Digital Radiography Flashcards

1
Q

What are the advantages of DR over SFR?

A

Improving image quality
Reducing patient radiation dose
Storage and management of images in digital form
Increasing patient throughput

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2
Q

Why is digitisation of SFRs not appropriate?

A

This approach has been found to considerably increase the workload of radiographic staff. Also, the resulting image is degraded below the (already limited) quality recorded on the original film. Film digitisation has, therefore, not been widely adopted as a gateway to DR and PACS.

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3
Q

What are the 3 generic stages of A DR detector?

A

X-rays are initially absorbed from the incident x-ray beam by the detector layer
The absorbed x-ray energy is then converted into a latent image (typically in the form of a pattern of electrical charge)
Finally, the latent image is read out as an (analogue) electronic signal prior to digitisation by the ADC

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4
Q

To be clinically effective, a DR image detector must have the following typical performance requirements (6):

A

Field coverage must be large enough to provide full anatomical coverage in all relevant radiographic examinations

The radiation sensitivity is high enough to ensure low dose operation

Each picture element (pixel) forming the image detector, must be sufficiently small to ensure adequate spatial resolution

The dynamic range must be large enough to cover the full range of radiation intensity both within a single exposure and across different examinations and patient sizes

Noise sources must be kept to a minimum to ensure optimum image quality

The image readout and display time must be sufficiently short to ensure rapid availability of images and efficient throughput of patients

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5
Q

Which of the following are characteristics of a DR system?

A. It is not compatible with an automatic exposure control
B. The latent image can take the form of a pattern of electrical charge
C. The DAC precedes the ADC
D. High x-ray sensitivity is needed to minimise patient radiation dose

A

A. Incorrect. Digital radiography systems can be operated under either manual or automatic control of the radiographic exposure factors.

B. Correct. The absorbed x-ray energy is converted into a latent image that is typically in the form of a pattern of electrical charge stored in the detector elements prior to being read out.

C. Incorrect. The latent image is read out as an analogue electronic signal that must be digitised by the ADC. The digital image may later be changed back to an analogue signal by a DAC, for example in order to be displayed on a PACS monitor.

D. Correct. The sensitivity of the detector is an important factor in determining the radiation dose required to produce a given image quality.

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6
Q

How is the pixel spacing derived from the analogue input?

A

In general, the formation of a pixelated image requires discrete sampling of an analogue signal such as a field of light photons or a pattern of stored electronic charge carriers. The pixel spacing or sampling interval 𝛥 is the distance between the centres of two adjacent pixels, measured at the entrance plane of the image detector.

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7
Q

What causes aliasing in DR?

A

the greater the fN the greater the spatial resolution of the acquired image. Sampling theory requires that the input signal which is sampled must not contain high spatial frequencies (equivalent to fine detail structures) which exceed fN - otherwise the digitised image will be subject to so-called aliasing artefact.

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8
Q

What is the fill factor of a system?

A

In solid-state designs of DR detector, an array of microcircuitry is integrated with the x-ray absorption layer. This makes it possible to directly read the image out of the detector in electronic form.

The readout microcircuitry comprises a high resolution array of active electronic components. Microcircuit design constraints inevitably mean that a fraction of the pixel area is occluded by the superstructure of the active component (plus associated switching and data lines). In principle this effect can reduce the sensitivity of the x-ray detector.

The degree to which the active portion of the pixel is occluded is described by the fill factor (FF) of the detector

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9
Q

How does bit depth change grayscale?

A

The greyscale value is expressed as a binary (or base-2) number. This can be compared with our normal counting system which uses the base-10 or decimal number system.

The greyscale resolution of a digital image is defined by the number of bits (binary units) of information per pixel where 1 bit of information per pixel corresponds to two possible greyscale values (0,1). Obviously 1 bit is suitable for depicting text, line drawings and graphs but is inadequate for representing a greyscale image.

10 bits - Corresponds to a choice of 2^10 or 1024 greyscale values {viz., 0 to 1023} - this is the minimum number of bits needed to represent a digital radiography image.
state of the art systems use 14bit
N bits Corresponds to 2^N possible greyscale values {viz., 0,1,2… to 2^N-1}.

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10
Q

How do you calculate the amount of data in an image?

A

N x M x G

N x M is the total number of pixels making up the image.
G is the associated greyscale information per pixel expressed in bytes.

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11
Q

Why is image compression used?

A

Over time, a radiology department utilising DR will generate prodigious amounts of image data.

The archive capacity requirements will, however, be eased if digital data compression is used.

Image compression, by up to a factor ~3:1 or so, is possible with no loss of image quality if a so-called reversible data compression algorithm is used.

More powerful so-called irreversible compression algorithms can be used to achieve compression factors of 10:1 or even greater.

It should be noted that as the degree of (irreversible) compression is increased the quality of the images will deteriorate, making them susceptible to artefacts and reduced spatial resolution.

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12
Q

What is x-ray luminescence?

A

The physical mechanism which describes the conversion of x-ray energy into light in a phosphor screen

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13
Q

What are the 2 subtypes of xray luminescence?

A

X-ray fluorescence
This describes the prompt (immediate) emission of light - this is the mechanism which underpins screen film radiography (SFR).

X-ray phosphorescence
This describes interactions where the emission of light is delayed over a timescale of many minutes, hours and days.

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14
Q

WHat radiographic technique uses phosphoresence?

A

X-ray phosphorescence is the physical mechanism exploited in the digital x-ray imaging technique known as computed radiography (CR).

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15
Q

WHat are the components of a CR imaging plate?

A

A CR IP comprises a thin layer of storage phosphor crystals embedded in a polymer binder.

The x-ray sensitive phosphor layer is coated upon a plastic substrate for mechanical support.

The top surface of the IP is protected from abrasion by a layer of toughened plastic.stals embedded in a polymer binder.

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16
Q

WHat is a common storage phosphor in CR?

A

The one commonly used in CR IPs comprises barium fluorohalide crystals activated with divalent europium ions i.e. BaFX:Eu2+.

X stands for a specific mix of halogen atoms selected from bromine, iodine and possibly chlorine atoms.

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17
Q

What is the difference between Standard CR IPs and High resolution IPs?

A

A standard IP comprises a thicker layer of phosphor crystals of larger size and includes a light reflection layer to increase sensitivity.
A standard IP typically absorbs 40% of the x-ray photons incident upon it.

A high-resolution IP comprises a thinner layer of finer phosphor crystals and usually does not include a light reflection layer.
High-resolution IPs are reserved for examinations demanding high spatial resolution.
High-resolution IPs have lower fractional x-ray absorption efficiency and therefore demand a higher x-ray dose than ST IPs.

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18
Q

Where is the IP housed during the film exposure?

A

During the exposure of the patient the IP is housed in a light-tight plastic or metal container known as a cassette.

Image plate cassettes have a similar construction to those used in conventional radiography, having a radiolucent front face (often constructed from carbon fibre) plus a lead backing layer.

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19
Q

How is a latent image formed in CR?

A

The absorption of an x-ray photon in a phosphor crystal gives rise to a high energy photoelectron which subsequently ionises a large number of atoms along its track releasing thousands of electrons.

In CR, the latent image comprises a pattern of electrons which have become temporarily trapped at specific sites throughout the layer of phosphor crystals. These electron traps correspond to dislocations in the crystal structure which are created during the IP manufacturing process.

The pattern of trapped electrons mirrors the intensity distribution of the x-ray beam originally incident upon the IP. On average, each x-ray photon absorbed in the IP gives rise to over a hundred trapped electrons.

Under normal conditions, electrons remain trapped for some time until they spontaneously relax back to their ground state releasing their stored energy as light photons

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20
Q

How is the image readout in CR?

A

the IP is scanned with a laser beam operating in the red part of the optical spectrum. The laser beam scans the IP with a raster pattern (corresponding to a set of parallel stripes) enabling the whole CR image to be read out in a systematic way.

Laser stimulation of trapped electrons causes them to immediately relax back to their ground state releasing their stored energy as light photons but in a structured way so an image can be constructed.

The stimulated emission occurs in the blue part of the optical spectrum. Laser stimulated emission is a so-called ‘destructive readout mechanism’ as it eliminates the latent image in the process.

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21
Q

What energy bands are there within a phosphor?

A

The phosphor used in an IP is an electrical insulator and therefore has an energy band diagram comprising:

A set of filled valence states (corresponding to states where electrons are tightly bound to atoms) plus
An empty conduction band (corresponding to states where electrons would be free to move through the material)
The valence and conduction bands are separated by a large energy gap representing states which electrons are forbidden (by laws of physics) from occupying.

In a CR IP however, situated within the energy gap close to the bottom of the conduction band are special electron states which are empty and correspond to the electron traps

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22
Q

WHat is the typical diameter of the laser in CR readout?

A

typically 0.1 mm

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23
Q

WHat happens to the IP after laser scanning?

A

the IP is transported past a bank of high intensity lamps which erases any residual CR signal

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24
Q

WHat happens to the stimulated emission signal in CR?

A

The signal photons have to be collected with high efficiency using a carefully designed light-guide.

Signal photons are conveyed via the light-guide to a high sensitivity light sensor known as a photomultiplier (PM) tube. A blue filter is mounted over the PM tube to exclude extraneous light.

As the laser scans the IP the PM tube produces a time series electrical current. This electrical current is signal processed before transfer to the analogue-to-digital converter (ADC). The ADC converts the electrical current signal to a stream of digital data which is transferred to the system computer.

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25
Q

A CR system exploits which of the following physical processes?

A

Laser stimulated phosphorescence

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26
Q

What does the detector dose indicator provide?

A

provides the operator with an indication of the mean dose incident on the image plate (IP). Unfortunately, there is not yet a standard definition of DDI. The relationship between DDI and IP dose varies depending on the manufacturer – for example, DDI may be inversely related to dose, or a function of the log of the dose.

In practice, interpretation of the DDI is often complicated by the fact that its value also depends on certain factors. Nevertheless, the DDI represents an invaluable quality control tool.

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27
Q

How does the curve for CR differ from SFR?

A

The intensity response of CR is totally linear, with no low or high dose saturation effects.

The corresponding dose latitude, often referred to as the dynamic range, of CR extends over a very wide range of detector entrance dose levels, ~ 104:1.

The CR response can be compared with the familiar (non-linear) S-shaped characteristic curve of radiographic film

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28
Q

What are the advantages of the wide dynamic range of CR?

A

It records anatomical information over a wider range of tissue densities for a single exposure of the patient, ideally this should provide the clinician with access to more detailed diagnostic information
More consistent acquisition of images with a lower occurrence of incorrectly (over or under) exposed images
It results in lower rates of repeat exposures with an associated reduction of dose to patients and possibly staff

29
Q

How does the spatial resolution of CR compare to SFR?

A

In general, the spatial resolution of a standard CR system is significantly lower (typically ~ half) than that of a competing screen film combination.

30
Q

What factors effect spatial resolution of CR systems?

A

Diameter of the laser beam (e.g. 100 μm vs 50 μm)
IP size and the sampling interval (pixel spacing)
Mean size of the phosphor crystals
Thickness of the phosphor layer
Presence of a light reflection or absorption backing layer
Scatter and re-absorption of x-ray photons
Spread of light as the laser beam penetrates the IP during readout - this is the dominant source of blur or unsharpness in CR imaging
Digital image enhancement also affects perceived sharpness of CR images

31
Q

What is MTF?

A

The spatial resolution of a digital x-ray imaging system is best described by the modulation transfer function (MTF). The MTF is a graph which depicts the signal transfer properties of an imaging system as function of spatial frequency.

The MTF is a dimensionless quantity which represents the ratio of the output to the input modulation (a concept allied to contrast).

32
Q

What is limiting spatial resolution?

A

The high spatial frequency cut-off point of the MTF is usually referred to as the limiting spatial resolution.

33
Q

What is the limiting spatial resolution of CR?

A

Limiting spatial resolution of a CR system typically lies in the range of 2.5 to 5 lp/mm.

By way of comparison the limiting spatial resolution of a fast medium screen film combination typically lies between 5 to 8 lp/mm.

Even higher spatial resolution, up to 8 to 12 lp/mm, is achieved with fine detail screen film combinations.

Specialised high resolution CR units can achieve a spatial resolution of 10 lp/mm.

34
Q

What does noise arise from in CR?

A

Noise in CR images results from random fluctuations at various stages in the x-ray image capture and readout stages.

The primary source of noise in CR arises from the random fluctuation in the count of x-ray quanta absorbed in the IP to form the primary image. This component of noise is usually referred to as quantum mottle.

Another important source of noise in CR imaging is known as secondary quantum noise. This arises from the random fluctuation in the yield of primary photo electrons produced by the photomultiplier tube per absorbed x-ray photon at readout. The random fluctuation is significant because the yield of photoelectrons is low.

35
Q

How can you increase SNR in CR?

A

Increasing the IP x-ray absorption efficiency η (but at a cost of increased blur) and/or
Increasing the incident photon fluence N (but at a cost of increased patient dose)

36
Q

What is the moire pattern artefact?

A

This occurs when a stationary x-ray anti-scatter grid, particularly one of low line-density, is used. This artefact results from interference between the linear structure of the grid and the regular pixel array of the digitised image.

Use of a grid with a line density exceeding 60 lines per cm is recommended in CR to prevent this type of artefact from occurring.

37
Q

WHat is DQE?

A

Detective quantum efficiency (DQE) provides a more complete measure of x-ray image quality. In simple terms DQE provides an objective measure of the efficiency with which information in the incident x-ray beam is recorded by the image detector.

Is equal to SNRout^2/ SNRin^2

38
Q

WHat does measuring DQE allow you to do?

A

to compare the imaging performance of different types and designs of x-ray image detector on an absolute basis. It is important to note that DQE does not include analysis of the image display device nor of the visual system of the observer.

39
Q

WHat is the DQE of CR?

A

0.25 for the single-sided readout design
~0.4 for double-sided

compared to Modern solid-state DR detectors can achieve DQE values exceeding 0.6. These detectors offer a DQE two to three times greater than that of standard CR.

40
Q

Why does a dual sided film in CR improve DQE?

A

This makes it possible to collect the laser stimulated emission from both the top and the bottom surfaces of the IP simultaneously. This requires a modified design of CR readout assembly which comprises two opposing light-guides and associated photomultiplier tubes. The signals from the two PM tubes are then combined, increasing the sensitivity of the readout process. This advance has significantly improved the DQE of CR imaging.

41
Q

Physical properties of CR include:
An extremely wide dynamic range (exceeding 1000:1)
B. An extremely wide dynamic range (exceeding
100 000:1)
C. A typical spatial resolution of 15 lp/mm
D. A typical spatial resolution of 50 lp/cm

A

A. Correct. CR typically has a dynamic range of about 10 000:1.

B. Incorrect. CR has a wide dynamic range, but not this wide!

C. Incorrect. The limiting spatial resolution of a CR system typically lies in the range 2.5 to 5 lp/mm, increasing to 10 lp/mm for a specialised high resolution unit.

D. Correct. 50 lp/cm = 5 lp/mm which is typical of a CR system.

42
Q

What can you remember about CR imaging?

A. CR DDI measures the incident dose required to produce a film density of unity
B. The spatial resolution of a high resolution IP is two to three times greater than a standard IP
C. The dual-sided CR readout mechanism was developed to improve the spatial resolution
D. Spread of laser light is the dominant source of unsharpness in CR imaging

A

A. False. The DDI gives an indication of the dose received by the IP.

B. False. High resolution IPs can be used to improve spatial resolution by ~20-30% compared with standard IPs, but typically at a cost of a two to three fold increase in dose.

C. False. The dual-sided CR readout mechanism was developed to improve the DQE performance.

D. True.

43
Q

CR image quality will be degraded if:
A. The dose to the IP is increased

B. If there is an incomplete erasure of the IP
C. There is build-up of dust and dirt in the scanner optics
D. Moiré artefacts occur due to the use of a moving anti-scatter grid

A

A. Incorrect. If the dose to the IP is increased, the image quality (SNR) will be increased (but at the cost of increased patient dose).

B. Correct. Incomplete erasure of the IP can cause a ghost image artefact.

C. Correct. Build-up of dust and dirt in the scanner optics can lead to excessive shading (variation in signal across the image).

D. Incorrect. Moiré artefacts can arise from the use of a static
anti-scatter grid but not from a moving grid.

44
Q

What are flat panel DR detectors normally made from?

A

The active matrix array is manufactured in a thin layer of the ‘amorphous’ (or structurally disordered) form of silicon doped with hydrogen or hydrogenated amorphous silicon (a-Si:H).

45
Q

What are indirect conversion DR detectors made from?

A

Indirect conversion DR detectors utilise a comparatively thin layer of x-ray fluorescent material, thallium activated caesium iodide (CsI:Tl), to capture the initial x-ray image.

At the same time the channelled crystal structure of this scintillator, which is similar in form to a fibre-optic bundle, ensures minimum unsharpness (blur) of the recorded image due to light scatter.

The CsI:Tl layer is coated on the a-Si:H active matrix array. The scintillator layer and readout electronics are supported by a glass substrate approximately 1 mm in thickness.

46
Q

What are the components of a pixel in a FP indirect detector?

A

Photodiode (a light sensor)
Charge storage capacitor
Thin-film transistor (TFT) switch

47
Q

How does image readout occur in indirect conversion DR?

A

Absorption of an x-ray photon in the scintillator releases ~3000 light photons in the green part of the spectrum. These light photons are then absorbed in the photodiodes releasing charge carriers. In turn, the charge carriers released at each (pixel) location, accumulate in the associated storage capacitor, forming the latent image. The conversion gain of this process yields a healthy 1500 or so charge carriers per absorbed x-ray photon.

The latent image is read out sequentially by gating each row of TFT switches in turn. As a result, the charge pattern is read out one line at a time and transferred to a bank of charge-sensitive amplifiers (CSAs). The resulting voltage signal is then digitised and transferred to the system computer where the DR image is built-up.

48
Q

What do direct DR detectors use instead of an x-ray scintillator?

A

Direct conversion DR detectors use a layer of x-ray photoconductor material which directly converts x-ray photon energy into free electrical charge carriers (electrons and holes). To date, the mostly commonly used photoconductor material in direct conversion DR detectors is amorphous selenium (a-Se)

Alternative x-ray photoconductive compounds which may be used in DR detectors in the future include:

Lead(II) oxide (PbO)
Cadmium zinc telluride (CdZnTe)
Mercury(II) iodide (HgI2)
Lead(II) iodide (PbI2)

49
Q

How do direct DR detectors capture the xray?

A

A direct conversion DR detector typically utilises a 500 μm thick layer of a-Se (Z = 34) as the primary x-ray image detector.

The a-Se layer is coated upon an active matrix array again manufactured in a layer of a-Si:H.

Absorption of x-ray photons in the a-Se releases charge carrier pairs i.e. (-) electrons and (+) holes.

A metal electrode is coated on the external surface of the a-Se.

The electrode is attached to a positive bias potential of 5000 volts.

The a-Si:H layer is close to earth potential.

The bias voltage establishes an intense electrical field which accelerates the:

Charge carriers across the layer to the appropriate electrode
Electrons towards the bias voltage and holes toward the a-Si:H electronics

50
Q

How does image readout work in direct DR detectors?

A

very similar to indirect.

Each pixel in the DR active matrix comprises a charge storage capacitor plus a TFT switch.

Holes released during the x-ray exposure accumulate in the array of storage capacitors forming the latent image.

The conversion process yields a healthy 1000 or so holes per absorbed x-ray photon.

The latent image is then read out sequentially by gating each row of TFT switches in turn in a manner similar to that used in the indirect DR detector (Fig 1).

As a result the charge pattern is read out one line at a time and transferred to a bank of CSAs.

The resulting voltage signal is then digitised and transferred to the system computer where the DR image is built-up.

51
Q

How does the DQE between direct and indirect detectors compare?

A

The fractional x-ray absorption and DQE of the CsI based (indirect conversion) detector is superior to that of the a-Se based (direct conversion) detector.

This is due to the higher mean Z of CsI and the greater absorption of x-ray photons of energies above the k-edges of Cs and I (at 36 and 33 keV respectively). By comparison the k-edge of a-Se, at 13 keV, lies below the energy range used in general radiography (but not necessarily mammography).

This means that indirect conversion DR detectors offer either:

Lower patient dose for the same image quality or,
Lower image noise (better image quality) for the same patient dose compared with direct conversion detectors

52
Q

How does the spatial resolution (MTF) compare between direct and indirect detectors?

A

The spatial resolution of direct conversion DR detectors, on the other hand, is superior to that of indirect conversion detectors.

This is due to the direct transfer of charge carriers across the a-Se layer by the intense electric field. This ensures charge packets exhibit negligible lateral diffusion which would produce blur (unsharpness) in the final image.

Despite its channelled structure, some residual light scatter does occur in the CsI:Tl layer which produces a greater degree of blur (unsharpness) than in a photoconductor.

53
Q

What are the benefits of DR (both direct and indirect) over CR?

A

DR detectors also offer direct readout of the latent image in electronic form with no need to handle cassettes nor for mechanical or optical scanning equipment. This reportedly increases the rate of image production leading to increased patient throughput and improved departmental productivity.

Both direct and indirect DR detectors have higher DQE than standard (single-sided) CR and therefore offers savings in patient dose (a standard CR system has a DQE of ~0.25).

Digital radiography detectors have similar spatial resolution to standard CR (which use a 100 micron diameter scanning laser beam) but inferior spatial resolution to HR CR systems (which use a 50 micron laser beam).

54
Q

Regarding indirect conversion DR detectors:
A. CsI:Na is the favoured x-ray phosphor material, due to its channelled crystal structure
B. The term ‘indirect’ implies the intermediate production of light photons
C. The readout matrix is fabricated in a layer of hydrogenated amorphous selenium
D. The latent image takes the form of a pattern of electrons in crystal traps

A

A. False. The favoured phosphor is CsI:Tl (thallium activated caesium iodide).

B. True.

C. False. The readout matrix is fabricated in a layer of hydrogenated amorphous silicon. Amorphous selenium is a photoconductive material used in direct conversion detectors.

D. False. The latent image is formed by a pattern of charge on storage capacitors. Crystal traps are relevant to storage phosphors used in CR image plates.

55
Q

Regarding a direct conversion DR detector:
A. It has a shorter image acquisition time than an indirect conversion detector
B. The principal signal charge carriers are positively charged holes
C. It has a better MTF (and therefore bone detail resolution) than an indirect conversion detector
D. One such detector can be shared among several radiographic rooms

A

A. False. A direct conversion detector generally has a longer image acquisition time than an indirect conversion detector. This is because, following image readout, trapped electrons need to be released from the surface of the a-Se.

B. True. The charge collection electrodes are generally held at a negative bias voltage, attracting positively charged holes.

C. True. Spread of light in an indirect conversion detector results in a poorer MTF than that of a direct conversion detector.

D. False. In general, a separate direct conversion detector is required for each acquisition station. This can be contrasted with CR in which a single reader can support several radiographic rooms.

56
Q

Comparing DR and standard (single-sided) CR:
A. The DQE of a DR system can be over twice that of a standard CR system
B. Digital radiography offers improved patient throughput compared with CR
C. Digital radiography detectors offer dose savings compared with standard CR
D. Digital radiography has similar spatial resolution to a HR CR system which uses a 50 micron laser

A

A. True. The DQE of an indirect conversion DR detector is typically about 0.65 whereas a standard CR system has a DQE around 0.25.

B. True. Digital radiography detectors offer direct readout of the latent image in electronic form with no need to handle cassettes. This offers the potential to increase patient throughput.

C. True. The higher DQE of a DR system offers the potential for patient dose savings.

D. False. Digital radiography has similar spatial resolution to standard CR but inferior spatial resolution to HR CR.

57
Q

What different types of post processing are available in DR/CR?

A

Computer post-processing regimes used in DR and CR typically include:

Calibration and correction
Data auto-ranging
Digital image enhancement

Beyond this, more sophisticated implementations of image post-processing are emerging. Notable among these are computer-aided diagnosis (CAD) routines to automatically detect specific diagnostic features. Applications of CAD include detection of lesions in the breast or chest for example, for the purposes of screening for cancer.

58
Q

What are 2 typical DR detector artefacts which need correction

A

Irregular shading across the image field due to non-uniform variations in the sensitivity or gain of the x-ray absorption layer

Bright or dark spots and lines in the image due to individual or rows and/or columns of defective pixels in the active matrix array

59
Q

How can irregular shading and bright/dark spots be removed in post-processing?

A

Gain variations can be calibrated out using a previously acquired mask image comprising an image acquired with a uniform x-ray beam. The gain calibration is achieved by logarithmic subtraction of the gain mask image from the patient image.

Defects in the pixel array can be corrected by interpolating the data values of neighbouring pixels which are functioning correctly. This technique uses a reference map of defective pixels which has been analysed previously.

Gain calibration and defective pixel correction take place automatically in the background and require no operator intervention. The reference (gain) mask and map of defective pixels must be updated periodically to compensate for any deterioration in detector response which occurs over time.

60
Q

What is data auto-ranging?

A

The range of data generated by a DR or CR detector must be matched to the display device(s). If it is not implemented correctly, a loss of image quality will occur as exposure data is initially acquired over a very wide dynamic range (up to 104:1) while display devices may only be able to accommodate 8 or 10 bits of data.

Data auto-ranging is the technique used to optimise the match between the acquired image data and the output display device(s). Auto-ranging software is used to automatically identify and normalise the clinically most important section of the acquired data range

61
Q

Why may the image grayscale need to be modified?

A

Practical reasons for modifying the image greyscale might include the need to:

Increase image contrast to improve the visibility of a subtle lesion
Vary the mean brightness of the image
Improve presentation of the overall greyscale range
Compensate for the different intensity responses of various display devices

62
Q

How is the image grayscale modified?

A

These goals can be achieved using the LUT technique (Fig 1). An LUT is a method of systematically re-mapping the greyscale values in the recorded image to a new range of values in order to improve the displayed image in some way as illustrated in the diagram.

An LUT with a unity slope and which passes through the origin will reproduce the image unchanged.

Shifting the linear LUT along the input greyscale range axis makes it possible to adjust the mean brightness of the image.

Increasing the gradient or slope of a linear LUT will increase the displayed contrast of the image, albeit at a cost of causing saturation of input greyscale values which fall outside the displayed range. This saturation effect can be eased by using a non-linear LUT, typically an S-shaped LUT with the display characteristics of a radiographic film.

63
Q

Why may the spatial fatures of a film need to be enhanced?

A

Increase the spatial resolution of small isolated structures in the image e.g. calcification deposits or fractures in bone
Improve the sharpness of edges of large area structures e.g. the edge contours of bones
Improve the presentation of fine texture patterns e.g. lung tissue or trabecular patterns in bone

64
Q

How are the spatial features of an image enhanced?

A

Perhaps surprisingly, the first step is to produce a blurred version of the original image. This is achieved by convolving (or scanning through) the image array applying a smoothing kernel which averages local pixel values over the area of the kernel. This operation blurs out features which are smaller in size than the smoothing kernel.

The blurred image is subtracted from the original image producing an image which retains the fine detail structures in the image alone. Addition of the fine detail image back onto the original produces the enhanced composite image. The degree of enhancement can be adjusted via the control parameter relative enhancement (RE).

65
Q

How are DR images now displayed?

A

Cathode ray tube monitors are largely being replaced by active matrix flat panel (AMFP) displays.

66
Q

How do AMFP displays work?

A

based upon liquid crystal (LC) technology and exploit the change in the polarisation of light which can be induced by a LC.

A polarising material is one which only permits the transmission of incident light when polarised in a particular direction.

However, for light polarised at other angles, light intensity is attenuated and at 90° the light is blocked completely.

A LC is a peculiar state of matter (combining properties of a liquid and a solid at the same time) whose polarisation properties can be rotated in response to the magnitude of an applied electrical voltage. The LC display contains a planar light source covered by a sheet of polarising material which defines the initial state of polarisation of the light.

A second sheet of polarising material is also used, but this sheet has its direction of polarisation rotated through 90° compared with the first sheet. Sandwiched between the two sheets of polarising material is the planar LC superimposed on a matrix of electronic elements, manufactured in ‘amorphous’ form of silicon doped with hydrogen (a-Si:H).

Application of the appropriate voltage distribution to the active matrix modulates light polarisation on a pixel-by-pixel basis varying the light emission. As a result the AMFP display generates a 2D array of illuminated pixels which the radiologist views as the image.

Active matrix flat panel displays are more electrically stable than CRTs and not subject to geometrical distortion, non-uniform shading or contrast loss.

67
Q

Regarding digital image enhancement:
A. It materially improves image signal-to-noise ratio
B. It can be used to increase the contrast of relevant image details
C. Unsharp masking has no effect on image noise
D. A single LUT can be used to match the response of several display devices

A

A. False. An image enhancement algorithm acts on both the signal and the noise so it cannot materially change the image signal-to-noise ratio. However it can affect how the observer perceives the image.

B. True. Selecting an appropriate range of grey levels will enhance contrast.

C. False. Unsharp masking enhances fine details (features with high spatial frequencies), including image noise.

D. False. An LUT can only match a single response.

68
Q

Which of the following digital processing algorithms would you use to improve the spatial resolution of a DR image?
A. Data auto-ranging
B. Local pixel averaging
C. Unsharp masking
D. Look-up table transformation

A

A. Incorrect. Data auto-ranging optimises the match between the acquired image data and the output display device. This improves the contrast of relevant details but does not affect spatial resolution.

B. Incorrect. Local pixel averaging has the effect of blurring the image and thus decreases spatial resolution.

C. Correct. Unsharp masking is an algorithm to enhance fine details and thus improve spatial resolution.

D. Incorrect. A LUT transformation re-maps the greyscale values in the recorded image to a new range of values in order to improve the displayed image. It does not affect spatial resolution.

69
Q

What effect would an LUT with a slope equal to -1 have on a DR image?
A. Increase the displayed contrast
B. Extend the dynamic range
C. Suppress the anatomical background structures in the image
D. Invert the polarity of the image

A

The correct answer is D.