Laboratory Enzyme Inhibition Flashcards

1
Q

What is the reaction between catechol and dioxygen catalyzed by catechol oxidase?

A

Catechol oxidase, a copper enzyme, oxidizes catechol to 1,2-benzoquinone and water.

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2
Q

How was UV-Vis spectroscopy used to monitor the reaction?

A

It measured the decrease in catechol (substrate) absorbance over time, indicating its consumption and product formation.

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3
Q

How do plants protect themselves from radicals formed during reaction?

A

Plants have antioxidant defenses like catalase and superoxide dismutase to neutralize harmful radicals.

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4
Q

Does the reaction involve homolytic cleavage?

A

No, only electron transfer from Cu(I) to O2 occurs initially.

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5
Q

What is monitored by UV-Vis in this experiment?

A

The formation of the quinone product (increasing absorbance).

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6
Q

What type of inhibition does p-hydroxybenzoic acid exert?

A

Predicted competitive inhibition due to structural similarity with the substrate.

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7
Q

What are potential sources of error?

A

Temperature, impurities, and enzyme denaturation.

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8
Q

Why is PPO significant?

A

PPO causes browning in fruits, leading to economic losses. It also plays a role in various biological processes in plants.

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9
Q

Discuss the mechanism involved in the experiment.

A

Catechol along with dioxygen in the presence of Cu2+ is oxidized to ortho-quinone.
1. A nucleophile attacks one of the hydroxyl groups of catechol, producing a negative charge on the oxygen atom of that hydroxyl group.
2. By delocalization, the eventual formation of 1,2-benzoquinone will first undergo reactions which include creating an intermediate on the other hydroxyl group.

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