Lecture 10: Bacteria genome replication and gene expression Flashcards

1
Q

Name two instruments that can be used to grow anaerobic bacteria.

A

The anaerobic jar and the anaerobic chamber

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2
Q

What is the role of the catalyst chamber in the anaerobic jar?

A

It contains palladium pellets that catalyze the reaction of hydrogen and oxygen.
H2 + O2 –> 2 H2O

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3
Q

What is the role of indicator strips in the anaerobic jar?

A

They start blue but lose their colour as the oxygen concentration decreases. They are a visual indicator of O2 concentration.

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4
Q

What is the role of the gas generator envelope in the anaerobic jar?

A

It adds H2, which gets rid of the oxygen, and CO2, which promotes rapid growth of microorganisms.

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5
Q

When is an anaerobic jar not suitable for an experiment? What should be used instead?

A

If the bacteria are so sensitive to oxygen that they can’t survive the duration when the reaction is completed by the palladium pellets. Instead, we can use an anaerobic chamber.

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6
Q

Explain the difference between growing cells on solid vs liquid media.

A

In liquid cultures, the cells are all surrounded by the same environment via the liquid medium. On solid media, different cell positions in a colony will face different environmental conditions.

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7
Q

In a culture growing on a solid medium, cells at the center are […]

A

In the stationary or death phase because there is no food left inthe center

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8
Q

In a culture growing on a solid medium, cells at the edge are […]

A

Actively growing (exponential phase), because they are reaching into areas that still have a lot of nutrients.

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9
Q

In a culture growing on a solid medium, the cells at the surface experience […] conditions

A

Aerobic

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10
Q

In a culture growing on a solid medium, the cells under the surface experience […] conditions

A

More anaerobic

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11
Q

When comparing within bacterial cultures, it is best to use a […] medium because […]

A

Liquid, because the condition are more consistent for different cells.

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12
Q

Name two techniques to quantify the quantity of cells in a liquid culture and the difference in purpose between them.

A

Using a spectrophotometer or the cell count technique. The spectrophotometer will yield a mass estimation, while the cell count technique will yield an exact quantity.

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13
Q

Explain how a spectrophotometer can be used to obtain a microbial mass measurement.

A

Light is shined through the culture and the turbidity is measured. If there are few cells, there will be a lot of light (less turbidity), yielding a higher signal. If there are many cells, there will be less light (more turbidity), yielding a lower signal. Knowing the typical turbidity figures for the culture, you can determine roughly how many cells are in the culture.

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14
Q

Describe the main steps involved in the cell count technique.

A

Take 1 ml of your culture sample and put it into 9 mL of fresh broth (media) to yield a 1:10 dilution. Repeat this 4 more times to yield a 1:100,000 dilution. Take 1 mL of this and either spread it directly on agar or mix it with agar beforehand. The culture with either grow on the agar surface or in it. You can then count the colonies and count backwards with the dilution factor.

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15
Q

After doing the serial dilutions cell count technique, you count 225 colonies. Knowing that you diluted to 1:100,000 before plating, how many cells did you start with in your culture?

A

Since plating 1 mL counts as another tenfold dilution, the final dilution factor is 1:1,000,000. So 225 colonies x 1,000,000 = 225 million cells/ml.

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16
Q

What is the formula for total population number starting with a single cell? What is the problem with this method?

A

2n = cell population after nth generation
The problem is that in reality, we never start with a single cell in a culture.

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17
Q

What is the formula for total population number when starting with more than 1 cell?

A

Nt = N0 x 2^n
Where N0 = total number of cells in the initial inoculum
n = number of generations
Nt = final number of cells

18
Q

What is the formula for number of generations when starting with more than 1 cell?

A

n = 3.3 (log Nt - log N0)

19
Q

What is a gene?

A

A DNA segment that codes for a protein, ribosomal RNAs (rRNA), or transfer RNAs (tRNA)

20
Q

What is a genome?

A

It is the complete DNA sequence present in a cell or a virus

21
Q

What is a genotype?

A

The specific set of genes of an organism

22
Q

What is a phenotype?

A

Observable characteristics of an organism

23
Q

Is a procaryote haploid or diploid? How many sets of genes does it have?

A

Haploid, meaning that it has only one set of genes.

24
Q

Explain Griffith’s Transformation Experiment and what it demonstrated.

A

It took two different phenotypes of streptococcus pneumoniae: smooth (with capsule) and rough (without capsule). When the smooth strain was given to mice, it killed them. When the rough strain was given to mice, they survived. The difference was the virulence factor in the smooth capsule. They did the experiment again after killing the smooth strain with heat. Just the smooth strain did not kill mice now, but the smooth strain mixed with the live rough strain did. This showed a transformation of non-virulent bacteria into pathogens.

25
Q

Explain the Oswald T. Avery et al. experiment and what it showed.

A

They also used rough and smooth strain of streptococcus pneumoniae to attempt to understand how the rough strain was made virulent in the Griffith experiment. They eventually found that when combined R cell with purified S cell DNA, they became S colonies, suggesting that DNA was acquired from the smooth cells, and that DNA carries genetic information.

26
Q

In the Oswald T. Avery experiment, combining R cells + purified S cell polysaccharides would yield […]

A

R colonies

27
Q

In the Oswald T. Avery experiment, combining R cells + purified S cell RNA would yield […]

A

R colonies

28
Q

In the Oswald T. Avery experiment, combining S cell extract + protease + R cells would yield […]

A

S colonies

29
Q

In the Oswald T. Avery experiment, combining R cells + purified S cell DNA would yield […]

A

S colonies

30
Q

In the Oswald T. Avery experiment, combining R cells + purified S cell protein would yield […]

A

R colonies

31
Q

In the Oswald T. Avery experiment, combining S cell extract + RNase + R cells would yield […]

A

S colonies

32
Q

Explain the Hershey-Chase Experiment and what it showed.

A

It was attempting to show whether proteins or DNA carried genetic information in T2 bacteriophages with protein capsids. They did one round with the protein labelled with radioactive 35S and another round with the DNA labelled with radioactive 32P and then put it in a centrifuge with bacterial cells. After centrifuging, they found that the 32P DNA was inside the bacterial cells. Meanwhile, the proteins were not inside the cells, indicating that DNA carries genetic information for T2.

33
Q

Describe the central dogma of bacteria.

A

DNA can get either replicated for cell division or transcribed into RNA. The RNA can then have its own function (rRNA, tRNA) or be used as a template for translation into a protein. The protein will then have its own function and express the genes.

34
Q

The two types of nucleic acid are […]

A

DNA (deoxyribonucleic acid) and RNA (ribonucleic acid)

35
Q

Describe the structure of nucleosides and nucleotides.

A

Nucleosides are made up of a sugar ring (ribose in RNA or deoxyribose in DNA) and a nitrogenous base. They are oinked to one another by phosphate groups. Nucleotides are nucleosides with one or more phosphate groups attached to the sugar.

36
Q

There are […] H bonds between A and T, and […] H bonds between G and C.

A

2, 3

37
Q

Describe the difference the difference between eucaryotes and procaryotes in terms of location of DNA

A

DNA is located inside the nucleus in eucaryote, while there is no nucleus in procaryotes. The DNA is instead anchored to the cell membrane.

38
Q

Describe the difference the difference between eucaryotes and procaryotes in terms of genome size.

A

Eucaryotes: 10^9 base pairs
Procaryotes: 10^6 base pairs

39
Q

Describe the difference the difference between eucaryotes and procaryotes in terms of genome shape.

A

Eucaryotes: numerous linear chromosomes
Procaryotes: one circular chromosome

40
Q

Describe the difference the difference between eucaryotes and procaryotes in terms of DNA organization.

A

Eucaryotes: higly compact and organized into chromatin
Procaryotes: only supercoiled, not as compacted

41
Q

Describe the difference the difference between eucaryotes and procaryotes in terms of DNA-protein association.

A

Eucaryotes: associated with histones
Procaryotes: associated with small, non-histone proteins

42
Q

Describe the difference the difference between eucaryotes and procaryotes in terms of plasmids.

A

Eucaryotes: no plasmids
Procaryotes: contains plasmids that can be transferred between bacterial cells.