5.5. Acid/Base Balance - Reabsorption of Bicarbonate Flashcards
Where does the bulk of bicarbonate reabsorption occur?
In the proximal tubule
What initiates the mechanism by which bicarbonate is reabsorbed?
Active H+ ion secretion from the tubule cells (into the tubule lumen), coupled with passive Na+ reabsorption
- What does the H+ ions, secreted from the tubule cells (into the tubule lumen), react with?
- What does this form?
- Filtered Bicarbonate (HCO3-)
2. Carbonic Acid (H2CO3)
Where does the reaction in the tubule, between H+ ions and the filtered bicarbonate (HCO3-), occur?
On the tubule luminal membrane
- What does the reaction between H+ ions and the filtered bicarbonate (HCO3-) in the tubule lumen happen in the presence of?
- What does this cause?
- Carbonic Anhydrase
- The splitting of the formed Carbonic Acid, into:
a) H2O
b) CO2
What happens to the H2O, formed by the Carbonic Anhydrase within the Tubule Lumen?
It is excreted
What happens to the CO2, formed by the Carbonic Anhydrase within the Tubule Lumen?
It travels into the Tubule Luminal Cell
What happens to the CO2 which enters into the Tubule Luminal Cell?
It reacts with the H2O present in the cell to form intracellular Carbonic Acid
What happens to the newly-formed intracellular Carbonic Acid ?
It is in the presence of Carbonic Anhydrase and so splits into:
a) H+ ions
b) HCO3-
within the tubule cell
What happens to the H+ ions which are formed due to the Carbonic Anhydrase in the Tubule Luminal Cell?
They are actively secreted, re-starting the cycle
What happens to the HCO3-
ions which are formed due to the Carbonic Anhydrase in the Tubule Luminal Cell?
These pass into the peritubular capillaries and then out into circulation
What is significant about this ion being reabsorbed?
Although it is not the same ion, the net effect is the same
What is the Glomerular Filtration Rate?
125ml/minute = 180L/day
What is the plasma bicarbonate concentration?
24mmol/L
How much bicarbonate is filtered per day?
Glomerular Filtration Rate = 180L/day
Plasma Bicarbonate concentration = 24mmol/L
180 x 24mmol/L = 4320mmol filtered per day