Module 05: Linear Momentum Flashcards
Lesson 5.1 Momentum and Its Conservation
What is Linear Momentum?
Linear Momentum of an object is defined as the product of its mass and its velocity (p)
p = mv
- Is a vector
- The direction of momentum is the direction of velocity
- Unit: kg*m/s
- More momentum - the harder it to stop something
Lesson 5.1 Momentum and Its Conservation
How do you calculate the total momentum of two objects before and after collision?
When we desire to calculate the total momentum of two objects before the collision, their total momentum after collision is zero.
m1u1 + m2u2 = 0
When two objects move in the exact direction, the total momentum before the collision is,
- Pbefore collision = m1u1 + m2u2
When two objects move in opposite directions, the total momentum before the collision is,
- Pbefore collision = m1u1 + -(m2u2)
- Pbefore collision = m1u1- m2u2
Lesson 5.1 Momentum and Its Conservation
How does Newton’s Second Law of Motion apply to collision and momentum?
Force needed to change momentum (increasing/decreasing or changing direction)
🔬 Newton’s Second Law of Motion: The Rate of change of momentum of an object is equal to the net force applied to it
F= Δp/Δt
Lesson 5.1 Momentum and Its Conservation
What is the Law of Conservation of Momentum?
Law of Conservation of Momentum:
The total momentum of an isolated system of objects remains constant
- Momentum is a conserved quantity - when there are no net external forces acting on it
- Hence, as long as there is no external force:
mAvA = mBvB = mAvA’ + mBvB‘
- Must keep time interval small - since nonconserved forces act in the real world
- Conserved as long as PA and PB are measured just before the collision and P’A and P’B just after
- Useful when dealing with simple systems (colliding objects and “explosions”)
Lesson 5.1 Questions
1. (I) What is the magnitude of the momentum of a 28-g sparrow flying with a speed of 8.4 m/s?
Lesson 5.1 Questions
3. (I) A 7150-kg railroad car travels alone on a level frictionless track with a constant speed of 15.0 m/s. A 3350-kg load, initially at rest, is dropped onto the car. What will be the car’s new speed?
Lesson 5.1 Questions
5. (II) Calculate the force exerted on a rocket when the propelling gases are being expelled at a rate of 1300 kg/s with a speed of 4.5 × 104 m/s.
Lesson 5.1 Questions
7. (II) A child in a boat throws a 5.30-kg package out horizontally with a speed of 10.0 m/s, Fig. 7– 31. Calculate the velocity of the boat immediately after, assuming it was initially at rest. The mass of the child is 24.0 kg and the mass of the boat is 35.0 kg.
Lesson 5.2 Momentum and Its Conservation
What are the forces involved in a collision?
- During a collision of two objects - both objects are deformed because of large forces involved
- Collision: force each exerts on the other usually jumps from zero at the moment of constant to very large force - then returns to zero again
- The magnitude of the force that one object exerts on the other during a collision, as a function of time
- Time is very distinct and very small
- milliseconds for macroscopic collisions
Lesson 5.2 Momentum and Its Conservation
What is the net force of momentum?
Net force (based on Newton’s Second Law): equal to the rate of change of momentum
F = Δp / Δt
- where p = mv
Lesson 5.2 Momentum and Its Conservation
What is impulse?
Applies to each of the two objects in a collision
Impulse: Total change in momentum
- Used when t = small
- Not constant force
- Approximate force using the average force
- Units for impulse: Newton x second (N*s)
FΔt = Δp
Lesson 5.2 Momentum and Its Conservation
15. (I) A 0.145-kg baseball pitched at 31.0 m/s is hit on a horizontal line drive straight back at the pitcher at 46.0 m/s. If the contact time between bat and ball is 5.00 × 10–3 s, calculate the force (assumed to be constant) between the ball and bat.
Lesson 5.2 Momentum and Its Conservation
17. (II) A 12-kg hammer strikes a nail at a velocity of 7.5 m/s and comes to rest in a time interval of 8.0 ms. (a) What is the impulse given to the nail? (b) What is the average force acting on the nail?
Lesson 5.2 Momentum and Its Conservation
19. (II) A 125-kg astronaut (including space suit) acquires a speed of 2.50 m/s by pushing off with her legs from a 1900-kg space capsule. (a) What is the change in speed of the space capsule? (b) If the push lasts 0.600 s, what is the average force exerted by each on the other? As the reference frame, use the position of the capsule before the push. (c) What is the kinetic energy of each after the push?
Lesson 5.2 Momentum and Its Conservation
21. (II) A 95-kg fullback is running at 3.0 m/s to the east and is stopped in 0.85 s by a head-on tackle by a tackler running due west. Calculate (a) the original momentum of the fullback, (b) the impulse exerted on the fullback, (c) the impulse exerted on the tackler, and (d) the average force exerted on the tackler.
Lesson 5.3 Elastic Collisions
When is total kinetic energy conserved?
If two objects are very hard and no heat or energy is produced in the collision = Total Kinetic Energy before and after collision stays constant
Lesson 5.3 Elastic Collisions
What happens to energy the moment of collision?
The moment during contact = energy is stored momentarily in the form of Elastic Potential Energy.
Lesson 5.3 Elastic Collisions
What is an elastic collision?
Elastic Collision is where the total kinetic energy just before and after the collision stays constant
- At the atomic level, the collisions of atoms and molecules are often elastic
- When kinetic energy is not conserved, the total energy is always conserved
Lesson 5.3 Elastic Collisions
What is an inelastic collision?
Inelastic Collision is when the total kinetic energy is not conserved
- Kinetic energy is lost is changing into other forms of energy
Lesson 5.3 Elastic Collisions
Apply the Conservation Laws for Momentum and Kinetic Energy to elastic collisions:
- For v>0 the object is moving to the right (increasing x)
- For v<0 the object is moving to the left (decreasing value of x)
Lesson 5.3 Elastic Collisions
Apply the Conservation Laws for Momentum and Kinetic Energy to elastic collisions’ velocity:
- Know the masses and velocities before
- Determine velocity after collision:
vA + v’A = vB + v’B
Therefore: The relative speed after the collision has the same magnitude of the relative speed before the collision (regardless of mass)
vA - vB = v’B - v’A
Lesson 5.3 Elastic Collisions
25. (II) A ball of mass 0.440 kg moving east (+x direction) with a speed of 3.80 m/s collides head-on with a 0.220-kg ball at rest. If the collision is perfectly elastic, what will be the speed and direction of each ball after the collision?
Lesson 5.3 Elastic Collisions
27. (II) A 0.060-kg tennis ball, moving with a speed of 5.50 m/s, has a head-on collision with a 0.090- kg ball initially moving in the same direction at a speed of 3.00 m/s. Assuming a perfectly elastic collision, determine the speed and direction of each ball after the collision.
Lesson 5.3 Elastic Collisions
29. (II) A 0.280-kg croquet ball makes an elastic head-on collision with a second ball initially at rest. The second ball moves off with half the original speed of the first ball. (a) What is the mass of the second ball? (b) What fraction of the original kinetic energy (KE/KE) gets transferred to the second ball?
Lesson 5.4 Inelastic Collisions
What is an inelastic collision in relation to energy?
🔬 Inelastic Collisions are collisions in which kinetic energy is not conserved
- Some of the initial kinetic energy is transformed into another type of energy (thermal or potential energy)
- The inverse can also happen - potential energy (such as chemical or nuclear) is released, which causes the total kinetic energy after the interaction to be greater than the initial kinetic energy
- Ex: explosions
- Macroscopic collisions are inelastic to some extent
mv=(m+M)v’
Lesson 5.4 Inelastic Collisions
What is the final velocity formula for inelastic collisions?
Lesson 5.4 Inelastic Collisions
What happens when a collision is completely inelastic?
Completely Inelastic: when two objects stick to each other
- The kinetic energy in some cases is all transformed to other forms of energy (or only part of it)
- The total energy is still conserved
Lesson 5.4 Inelastic Collisions
33. (I) In a ballistic pendulum experiment, projectile 1 result in a maximum height h of the pendulum equal to 2.6 cm. A second projectile (of the same mass) causes the pendulum to swing twice as high, h2 = 5.2 cm. The second projectile was how many times faster than the first?
Lesson 5.4 Inelastic Collisions
35. (II) A 28-g rifle bullet traveling 190 m/s embeds itself in a 3.1-kg pendulum hanging on a 2.8-m long string, which makes the pendulum swing upward in an arc. Determine the vertical and horizontal components of the pendulum’s maximum displacement.
Lesson 5.4 Inelastic Collisions
37. (II) A 980-kg sports car collides into the rear end of a 2300-kg SUV stopped at a red light. The bumpers lock, the brakes are locked, and the two cars skid forward 2.6 m before stopping. The police officer, estimating the coefficient of kinetic friction between tires and road to be 0.80, calculates the speed of the sports car at impact. What was that speed?
Lesson 5.5 Center of Mass (CM)
What is the General Motion of an Extended Object?
- Momentum used to analyze the motion of extended bodies (an object that has size)
- Assumed they approximate a point particle or undergoes translational motion
- Motion that is not a pure translation as general motion
🔬 General Motion of an Extended Object (or system of Objects): The sum of the translational motion of the CM, plus rotational, vibrational, or other types of motion around the CM
Lesson 5.5 Center of Mass (CM)
What is a centre of mass?
Center of Mass (CM): even if an object rotates, there is one point that moves in the same path that a particle would move is subjected to the same net force
- M = total mass of the system
- Center of mass lies on the line joining mA and mB
Lesson 5.5 Center of Mass (CM)
If one mass is greater than the other …
If one mass is greater than the other, then the CM is closer to the larger mass
Lesson 5.5 Center of Mass (CM)
If there are more than two particles along a line …
If there are more than two particles along a line, there will be additional terms
Lesson 5.5 Center of Mass (CM)
If the two masses are equal then xCM is …
If the two masses are equal then xCM is midway between them
Lesson 5.5 Center of Mass (CM)
How does the center of mass depend on the frame of reference?
- CM depends on the reference frame or coordinate system
- Physical location is dependent on the choice
- If the particle is spread over two or three dimensions, must specific the other (y and z) coordinates as well:
Lesson 5.5 Center of Mass (CM)
What is the center of gravity (CG)?
🔬 Center of Gravity (CG) is the point at which the force of gravity can be considered to act
- Force of gravity actually acts on all the different parts of an object
- For translational motion - assume the entire weight of the object acts as the CG
- For all practical purposes the center of mass = center of gravity