Energetics & Equilibria 3: Chemical changes Flashcards
Define the standard state of a substance
The pure form at pressure = 1 bar and at the specified temperature.
Define:
- ΔrHo
- ΔrGo
- ΔrSo
ΔrHo is the standard enthalpy change: the enthalpy change when one mole of reaction occurs at a specified, constant composition, and at standard conditions.
ΔrGo is the standard Gibbs energy change: the Gibbs energy change when one mole of reaction occurs at a specified, constant composition, and at standard conditions.
ΔrSo is the standard entropy change: the entropy change when one mole of reaction occurs at a specified, constant composition, and at standard conditions.
Standard state implies pure substance: i.e. pure reactants form pure products
Important: constant composition means the mixture is big enough that the concentrations of species don’t change throughout the reaction
Define ΔfHo, the standard enthalpy of formation of a compound.
The standard enthalpy change of a reaction where one mole of the compound is formed from its constituent elements, each in their reference states (i.e. most stable state at 1 bar), at a specified temperature.
by definition, the standard enthalpy of elements in their reference states = 0, since no energy is required to put them into a state they’re already in (since stablest)
Draw a cycle which can be used to find the standard enthalpy change for generic reaction vAA + vBB –> vpP + vqQ.
Give the expression for the standard entropy change for the generic reaction vAA + vBB –> vpP + vqQ.
ΔrSo = vpSom(P) + vQSom(Q) - vASom(A) - vBSom(B)
Give the expression for the standard Gibbs energy of a reaction.
ΔrGo = ΔrHo - TΔrSo
ΔrHo varies with temperature. Give the relationship giving ΔrHo at temperature 2, given knowledge of ΔrHo at temperature 1.
ΔrHo(T2) = ΔrHo(T1) + ΔrCpo[T2 - T1]
ΔrHo varies with temperature. Derive a relationship giving ΔrHo at temperature 2, given knowledge of ΔrHo at temperature 1.
State any assumptions made.
Define standard molar heat capacity at constant pressure:
Consider generic reaction vAA + vBB –> vpP + vQQ
ΔrCpo = νPCop,m(P) + νQCop,m(Q) - νACop,m(A) - νBCop,m(B)
Definition of heat capacity at constant pressure:
Cp,m = (∂Hm/∂T)p (constant pressure)
Cp,m = dHm/dT (constant pressure)
(Everything is under standard conditions so can drop molar subscript)
So ΔrCpo = dΔrHo/dT
Assume heat capacity is constant in range T1 to T2, so:
Return to Cp,m = dHm/dT (constant pressure)
So dHm = Cp,mdT (constant pressure)
Then integrate (image)
Apply integrated relationship to definition of molar heat capacity at standard pressure:
ΔrHo(T2) = ΔrHo(T1) + ΔrCpo[T2 - T1]
ΔrSo varies with temperature. State the relationship giving ΔrSo at temperature 2, given knowledge of ΔrSo at temperature 1.
ΔrSo(T2) = ΔrSo(T1) + ΔrCpoln(T2/T1)
ΔrSo varies with temperature. Derive a relationship giving ΔrSo at temperature 2, given knowledge of ΔrSo at temperature 1.
State any assumptions made.
Define standard molar heat capacity at constant pressure:
Consider generic reaction vAA + vBB –> vpP + vQQ
ΔrCpo = νPCop,m(P) + νQCop,m(Q) - νACop,m(A) - νBCop,m(B)
Then derive relationship
Recall dSM = Cp,mdT/T (constant pressure)
Integrate between T1 and T2 (image)
assumption: temperatures are not very different, so Cp is constant and can be taken out of the integral
(Everything is under standard conditions so can drop molar subscript)
ΔrSo(T2) = ΔrSo(T1) + ΔrCpoln(T2/T1)
Convert 1 bar to Pa
1 bar = 105 Pa