CD deg: Aromatic compounds & their reactions Flashcards
Describe and draw the Kekulé structure of benzene.
Six-membered ring of carbon atoms with alternating single + double bonds.

Name 2 characteristics of benzene which were accurately predicted by the Kekulé model.
- Bond angles 120o
- Planar
Name three issues with the Kekulé model of the structure of benzene.
- Unexpected unreactivity with bromine water
- Discrepancy between observed and expected bond lengths (shapes)
- Discrepancy between observed and expected enthalpies of hydrogenation
Explain why benene’s unreactivity with bromine water was not accounted for by the Kekulé model of its structure. State the conclusion that this issue pointed towards.
- Kekulé model contains 3 C=C bonds, so benzene was expected to react with + decolourise bromine water
- Unreactivity suggests either that benzene has no double bonds, or that something makes those present less reactive
Explain why benene’s shape was not accounted for by the Kekulé model of its structure. State the conclusion that this issue pointed towards.
- Kekulé structure contains C-C + C=C bonds. C=C bonds are shorter so bonds in benzene expected to be different lengths
- All bonds in benzene are same length, so Kekulé bonding is incorrect
Explain why benzene’s enthalpy of hydrogenation was not accounted for by the Kekulé model of its structure. State the conclusion that this issue pointed towards.
- Enthalpy of hydrogenation of cyclohexa-1,3-diene is approximately twice that of cyclohexene, since it has twice as many double bonds, so that of benzene was expected to be 3 x that of cyclohexene
- Enthalpy of hydrogenation of benzene is lower than that of cyclohexa-1,3-diene
- Benzene’s structure is stabler than suggested by Kekulé model

Describe and draw the delocalised model of benzene.
- Carbon p-orbitals perpendicular to ring overlap, so electrons delocalise
- Forms circular π-orbitals above and below ring, containing 6 electrons overall

Like a bagel sandwich. Each carbon has 4 valence e-: 1 goes to C-H bond, 2 go to C-C bonds, 1 left over. 6 spare e- delocalise
Explain how the issues with the Kekulé model of benzene’s structure were rectified by the delocalised model.
Unreactivity with bromine water: carbon p-orbitals perpendicular to ring overlap, forming circular π-orbitals above and below ring. Delocalisation makes benzene stable, so doesn’t readily react by addition
Discrepancy between observed + expected shape: all bonds are equal length due to delocalisation
Discrepancy between observed + expected enthalpies of hydrogenation: delocalisation makes benzene stable, so hydrogenation doesn’t make benzene much more stable, so is less exothermic than predicted
Name this molecule:

1-ethyl-4-methyl benzene
Minimisation of numbers takes priority over alphabetical order (in this case, it would be 1-4 either way, so is in alphabetical order)
Name the following molecules:

Chlorobenzene, nitrobenzene, benzoic acid, benzene sulfonic acid
-NO2 = nitro group, -SO3H = sulfonic acid group
Name this molecule:

2-phenylbut-2-ene
Phenyl prefix is used to represent benzene when suffix is occupied
Name this molecule:

Phenylamine
Phenyl prefix is used to represent benzene when suffix is occupied
Name the following:
- C6H5OOCCH3
- C6H5COOCH2CH(NH2)CH3
- Phenyl ethanoate (molecular formula was written backwards)
- 2-amino propylbenzoate
What is an arene?
A molecule containing a benzene ring.
All arenes are aromatic, but this isn’t reversible
What are the conditions required for aromaticity?
Molecule must:
- Be cyclic
- Be planar
- Contain 4n + 2 delocalised π-electrons (where n = non-zero integer)
How can the number of delocalised electrons in a molecule be easily calculated?
No. double bonds x 2
Describe the bonding in aromatic molecules.
- All ring atoms have an available p-orbital perpendicular to ring
- P-orbitals overlap, so electrons delocalise
Is this molecule aromatic?

Yes, because:
- Cyclic
- Planar
- 4n + 2 delocalised π-electrons, where n = 3
Is this molecule aromatic?

Yes, because:
- Cyclic
- Planar
- 4n + 2 delocalised π-electrons, where n = 1
State and explain whether aromatic compounds undergo addition or substitution.
- Undergo substitution, since this maintains the stable delocalisation of electrons
- Don’t undergo addition since this would give 2 double bonds, which would be energetically unfavourable
- State the name of the mechanism by which aromatic compounds replace hydrogen atoms with other groups
- Draw a general mechanism to represent this
Electrophilic substitution

Initial attack of electrophile is slow + often unfavourable, so this step is catalysed
- Write the equation, using structural formulae, for the bromination of benzene
- State the conditions required
- Name the organic product
- FeBr3 (or form in situ from Fe), reflux
- Bromobenzene

Catalyst used to form Br+, which is a good electrophile
During the bromination of benzene, iron filings can be used to form the required catalyst in situ.
Using equations, describe the role of this catalyst in the reaction. Include an overall equation.
Formation of electrophile: Fe + 1.5Br2 → FeBr3
FeBr3 + Br2 → Br+ + FeBr4-
Reaction with benzene: Br+ + C6H6 → C6H5Br + H+
Regeneration of catalyst: FeBr4- + H+ → FeBr3 + HBr
FeBr3 → Fe + 1.5Br2
Overall: Br2 + C6H6 → C6H5Br + HBr
- Write the equation, using molecular formulae, for the chlorination of benzene
- State the conditions required
- Name the organic product
- C6H6 + Cl2 → C6H5Cl + HCl
- Anhydrous AlCl3
- Chlorobenzene
Using equations, describe the role of the AlCl3 catalyst used for the chlorination of benzene. Include an overall equation.
Formation of electrophile: Cl2 + AlCl3 → Cl+ + AlCl4-
Reaction with benzene: C6H6 + Cl+ → C6H5Cl + H+
Regeneration of catalyst: AlCl4- + H+ → AlCl3 + HCl
Overall: C6H6 + Cl2 → C6H5Cl + HCl
Suggest why halogenated arenes are important in industry.
Halogenation makes arenes more reactive, allowing the substitution of benzene into other molecules.
More reactive since halogens are good leaving groups
- Write an equation, using structural formulae, for the nitration of benzene
- State the conditions required
- Name the organic product
- c. HNO3 (reactant), c.H2SO4, below 55oC
- Nitrobenzene

At temperatures above 55oC, the 1,3-dinitro and 1,3,5-trinitro products form, which are highly explosive (TNT is trinitrotoluene, a.k.a. trinitro methylbenzene)
Using equations, describe the role of sulfuric acid in catalysing the nitration of benzene. Include an overall equation.
Formation of electrophile: HNO3 + 2H2SO4 → NO2+ + 2HSO4- + H2O + H+
Reaction with benzene: C6H6 + NO2+ → C6H5NO2 + H+
Regeneration of catalyst: 2HSO4- + 2H+ → 2H2SO4
Overall: HNO3 + C6H6 → C6H5NO2 + H2O
- Write the equation, using structural formulae, for the sulfonation of benzene
- State the conditions required
- Name the organic product
- H2SO4 (reactant), reflux
- Benzenesulfonic acid

- Describe how the electrophile in the sulfonation of benzene is formed
- Explain why it is a good electrophile
- Conc sulfuric acid dissociates: H2SO4 → SO3 + H2O
- 3 polar S=O bonds give central sulfur a large partial positive charge, making it susceptible to attack

Draw the mechanism for the sulfonation of benzene.
- Write a general equation for the Friedel-Crafts alkylation of benzene
- State the conditions required
- C6H6 + RCl → C6H5R + HCl
- Anhydrous AlCl3, reflux
Cl is replaced by benzene ring
- Write a general equation for the Friedel-Crafts acylation of benzene
- State the conditions required
- C6H6 + RCOCl → C6H5COR + HCl
- Anhydrous AlCl3, reflux
Cl is replaced by benzene ring
- Write equations to show how the electrophiles are formed in the Friedel-Crafts alkylation and acylation of benzene.
- Explain why they are good electrophiles.
Alkylation: AlCl3 + RCl → AlCl4- + R+
Acylation: AlCl3 + RCOCl → AlCl4- + RC+O
Both contain carbons with 1+ charge, which makes them susceptible to attack
Suggest why Fridel-Crafts substitution is important in the chemical industry.
It is a way of forming C-C bonds, and thereby extending chains or adding side chains.
- Write an equation showing the formation of the electrophile during the reaction between 2-chloropropane and benzene.
- Draw the mechanism for the reaction between benzene and the electrophile.
- Write an equation showing the reformation of the catalyst.
- Name the product.
Product: methyl ethylbenzene / 2-phenylpropane
- Write an equation showing the formation of the electrophile during the reaction between 2-ethanoyl chloride and benzene.
- Draw the mechanism for the reaction between benzene and the electrophile.
- Write an equation showing the reformation of the catalyst.
- Name the product.
Product: 1-phenyl propanone
Fill in the table summarising the substitution reactions of benzene.


Fill in the mechanism summary; in each box:
- Describe briefly what the mechanism applies to
- Draw the general mechanism

