Chromatography And Spectroscopy Chp 29 Flashcards

1
Q

Look for physical flashcards

A
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2
Q

Why is TMS used as a standard reference chemical?

A

It produces a strong single peak because:
- All Hs and Cs in the same environment
- All Hs and Cs are highly shielded (not affected by magnetic field)
- Inert, non-toxic, easy to remove (volatile)

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3
Q

Why are deuterated solvents used?

A

Deuterated solvents do not produce signals in the frequency ranges used in 1H and 13C NMR spectroscopy because D atoms have an even number of nucleons.

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4
Q

What are examples of deuterated solvents?

A

CDCL3 or Heavy water

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5
Q

What is the chemical shift?

A

The shift in frequency compared to TMS, required for a nucleus to undergo nuclear magnetic resonance.

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6
Q

What does the chemical shift depend on? What is it especially caused by?

A

The shift depends on the chemical environment, especially caused by the proximity of electronegative atoms or pi bonds.

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7
Q

What is Nuclear Magnetic Resonance (NMR) used for

A

To help determine the structure of a molecule

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8
Q

Resonance

A

When the nucleus absorbs energy and rapidly flips between the two spin states.

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9
Q

Carbon-13 NMR Spectroscopy

A
  • Tell us the number of different carbon environments- from the number of peaks
  • Tells us the types of carbon environments present, from the chemical shift
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10
Q

Proton NMR

A
  • Tells us the number of different hydrogen environment
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11
Q

Spin-spin coupling/splitting

A

Provides info about the number of hydrogens bonded to the adjacent carbon atom.

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12
Q

Why are OH and NH peaks difficult to identify?

A

-They sit in a broad area of the spectrum
-Normally found unsplit
-Large range

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13
Q

How do we identify OH and NH samples? (Proton transfer)

A

1) Run proton NMR with no D2O
2) Add D2O and shake vigorously
3) Run proton NMR again and compare 2 spectra to see if a peak has disappeared (OH or NH was present)

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14
Q

n + 1

A

‘n’ protons attached to adjacent carbon atoms

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15
Q

splitting patterns

A

-singlet
-doublet
-triplet
-quartet

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16
Q

Chromatography Stage 1: Preparing plate and applying solution

A
  • Apply solution of sample to pencil line using a capillary tube
  • Pencil line must be 1cm from bottom
17
Q

Chromatography Stage 2: Running and developing plate

A
  • Place solvent in chromatography tank, level solvent below line and allow solvent to reach within 1cm of the top
18
Q

Chromatography Stage 3: Developing and analysing

A
  • Remove plate from tank
  • Use UV to make spots visible
  • Calculate RF value and compare to data books
19
Q

RF Value equation

A

distance moved by component/distance moved by solvent front

20
Q

Integration value

A

Relative area under the peak is proportional the number of hydrogens causing the signal

21
Q

How does gas chromatography separate the compounds in a mixture if the stationary phase is liquid?

A

Relative solubility in the liquid polymer/stationary phase

22
Q

What happens to the RF value if you use a very polar solvent?

A

RF value would be larger

23
Q

Retention Time

A

The time taken for a component to travel through the capillary column in gas chromatography