sym 5 Flashcards
in the D4h,, operations mix x and y but leave z
independent
so we can do a seperate x and y matrix,, and treat them separately to the z matrix
bc z’ normally = z bc its the principal so rotating it kinda just makes it stay in its place.
for D4h
so by splitting the xy from the z matrix we go from a 3x3 matrix to a
2x2 + 1x1 matrix
2x2 being xy
1x1 being z
for D4h
3x3 matrix can be simplified due to z’ being z,, and so it called a
reducible representation
for D4h
the 2x2 + 1x1 representation is therefore called the
irreducible representation
bc u cannot simplify the relationship between them any more.
for D4h
in Dh4,, the x and y vectors are
degenerate
theyre both in the same chemical environment
operations cause them to interchange
the px and py orbitals have the same energy
a vibration changing the x dipole moment has the same frequerncy as the one changing the y dipole moment
Eu meaning
ungerade
inversion // i does reverse the vectors!!!
Eg meaning
gerade// inversion // i doesnt change the vectors
the x and y orbitals in D4h belong to XXXX bc what
they belong to Eu
an irreducible representation
Eu bc inversion reverses both of them!!
from x –> -x
from y –> -y
what do matrixes help us do
they help us realise how much of the original vector is present in the new one
when the character chnages its 0
but then like the one where it says -1 is the new vector.
how do we find gamma // r // the reproducible representation
r for reproducible representation
we draw an arrow at each atom around the central atom and see how these chnage with the operation:
for E in ammonia,, its 3,, bc when u do the identity operation all the arrows stay in the same place (they dont change so 1 + 1 + 1 bc theres 3 arrows)
for the 2C3 its 0,, bc they all change,, so 0 + 0 + 0 = 0
for 3sigmav (plane running through each NH bond) when u do it only one think stays the same (the bond ur going through) so u get 0 + 0 + 1 = 1
remmeber if it chnages its 0 and if it doesnt change its 1
how to remmeber when we use 0 and when we use 1
1 will stay where it is bc its standing up and straight
0 will roll away bc its curved so it will move
how do we know if what weve foun usung ‘r’ is reducble
bc it doesnt match any of the standard irriducible representations
group theory and reducible representation exppp
group theory says that any reducible representation can be broken down into a sum of standard irreducible representations
these will give the labels for the representations of the fundamental vibrations we need to predict the lines that should be seen in ir and raman spec.
h =
order of the group
total number of operations in the group (add the big numbers of the clases up)
what is the gc of a class
the big number of the classss
what is the gc of the operation 2C3
the gc would be 2
the large number