A
  1. Solute molecules are separated from each other.

Solute–Solute attractions resist this.

  1. Solvent molecules are separated from each other.

Solvent–Solvent attractions resist this.

  1. Solute and solvent molecules mix with each other.

Solute–Solvent attractions assist this.

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12
Q
A

Each one of these has a particular energy called (H) in this case it is
Heat energy (called Enthalpy) a change in heat energy is (triangle symbol)H

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13
Q

Molecular substances will dissolve in each other if:

A
  1. H initial and H final are of similar energy H
  2. Both solute–solute attractions and solvent–solvent attractions are weak so
    that there is little resistance to the tendency to mix
  3. The solute–solvent attractions are sufficiently strong to overcome the
    resistance to mixing due to solute–solute and solvent–solvent attractions
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14
Q

What other factors are helping in the formation of one substance dissolving
in another?

A

Energy systems have a tendency to increase their Entropy (S).

Entropy S is a measure of disorder

The universe is moving towards greater disorder or larger Entropy

Applied to our system the solute and solvent has a natural tendency to mix
or move towards greater disorder

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15
Q
A

The universe is moving towards greater disorder or larger Entropy
Applied to our system the solute and solvent has a natural tendency to mix
or move towards greater disorder

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16
Q
A

The same reason why N2 and O2 do not move towards more order by separating
out in the room. Probability of disorder or the permutations are larger

17
Q

Miscible

A

If substances are soluble in one another

18
Q

Are Ethanol and Water miscible?

A
  1. Ethanol and Water are miscible because, They form hydrogen bonds between each other
19
Q

Are Hexane and Octane miscible?

A
  1. Hexane and Octane are miscible because,
    The have form weak London dispersion forces between each other and begin with only
    weak Hexane-Hexane and Octane-Octane dispersion forces
20
Q
  1. Hexane and Water are immiscible because:
A

The hydrogen bonds in water prevent the mixing

The hexane-hexane interaction has only weak London dispersion force and overall the mixed system (if it
existed) would have far greater energy than the combined Hexane-Hexane and Water-Water systems

21
Q
A

As the non-polar end of any alcohol is increased so does its chances of being soluble in a nonpolar molecule. And less chance of being soluble in water

22
Q

oxidise reaction

A
23
Q

acid-base reaction

A
24
Q

chemical change macrosopic

A

a change in colour
* a change in temperature
* the evolution of heat
* a change of phase (e.g.
precipitation of a solid out of a
solution)
* the emission of light.

25
Q
A

Stoichiometry is concerned with the relative amounts of reactants and
products in a chemical reaction.

26
Q

M = m/n

A

M = molar mass (in grams/mol)
m = is mass in grams
n = is the number of mols (in mols)

27
Q
A

The mole ratio allows us to convert from moles of one substance in a
balanced equation to moles of a second substance in the equation.

28
Q

mole to mass conversion importance

A

1.Determining Reactant Quantities
2.Predicting Product Yields
3.Quality Control in Manufacturing
4.Environmental Applications

29
Q

Moles From Mass

A

n = 10.0 g / 18.02 g/mol = 0.555 mol

30
Q

Converting Moles to Mass

A

m = n x M = 2.5 mol x 32.00 g/mol = 80.0 grams

31
Q

To determine the mass of product that will be produced when you
react 10.0 g of A with 10.0 g of B.

A

The mole ratio between A, B, and the product they form. In other words, we
need to know the balanced reaction equation.
▪ The molar masses of A, B, and the product they form.

32
Q

reaxction where solid forms

A

A reaction in which a solid forms is called a precipitation reaction.

33
Q

Predicting precipitates

A
  1. Write the reactants as they actually exist before any reaction occurs.
    Remember that when a salt dissolves, its ions separate.
  2. Consider the various solids that could form. To do this, simply
    exchange the anions of the added salts.
  3. Use the solubility rules to decide whether a solid forms and, if so, to
    predict the identity of the solid
34
Q

Spectator ions

A

Spectator ions are aqueous ions that don’t participate in reactions:

35
Q
A