CI abcde: Kinetics: rates & orders of reactions; Arrhenius equation Flashcards
Why does increasing the concentration of a reactant not necessarily mean that the rate of reaction will increase?
The reactant may not be involved in the rate-determining step.
What influences how fast a rate-determining step is?
Its activation enthalpy.
2H2O2 → 2H2O + O2
0.01 moles of oxygen are formed per second. What is the rate in terms of hydrogen peroxide?
- 0.02 mol s-1
Rate = k[H2O2][catalase] at temperature T.
What is the unit of the rate constant?
k = rate / product of concentrations
mol dm-3 s-1
(mol dm-3)(mol dm-3)
So unit of k = dm3 mol-1 s-1
Write positive indices first by convention
Experimental evidence showed the rate of a reaction is given by the following equation:
rate = k[S2O82-][I-]
What is the order of the reaction:
- With respect to each of the reactants?
- Overall?
- First order with respect to S2O82-
- First order with respect to I-
- Second order overall (add the powers)
What is the unit of the rate constant for zero order reactions?
mol dm-3 s-1
What is the unit of the rate constant for first order reactions?
s-1
What is the unit of the rate constant for second order reactions?
dm3 mol-1 s-1
This is the Arhenius equation:
k = Ae-Ea/RT
What is represented by each symbol?
k, rate constant
A, frequency factor
e, the constant
Ea, activation enthalpy
R, gas constant
T, temperature in Kelvin
k = Ae-Ea/RT
Prove that the Arrhenius equation can be used to plot a straight line graph. State its gradient and y-intercept.
Take natural log of both sides (on data sheet)
lnk = -Ea/RT + lnA
lnk = -Ea/R x 1/T + lnA
Since k and T are the only variables, this is equivalent to y = mx + c
Plot lnk against 1/T
Gradient = -Ea/R and y-intercept = lnA
What is the unit of A in the Arrhenius equation?
The same as that of k.
What is the magnitude of the change in rate of a reaction with activation energy 50 kJ mol-1 when the temperature is increased from 20oC to 30oC?
In both cases, k = [X]m[Y]n so k is only factor affecting rate; k ∝ rate
Convert Ea into J (unit of gas constant) and T into K.
k1 = A e-50,000 / 8.314 x 293 = 1.2 x 109 A
k2 = A e-50,000 / 8.314 x 303 = 2.4 x 10-9 A
A is a constant, so number of collisions + therefore rate is multiplied by approx. 2
Which statement about the Arhenius equation is correct?
- A plot of lnk against T gives a straight line
- When T is very large, ln k almost equals A
- Ea is the gradient of a plot of ln k against 1/T
- A plot of k against 1/T gives a straight line
2
- Should be 1/T
- lnk = -Ea/R x 1/T + lnA = -Ea/RT + lnA so, as T → ∞, -Ea/RT → 0
- Should be -Ea/R
- Should be lnk
Suggest 5 methods of analysis which could be used to measure the rate of a reaction.
- Titration
- pH
- Colorimetry
- Volume of gas evolved
- Mass change
How does quenching work?
- Sample isolated from reaction mixture
- Chemical added which stops reaction (e.g. neutralises a catalyst)
- Sample titrated to find conc. of a reactant/product
To work out the rate equation for a reaction, you need to vary the concentration of the reactants one at a time.
In what 2 ways could you ensure that you are investigating the effect of a single reactant?
- Run one experiment with a given concentration of one reactant. Have other in excess so that its concentration does not change significantly
- Run several experiments with different concentrations of one reactant. Keep concentration of other reactant constant
Explain how the initial rate method can be used to determine the order of a reaction with respect to one reactant.
- Run several experiments with different concentrations of one reactant. Keep concentration of other reactant(s) constant
- Measure conc of first reactant throughout
- For each, plot concentration against time, then take gradient of tangent at origin: initial rate
- Plot initial rate against concentration:
- Flat line = 0 order wrt this reactant
- Straight line with gradient > 0: 1st order wrt this reactant
- If initial rate against conc2 is straight line with gradient > 0: 2nd order wrt this reactant

Explain how reaction time can be used to determine the order of a reaction with respect to one reactant.
- Run several experiments with different concentrations of one reactant. Keep concentration of other reactant(s) constant
- For each conc, measure time taken to form a small, fixed amount of a product
- Rate = amount of product / time. For given amount, initial rate ∝ 1/t
- Plot 1/t against concentration:
- Flat line = 0 order wrt this reactant
- Straight line with gradient > 0: 1st order wrt this reactant
- If 1/t against conc2 is straight line with gradient > 0: 2nd order wrt this reactant

Explain how half-lives can be used to determine whether a reaction is first order with respect to one reactant.
- Run one experiment with a given concentration of one reactant. Have other(s) in excess
- Measure concentration of reactant of interest throughout reaction
- Plot concentration against time
- Find 3 half-lives: time for concentration to halve
- Constant half-life indicates reaction is 1st order with respect to reactant of interest

B
A: gradient is constant, so rate with respect to A is constant; [A] doesn’t affect rate so 0, not 1st, order
C: insufficient information to know
D: they are
Which of these graphs is a straight line for the first order reaction Z → products?
- [Z] against time
- rate against [Z]
- ln k against 1/T
- A 1, 2 and 3
- B only 1 and 2
- C only 2 and 3
- D only 1
C
Not 1 as there is constant deceleration, not constant decrease.
A reaction is first order with respect to a catalyst, Y. What is true about a graph of [Y] against time?
- It will be a curve going downwards with constant half life
- It will be a straight line going downwards
- It will be a straight line parallel with the x-axis
- It will be a curve rising with decreasing rate
3
(Catalyst, so not used up during reaction)
H2O2 + 2H+ + 2I- → 2H2O + I2
Rate = k [H2O2] [I-]
Discuss the two mechanisms in terms of the orders of reaction and the individual steps. (4)
Mechanism 1
- H2O2 + I- → H2O + IO- (slow)
- IO- + 2H+ + I-→ I2 + H2O (fast)
Mechanism 2
- H2O2 + I- → H2O + IO- (fast)
- H+ + IO- →HIO (slow)
- H+ + HIO → H2IO+ (fast)
- H2IO+ + I- → I2 + H2O (fast)
- Mechanism 1 has correct slow step not involving H+
- The slow step would be first order with respect to H2O2 and I-
- Mechanism 2 has all two-body (AW) collisions
- One of:
- Slow step in 2 would give 1st order with respect to all 3 reagents
- Fast step of 1 very unlikely as 4 particles collide