Mack (1994) - CL assumptions Flashcards

1
Q

Implicit CL assumptions (3)

Mack

A
  1. linearity - future loss proportional to claims to date&raquo_space; means that development factors are uncorrelated
  2. independence - AYs are independent
  3. variance - variance of next loss is a function of age and losses to date

Mack’s assumptions apply to cumulative losses

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2
Q

Variance of next loss

A

variance of next cumulative loss = claims to date * alpha-subk^2

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3
Q

MSE of ultimate claims

A

MSE = C_ij^2 * RowSum[(a^2 / f^2) * (1/C_ik + 1/ColSum(C_jk))]

where C_ij^2 is the estimate at ultimate
a^2 is the estimated column parameter
f is the LDF (LS, volume weighted, or simple average; based on Var assumption)
the ColSum consists of elements above the diagonal

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4
Q

Alpha-k^2 formula and what it represents

A

a_k^2 = 1/(I - k - 1) * C_ik * ColSum(C_i,k+1/C_i,k - f_k_hat)^2

C_i,k+1/C_i,k is the empirical LDF in row i col k
f_hat is the LDF estimate for the column (based on Var assumption use simple or weighted average, or LS)
I is the size of the triangle I x I

represents variability in age-to-age factors

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5
Q

Estimators for last alpha parameter (3)

A
  1. = 0 - only reasonable if development expected to be finished by end of triangle
  2. extrapolate the alpha series using loglinear regression
  3. IF a’s are decreasing: Previous * Previous / 2nd Previous
    ex. a3 = a2 * a2 / a1
    IF a’s are increasing: use 2nd Previous a
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6
Q

Problems with assuming reserves are normally distributed (2)

A
  1. poor distribution if data is skewed
  2. potential for a negative lower bound even if negative reserves are not possible (lognormal distribution corrects this)
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7
Q

Lognormal confidence interval for reserves (and lognormal parameters)

A

sigma^2 = LN [(1 + se(R)/R)^2]

CI = R * exp(-sigma^2 / 2 +/- Z*sigma)

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8
Q

Alternate variance assumptions and corresponding variance proportionality implications (3)

A
  1. claims to date^2 weighting - age-to-age factor = sum( current claims * claims in next period ) / sum( current claims^2 )
    &raquo_space; variance proportional to 1
  2. normal volume weighted avg
    » variance proportional to claims to date
  3. simple average - age-to-age factor = (1 / (I - k)) * sum (claims in next period / current claims)
    » variance proportional to claims-to-date^2
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9
Q

Test for linearity assumption

Mack

A

plot claims in next period against claims to date and look for a straight line through the origin

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10
Q

Test for variance assumption

Mack

A

plot weighted residuals against claims to date and look for a random scatter

weighted residual = (actual claims in next period - fitted claims in next period) / sqrt(variance proportionality assumption)

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11
Q

Weaknesses of the CL method (2)

Mack

A
  1. age-to-age factors further out in the tail rely on very few observations
  2. known claims in latest AY form an uncertain basis for projecting to ultimate
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12
Q

Test for correlation between development factors

Mack

A

Calculate LDFs for whole triangle
Rank LDFs in each pair of adjacent columns (1 is smallest)
D^2 = squared difference in each pair, sum up D^2s to get S
T_i= 1 - S/(n*(n^2-1)/6) ; n = number of components in comparison
weight the T_i’s and SUMPRODUCT to get T

E(T) = 0
Var(T) = 1 / [(I - 2)(I-3)/2]
where I is the size of the triangle (full loss triangle NOT LDF triangle)

50% CI = +/- 0.67*sigma
Reject H0 if T is outside this interval

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13
Q
Correlation coefficient (T) for a pair of columns and global statistic
(Mack)
A

T-k = 1 - 6 * { sum(squared diff b/w r and s) / [ (I - k)^3 - I + k ] }

T = (I - k - 1) weighted average of T-k’s

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14
Q

E[T] and Var(T) formulas for correlation coefficient b/w development factors
(Mack)

A

E[T] = 0

Var(T) = 1 / [ (I - 2) * (I - 3) / 2]

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15
Q

Examples of CY effects and impacted Mack assumption (4)

Mack

A
  1. major claims handling changes
  2. case reserving changes
  3. substantial court decisions
  4. inflation

*CY effects violate AY independence

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16
Q

Test for CY effects/AY independence

Mack

A

Calculate LDFs for whole triangle
RANK() each column with 1 = smallest
Assign S if < Median, L if > Median, * if = Median
N = # elements in diagonal
S = add up S in each diagonal
L = add up L in each diagonal
Zi = MIN(S,L) each row
m = FLOOR((n-1)/2)
c_n = COMBIN(n-1 | m) * n/2^n
E[Zn] = n/2 - c_n
Var[Zn] = n(n-1)/4 - c_n*(n-1) + E[Zn] - E[Zn]^2

95% CI = E[Z] +/- 2*sigma(Z)

17
Q

S, L, Z, n, and m statistics for CY effects/AY independence test

A
S-j = # smaller than median on diagonal j
L-j = # larger than median on diagonal j
Z-j = min( S-j, L-j )
n = S-j + L-j
m = (n - 1) / 2 (truncated)
18
Q

E[Z] and Var(Z) for CY effects/AY independence test

Mack

A

E[Z-j] = n / 2 - c

Var(Z-j) = n * (n - 1) / 4 - c*(n - 1) + E[Z-j] - E[Z-j]^2

where c = nCr = COMBIN(n-1 | m) * n/2^n

i.e. “n-1 choose m”