Lecture 10 notes Flashcards
1
Q
how is genetic code deciphered?
A
DNA -> transcription -> mRNA -> translation -> polypeptide
2
Q
DNA (and RNA) notation
A
- the sequence of one strand of DNA dictates the sequence of the other strand
- if only one strand is show, 5’ is to the left unless otherwise noted
- if only one strand is shown the DNA is assumed to be double stranded unless otherwise noted
3
Q
translation
A
proteins are synthesized by ‘reading’ mRNA
-tRNAs, guided by mRNA, align amino acids for peptide bond formation in the ribosome
4
Q
DNA is collinear with encoded protein
A
approach:
- isolate many mutants of one gene
- map the mutants to establish position within gene
- isolate mutant proteins, determine amino acid sequence
- linear order of DNA mutations correlates with linear order of amino acid changes
5
Q
how many different amino acids could be specified by a two letter code?
A
16; 4^2
6
Q
codons are triplets
A
- use Phage T4 rll mutants to define the size of a codon
- many ‘frameshift’ mutants were isolated
- combining 3 different mutations with the same sign (+ or -) can yield rll+
7
Q
deciphering the genetic code
A
basic approach:
- synthesize RNA of known sequence
- translate the RNA into protein (in vitro)
- determine the sequence or composition of protein
8
Q
nonsense codons
A
“stop” codons, ends a sequence of amino acids
- UAA
- UAG
- UGA
- amber mutants
- truncated proteins end before an amino acid whose codon differs from UAG at one position
9
Q
combination of +1 and -1 mutants
A
yield wildtype