Kinetics 6: Main recall Flashcards
Rate constants often vary with temp, many according to the Arhenius equation.
- Give the eq
- Define the components, giving units
KT = Aexp(-Ea/RT)
- KT = rate constant, units vary
- A = A-factor / pre-exponential factor* same units & dimensions as K, since exp term is dimensionless
- Ea = act energy in kJ mol-1
- R = gas constant, in kJ [temp unit]-1 mol-1 (so that overall, exp term is dimensionless)
- T = temp, K
* A is the collision rate per unit reactant concentration. A is also the rate constant at infinite temp, since 1/T = 0 when lnK = lnA. A is independent of or weakly dependent on temp
Range of typical values for Ea
10-200 kJ mol-1
Value of RT at room temp
~2.4 kJ mol-1
What fraction of molecules have sufficient energy to attain the transition state?
Fraction = exp(-Ea/RT)
Recall RT = 2.4 kJ mol-1 at room temp
Gas kinetic theory
- Expression for mean speed, give unit
- Bimolecular collisions depend on the relative motion of the molecules. Expression for mean relative speed?
ĉ = √(8KBT/πm) in ms-1
KB is Boltzmann constant, m = particle mass in kg
ĉ = √(8KBT/μ) in ms-1
Where reduced mass, μ = (mAmB/mA+mB)
μ in AMU, atomic mass units
Define and give the eq for the steric factor.
Steric factor p is the fraction of sufficiently energetic collisions which lead to reaction
p = Aexperimental/Acoll theory
normally p <1, but p >1 when molecules interact over larger distances than predicted by gas kinetic theory
Gas kinetic theory
- Expression for mean speed, give unit
- Bimolecular collisions depend on the relative motion of the molecules. Expression for mean relative speed?
ĉ = √(8KBT/πm) in ms-1
KB is Boltzmann constant, m = particle mass in kg
ĉ = √(8KBT/μ) in ms-1
Where reduced mass, μ = (mAmB/mA+mB)
μ in AMU, atomic mass units
1st order rate law
r = k1st[A]
d[A]/dt = -k[A]
integrated 1st order rate law in terms of reactant
[A]t = [A]0exp(-k1stt)
Produce and solve the rate law for the second order reaction A –> products.
rate law
d[A]/dt = -k2nd[A]2
∫(from [A]t to [A]0) 1/[A] d[A] = k2nd ∫(from t=t to t=0) dt
1/[A]t = k2ndt + 1/[A]0
Give the expression for the half-life for a first-order reaction.
t1/2 = ln2/k1st
Give the expression for the half-life for a second order reaction.
t1/2 = 1/(k2nd[A]0)
Study the reaction scheme below. What conditions are required for the pre-equilibrium hypothesis to apply?
Rate of process 1 >> rate of process 2, such that rates of [1] and [-1] are equal (in equilibrium), and process [2] is rate-determining.
pre-eq hypothesis is often useful for intermediates involving protonation or deprotonation, since these processes are usually faster than breaking/making bonds to atoms heavier than hydrogen
What conditions permit using the steady state approximation? Include a graph of concentration against time.
Applicable when, in a complex mechanism, a reactive intermediate reacts as soon as it’s formed, such that its concentration is assumed to be constant.
Only applicable when reaction is in steady state - not in the initial or final phases.
simplifies solving differential eqs since it removes the time dependence
Write out the Michaelis-Menten scheme.