Topic 14 Flashcards
1
Q
How do you setup an electrochemical cell?
A
- OBtain metals and clean to remove impurities
- Wash metals with propanone and place into solutions with the same ion
- Make a salt bridge with filterpaper soaked in saturated KNO2 or KCl linking the two beakers
- Connect the electrodes to a voltmeter and power source
2
Q
What is redox?
A
- Reduction = Gain of electrons
- Oxidation = Loss of electrons
OIL RIG
3
Q
What are reducing agents?
A
- They are oxsidised themselves
- Loose electrons
- Helps reduce another atom
4
Q
What is a oxsidising agent?
A
- Reduces itself
- Gains electrons
- Helps oxsisdise other substances
5
Q
What are half cells?
A
- One half of a chemical cell
- Constructed of a metal dipped in its ion
- OR a platinum electrode with 2 aqueous ions
6
Q
What reactions occur in an ion half cell?
A
Fe2+ + 2e- <-> Fe
7
Q
Why do we use a platinum electrode?
A
- Its inert but electrically conductive
- It allows for electricity to travel up electrode and into next cell
8
Q
What happens in an electrochemical cell?
A
- One side undergoes reduction the other oxidation
- Redox reaction
- Voltmeter find the Ecell / EMFwhich is the pd between the two
- Elecrons flow from a less reactive metal to the more reactive cell
9
Q
What is the standard electrode potential?
A
- Voltage produced from a standard half cell connected to a hydrogen half cell
- Standard hydrogen half cell = 0V
- Needed to compare other half cells
- Under standard conditions
- 298K
- 100 kPa
- 1 mol dm-3 conc of ions
10
Q
What does the standard hydrogen potential look like?
A
11
Q
How do you work out EMF?
A
- Use the electrode potentials of each half cell
- EMF = Reduced - Oxidised
- Larger V = Reduced
12
Q
What is the setup for a non metal and metal half cell
A
13
Q
What happens when a copper half cell and a hydrogen half cell is turned on
A
14
Q
What is cell notation?
A
15
Q
How can you predict feasibility using standard electrode potential?
A
- Work out standard EMF
- Reduced - Oxidised
- If the value is positive it is reduced
- The reaction is feasible