28-30 Flashcards

1
Q

reaction intermediates don’t pile up; when confronted by a slow step, they go in the reverse direction

A

Catalysts are not mentioned, either. Catalysts can be modified during a reaction, but return to original state at the end (CATALYST = REGENERATED)

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2
Q

three factors that influence rate

A

LOWER activation energy (via catalyst)
MORE CONCENTRATED reactants
HIGHER temperature

TEMPERATURE influences rate constant, k; does NOT change Ea (!IMPORTANT)

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3
Q

Catalyst == Ea

A

NOT G, H, or S

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4
Q

rate constant k

A

rate / [A]^a [B]^b

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5
Q

equillibrium

A

generation of product is the same as generation of reactants (rate = reverse_rate)

DYNAMIC equilibrium

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6
Q

K_a, K_b, K_s

A

all equilibrium constants

K_eq is a constant at a given temperature

TEMPERATURE INFLUENCES K_eq

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7
Q

K_a, K_b, K_s

A

all equilibrium constants

K_eq is a constant at a given temperature

TEMPERATURE INFLUENCES K_eq

K_sp is the solubility (salt) product constant

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8
Q

reaction quotient

A

Q - same as K_eq but fluctuates

Q > Keq, reverse reaction is favored
Q < Keq, forward reaction is favored

le Chatelier’s principle is related to Q

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9
Q

pressure and le Chatelier’s equation

A

see which side has more moles of gas

increased pressure = reduced volume = favors the fewer moles

PRESSURE CAUSES REACTIONS TO CONDENSE

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10
Q

reaction quotient

A

Q - same as K_eq but fluctuates

Q > Keq, reverse reaction is favored
Q < Keq, forward reaction is favored

le Chatelier’s principle is related to Q

Q = K_eq, reaction is at equilibrium
∆G = 0, reaction is at equilibrium

you can also calculate Q by [Partial pressure A]^a / [Partial pressure B]^b

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11
Q

temperature and le Chatelier’s equation

A

if the product is heat, then reducing temperature favors the forward process

likewise, adding heat shifts left

“LOWERING TEMPERATURE favors the exothermic reaction, raising temperature favors endothermic”

CHECK TO SEE ∆H and add heat to the equation

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12
Q

hydration

A

when solvent is water, it is hydration and aqueous

solvent is higher in proportion than solute

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13
Q

strong electrolyte = good conductor of electricity

A

covalent bonds = nonelectrolytes

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14
Q

ionizability factor (i)

A

tells us how many particles are dissociated in solution

glucose i =1
nacl i=2

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15
Q

phase solubility rules

A
  1. solubility of solids in liquids increases with temperature
  2. solubility of gases in liquids decrease with increasingly temperature
  3. gases dissolve better under high pressure
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16
Q

solubility of a gas

A

Solubility = kP

k, Henry’s law
P, partial pressure of gas above the liquid

17
Q

K_sp

A

K_sp = [Mg2+][OH-]^2

leave Mg(OH)2 out because it is a solid

equilibrium = rate at which ions go into solution same as precipitation

18
Q

Q_sp and Ksp

A

K_sp is when the solution is SATURATED

if Q_sp is greater than K_sp, then salt will precipitate

19
Q

common ion effect

A

hydroxide is added, will shift another chemical balance

20
Q

complex ion formation

A

creating a complex ion with Lewis base (NH3) takes away a ion from solution, driving forward the propensity of solid salt to exist as ions in solution

21
Q

complex ion formation

A

creating a complex ion with Lewis base (NH3) takes away a ion from solution, driving forward the propensity of solid salt to exist as ions in solution

22
Q

polyprotic acids and amphoteric substances

A

HCO3- is both a base and acid = amphoteric

23
Q

the relationship between [H3O+] and [OH-]

A

K_w is always 10^-14 (autoionization)

K_w increases with increasing temperature

adding acid will shift the equation to the left, decreasing [OH-]

[OH-] = K_w/[H3O+]

24
Q

pOH and pH always equal for acid-base conjugate pair

A

14 (based on K_w)

25
Q

p

A

NEGATIVE LOG

“peeing under a (-) log”

26
Q

acid-base conjugate pair

A

KaKb = 10^-14

pKa + pKb = 14

27
Q

LEWIS acid and base

A

ACID - electron RECEIVER
BASE - electron donor

A lewis acid causes another molecule to give up an Hydrogen

H+ is a conjugate acid, because it ACCEPTS OH-

OH- donor = BASE

28
Q

strength of acid

A

strong = completely dissociates, HIGH K_a value

HI, HBr, HCl

HClO4, H2SO4, HNO3

29
Q

strength of base

A

K_b

Group 1 hydroxides
Group 1 oxides
Ba(OH)2, Sr(OH)2, Ca(OH)2, “CAlifornia has StRong BAses”

Metal amides (NaNH2)

conjugate acid has NO acidic properties

30
Q

a 0.01 M solution of HCl is what pH

A

0.01 moles / L

pH = -log(0.01) = 2

31
Q

K_a

A

[H+][CN-] / [HCN] = x^2 / (starting amount)

32
Q

Neutralization

A

equimolar strong acid + strong base = neutral pH

weak acid + weak base = variable pH (not neutral)

weak acid or base + strong base/acid (equimolar) = complete neutralization

H+ + OH- -> H2O + heat

ALL equimolar neutralization reactions go to completion