SNS - General Chemistry - Compounds And Stoichiometry Flashcards
Stoichiometry
Refers to the quantitative realtionships among compounds in a chemical reaction
Stoichiometry
Law of constant composition
Any sample of a given compound will contain the same elements in an identical mass ratio, for example every sample of H2O will contain two atoms of hydrogen for every atom of oxygen, and one gram of hydrogen for every eight grams of oxygen
Avogadro’s Number
6 x 10^23
Stoichiometry Mole
The amount of substance that contains as many units as the number of atoms in 12 grams in 12g 12C. It is the central unit of measurement in chemistry.
Stoichiometry
% Composition
= Mass of X in formula / formula weight of compound x 100%
Stoichiometry Empirical Formula
Gives the smallest whole-number ratio of elements in a particular compound.
Stoichiometry Empirical Formula Finding Empirical Formula From % Composition
- Assume 100g sample 2. Find the number of moles of each element present in 100g sample by dividing % present by atomic mass 3. Divide numbers of moles by the smallest number of moles calculated to be present, eg, 4:6 = 1:1.5 - 2:3
Stoichiometry Molecular Formula
Gives the actual number of aloms of each element present in a particular compound
Types of Reaction
- Combination 2. Decomposition 3. Single-replacement 4. Double-replacement 5. Combustion 6. Redox 7. Neutralisation
Types of Reaction Combination
Involve the formation of one product by two or more substrates. Ofter called synthesis reactions If heat of formation is negative, the reaction proceeds spontaneously in order to acheive a lower eneergy state and is exothermic. With large negative values, the reaction proceeds rapidly and vice versa.
Types of Reaction Decomposition
Involve the formation of two or more products from one substrate A very high positive value for the heat of formation indicates that a reaction will decompose explosively. A very high negative value indicates that the reaction is highly exothermic and will be difficult to decompose
Types of Reaction Zn + S -> ZnS
Combination
Types of Reaction 2HgO -> 2Hg + O2
Decomposition
Types of Reaction Single Replacement
A single element reacts with a compound to produce a different element and a new compound
Types of Reaction Double Replacement
Involve two compunds. The cations for the two compunds switch places
Types of Reaction 2AgNO3 + Zn -> Zn(NO3)2 + 2Ag
Single Replacement
Types of Reaction MgSO4 + BaCl2 -> MgCl2 + BaSO4
Double Replacement
Types of Reaction Combustion
Start by combining an organic substance with oxygen to form carbon-dioxide and water If the original organic compound contains an element other that carbon, hydrogen or oxygen, these elements must be in their elemental state in the product
Types of Reaction C5H12 + 8O2 -> 5CO2 + 6H2O
Combustion
Types of Reaction Redox
Involve the transfer of electrons by a compund or ion. If electrons are on the right (product side), it is an oxidation reaction. If electrons are on the left (reactant) side, a reduction reaction has taken place. Thgese reactions are usually broken down into two half equations
Types of Reaction I2 + 2Fe2+ -> 2Fe3+ + 2I-
Redox
Types of Reaction I2 + 2e- -> 2I-
Reduction
Types of Reaction 2Fe2+ -> 2Fe3+ + 2e-
Oxidation
Types of Reaction Neutralisation
or Hydrolysis reactions A form of double replacement reaction using an acid and a base to form a salt and water
Types of Reaction HCl + NaOH -> H2) + NaCl
Neutralisation/Hydrolysis
Equivalents
For some substances it is useful to define a measure of reactive capacity, for example the ability of acids to donate protons. One mole HCl can donate one mole H+ while one mole H2SO4 can donate two moles H+. This difference is expressed using the term ‘equivalent’: One mole HCl contains one equivalent of H+, one mole H2SO4 contains two
By using equivalents, it is possible to say whether one equivalent will neutralise one equivalent of base - not necessarily true when dealing with moles
Gram-Equivalent Weight
Used to determine the number of equivalents a compound contains:
Equivalents = weight of compound / gram equivalent weight
GEW = molar mass / n
where n = usually either the number of hydrogens used per molecule of acid in a reaction or the number of hydroxyl ions used per molecule of base in a reaction
% Composition of Chromiun in K2Cr2O7
Mass of chromium in compound = 52 x 2 = 104
Formula mass = 104 + (39 x 2) + (16 x 7) = 294
% Composition = 104/294 x 100% = 35.4%
Molecular and empirical formulae of a compound containing 40.9% carbon, 4.58% hydrogen, 54.52% oxygen with a molecular weight of 264 g/mol
- Carbon: 40.9/12 = 3.41, Hydrogen: 4.58, Oxygen: 54.52/16 = 3.41
- Carbon: 3.41/3.41 = 1, Hydrogen: 4.58/3.41 = 1.34, Oxygen = 3.41/3.41
- Therefore 3C:4H:3O, empirical formula C3H4O3, mass = (36 + 4 + 48) = 88
- = 264/88 = 3, Molecular formula = C9H12O9
Balance the Equation:
C4H10 (l) + O2 → CO2 (g) + H2O (l)
2C4H10 + 13O2 → 8CO2 + 10H2O
How many grams CaCl are needed to prepare 72g AgCl according to the following equation:
CaCl2 (aq) + 2AgNO3 (aq) → Ca(NO3)2 (aq) + 2AgCl (s)
- =72/(144) = 0.5
- =2/0.5 = 4
- =(110) / 4 = 27.5g
Percent Yield
= Actual Yield / Theoretical Yield x 100%