(YELLOW) Carboxylic acids Flashcards

(YELLOW) Carboxylic acids

1
Q

Solubility decreases with increasing chain length. Explain why (in carboxylic acids)

A

The length of the non polar part increases therefore increased London forces between them and increased amount of energy needed to separate them. Not energetically compensated for by the new hydrogen bonds formed between the acid and water. Energy required to overcome h bonds in liquid water is also not compensated for.

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2
Q

What is the appearance of benzoic acid

A

White powder/crystals

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3
Q

Comment benzoic acid solubility in hot water and in cold

Explain the difference using intermolecular forces

A

Insoluble in cold water
Dissolves in hot water to give a colourless solution, crystallises out as solution cools.

H-bonding with water is not enough when cold to overcome the considerable London forces and H-bonding between benzoic acid molecules. When hot these forces can be overcome and benzoic acid forms H-bonds with water.

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4
Q

hydrolysis of a nitrile

how do you go from a nitrile to a carboxilic acid

give reagents , and conditions , and an general equation ( of the two types )

A

reagents : dil HCl ( + water and H+ catalyst )

donditions : heat under reflux

CH3CN + H2O + HCl —–> CH3COOH + NH4Cl

or with just water:

CH3CN + H2O —–> CH3COOH + NH3

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5
Q

hydrolysus of an amide

how do you go from an amide to a carboxilic acid

give reagents , and conditions , and an general equation

A

reagents : water and H+ catalyst
conditions: heat under relux (probs does not say)

CH3CHONH2 + H2O –(H+ catalyst)—> CH3COOH + NH3

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6
Q

write out the reaction between ethanoic acid and KOH

A

CH3CO2H(l) + KOH —–> CH3COO-K+ + H2O

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7
Q

write out the reaction between ethanoic acid and sodium

A

CH3CO2H(l) + Na —-> CH3COO-Na+ + ½ H2(g)

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8
Q

write out the reaction between propanoic acid and potassium hydroxide

A

CH3CH2CO2H (l) + KOH(aq) —> CH3CH2COO-K+ (aq) + H2O

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9
Q

write out the reaction between methanoic acid and sodium carbonate:

A

2H2COOH + Na2CO3 —> 2H2COO-Na+ + CO2 + H2O

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10
Q

write out the reaction between ethanoic acid and sodium hydrogencarbonate:

A

CH3COOH + NaHCO3 –> CH3CO O–Na+ + H2O + CO2

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11
Q

info card

A
  • Weak acids when compared to nitric, sulphuric and hydrochloric acids.
  • Stronger acids than alcohols, which are considered to be neutral.
  • Take part in typical acid reactions – with metals, carbonates and bases to form salts.
  • Salts formed from carboxylic acids are known as carboxylates.
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12
Q

are short chain carboxilic acids soluable in water

A

yes as they can form hydrogen bonds

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13
Q

rank on order of boiling points :
Butane , Butan-1-ol , Butanoic acid

explain why using intermolecular forces

A

Butane<Butanoic acid<Butan-1-ol

/ butane has only weak london forces therefore lowest b.p
/ butan-1-ol and butanoic acid both have h-bonding and london forces
/butanoic acid has more e- so stronger london forces and can form more extensive hydrogen bonds therefore more energy is required to break the intermolecular forces

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14
Q

why are carboxilic acids acids while alcohols are not

A

The reason why carboxylic acids are more acidic than alcohols is as follows. In addition to the O-H…the C=O group pulls electrons away from the –OH group making the H atom more d+. The equilibrium is shifted further to the right compared to their corresponding alcohols, favouring the deprotonated salt.

when a proton (H+ ion ) is lost , a pi bond is formed over the C-O atoms (COO-)
the negative charge is shared (delocalised) between the 3 atoms
this stabalisise the carboxilate ion
alcohols do not have this delocalisation so they do not readily lose protons

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15
Q

what are the observations and quation for adding :

1) To a 1cm3 of dilute ethanoic acid, add a
small quantity of a solid
carbonate (e.g. CaCO3).
Equation for reaction:
Collect the gas evolved
into a teat pipette and
bubble through a small
volume of fresh lime-
water.

A

Effervescence Test tube became warm

2CH3COOH + CaCO3 —-> (CH3COO-)2Ca2+ + H2O + CO2

Lime water —-> white ppt

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16
Q

what are the observations and quation for adding :

2) To a 1cm3 of glacial
ethanoic acid, add 1cm3
ethanol and 2 drops
conc. sulfuric acid.
Warm in a water bath
then tip onto a saturated
solution of Na2CO3 in a
small beaker. Smell
cautiously.
Equation for reaction

A

Exothermic before heating, effervescence on pouring onto Na2CO3

fruity smell

CH3COOH + CH3CH2OH —-> CH3COOCH2CH3 + H2O Ethyl ethanoate

Exothermic due to adding conc H2SO4 to aqueous solutions Effervescence as acids are neutralised Esters smell sweet/fruity Ester formed from reaction of carboxylic acid and alcohol So carboxylic acid present

17
Q

what are the observations and quation for adding :

The following reaction is
not a test but a useful
reaction to know.

To 10 drops dilute
ethanoic acid add
NaOH(aq) drop by drop
to excess. Describe the
CHANGE in smell.

Equation for reaction:

Evaporate to dryness
cautiously. Describe the
appearance of the
substance left and identify
it.

A

Exothermic Vinegar smell disappears

CH3COOH + NaOH —> CH3COO-Na+ + H2O Sodium ethanoate produced

If evaporated to dryness a white solid remains If HCl added —> vinegar smell
CH3COO-Na+ + HCl —> CH3COOH + NaCl

18
Q

what happens when you mix a carboxilic acid with PCl5

what happens when you mix AgNO3 with the product

what happens when you put conc ammonia near it

A

effovecence and steamy fumes

white ppt , carboxilic acid has to be in excess though

white smoke NH4Cl

19
Q

what happens when you mix R-OH with PCl5

give the equation

A

R-Cl + POCl3 + HCl (steamy fumes)

20
Q

what happens when you mix R-COOH with PCl5

give the equation

A

R-COOH + POCl3 + HCl (steamy fumes)

21
Q

give the equation for ethanoyl chloride with water

and conditions

A

CH3COCl + H2O —-> CH3-CHOOH + HCl

the water acts as a nuclio phile

room temp

22
Q

give the equation for ethanoyl chloride with an alcohol (ethanol)

conditions :

A

CH3COCl + CH3CH2OH —-> H3CCOOCH2CH3 + HCl

creates an ester

room temp anhydrys conditions

23
Q

give the equation for ethanoyl chloride with conc ammonia

conditions :

A

CH3COCl + NH3 —-> H3C-CONH2 + HCl

excess amonia results in NH3 + HCl —-> NH4Cl

room temp , anhydris conditions

24
Q

give the equation for ethanoyl chloride with C2H5NH2

conditions :

A

CH3COCl + C2H5NH2 —-> CH3CONHCH2CH3 + HCl

product name N-ethyl ethanamide

conditions : anhydris conditions , room temp

25
Q
A