Pumping Apparatus Flashcards
Friction Loss Coefficient - Single Hoselines:
Hose diameter of 1 3/4 inch with 1 1/2 inch couplings has a “coefficient” fiction loss of:
15.5
The friction loss in 100 feet of 2 1/2 inch hose flowing 200 GPM is 10 PSI. What would the friction loss in 300 feet of 2 1/2 inch hose flowing 200 GPM be?
30 PSI
Friction Loss Coefficient - Single Hoselines:
Hose diameter of 2 1/2 inches has a “coefficient” friction loss of:
2
Friction Loss Coefficients - Siamesed Lines of Equal Length:
Two 2 1/2 inch hoses has a “coefficient” fiction loss of:
0.5
Friction Loss Coefficients - Siamesed Lines of Equal Length:
Two 3 inch hoses with 2 1/2 inch couplings has a “coefficient” fiction loss of:
0.2
What is the formula to find friction loss? Equation A:
Friction loss = ( )( )sq( )
Friction Loss = (coefficient #) x
flow-rate in hundreds of GPM / 100)sq x (hose length in hundreds of feet / 100
Formula to find “elevation pressure” is:
- When # of feet is given:
- When # of stories/floors are given:
EP = (0.5)(Height in feet)
Or
EP = (5psi)(# of stories - 1)
An engine is pumping through 500 feet of 2 1/2 inch hose flowing at 300 gallons per minute and the nozzle is operating 100 feet below the pump. Friction loss combined with elevation loss would be:
40psi
FL=(coefficient)(flow rate / 100)sq(hose length /100) FL=(2)(300 / 100)sq(500 / 100) FL=(2)(3)sq(5) FL=(2)(9)(5) FL=90 ----------------------------------------- EP=(0.5)(100) EP=50 ----------------------------------------- TFL = FL-EP TFL = 90-50 TFL = 40psi
Water exerts a pressure of 0.434 PSI per foot of elevation.
- When a nozzle is operating at an elevation higher than the apparatus, this pressure is exerted back against the pump. To compensate for this pressure “loss”, elevation pressure must be _____ to the friction loss to determine total pressure loss.
- Operating a nozzle lower than the pump results in pressure pushing against the nozzle. This “gain” in pressure is compensated for by _____ the elevation pressure from the total friction loss.
- adding
2. subtracting
An engine is pumping through 150 feet of 2 1/2 inch at 300 GPM and has a nozzle pressure of 50 psi.
- The friction loss of the hose would be: (exam sts: “FL would be most nearly:”)
- The friction loss of the hose and nozzle would be:
1. FL=(2)(300/1)sq(150/1) FL=(2)(3)sq(1.5) FL=(2)(9)(1.5) FL= 27 psi (^ exam answer, didn't add NP?)
- TFL= FL+NP
TFL= 27+50
TFL= 77 psi
- When solid stream nozzles are used on hand lines, they should be operated at _____ PSI nozzle pressure.
- A solid stream master stream device should be operated at _____ PSI.
- 50 PSI
2. 80 PSI
In most cases, (1)_____ PSI is used as a nozzle pressure for solid stream hand lines equipped with up to 1 1/2 inch nozzles. If greater rate and volume are needed, the nozzle pressure may be raised to (2)_____ PSI without becoming unmanageable. Above this point, solid streams become increasingly difficult to handle.
- 50 PSI
2. 65 PSI
The most amount of water that can be safely flowed through a handline is:
A. 250 GPM.
B. 300 GPM.
C. 350 GPM.
D. 400 GPM.
C. 350 GPM
The friction loss in 600 feet of 2 1/2 inch hose flowing at 200 GPM is most nearly:
FL = (2)(200/100)sq(600/100) FL = (2)(2)sq(6) FL = (2)(4)(6) FL = 48 psi
The master stream is the “big gun” of the fire department:
- Smoothbore master streams are usually operated at _____ PSI
- and fog master streams at _____ psi.
- Master stream flows are usually _____ GPM or greater.
- 80 PSI
- 100 PSI
- 350 GPM
A hoseline is operating on the 10th floor of a high-rise building. The building is equipped with a standpipe system. What is the total pressure loss due to elevation at the base of the standpipe system?
EP = 5 PSI x (# of stories - 1) EP = 5 PSI (10 - 1) EP = 5 PSI (9) EP = 45 PSI
A hoseline is operating on the 12th floor of a high-rise building. The building is equipped with a standpipe system. What is the total pressure loss due to elevation at the base of the standpipe system?
EP = 5 PSI (# of stories - 1) EP = 5 PSI (12 - 1) EP = 5 PSI (11) EP = 55 PSI
Your pumper is operating from a hydrant. The static pressure is 90 psi, and the residual pressure is 82 PSI. You are supplying a hoseline flowing 300 GPM. Using the percentage method of calculating additional water available, what is the percentage drop in this layout?
Percent Drop = (Static-Residual)(100) / Static PD = (90-82)(100) / 90 PD = (8)(100) /90 PD = 800/90 PD = ~ 9%
Static/Residual Additional Hydrant Water:
If the percentage drop is 10% or less, _____ additional lines with the same flow as the line being used maybe added.
3
Static/Residual Additional Hydrant Water:
If the percentage drop is 11%-15%, _____ additional lines with the same flow as the original line may be added.
2
Static/Residual Additional Hydrant Water:
If the percentage drop is 16%-25%, _____ additional line equal to the flow of the original line may be added.
1
Static/Residual Additional Hydrant Water:
If the percentage drop is over 25%, _____ additional lines with the same flow as the original line may be added.
Zero
-More water may be available, but not as much that is flowing through the original line being used.
Your pumper is operating from a hydrant. The static pressure is 90 PSI, and the residual pressure is 82 PSI. You are supplying a hoseline flowing 300 GPM. Using the percentage method of calculating additional water available, how many more lines are available from this layout?
3 more lines
An automatic nozzle will maintain a constant nozzle pressure of _____ PSI, no matter how much the pump discharge pressure is above this figure. As pump discharge pressure is increased, the nozzle automatically enlarges its effective opening size (within the range of the nozzle) to match the flow.
100 PSI
What is the friction loss in 200 feet of 2 1/2 inch hose flowing 300 GPM?
FL=(C)(GPM/100)sq(HL/100) FL=(2)(300/100)sq(200/100) FL=(2)(3)sq(2) FL=(2)(9)(2) FL= 36 PSI
The two factors affecting fog streams that are not applicable to solid streams are:
A. Water velocity and water droplet friction with the air.
B. Fire stream pattern, and water droplet friction with air.
C. Water velocity and gravity.
D. Gravity and fire stream pattern.
B. Fire stream pattern, and water droplet friction with air.
Tests have revealed that there are practical working limits for velocity of fire streams. Do not operate portable master stream devices equipped with solid stream nozzles above _____ PSI.
80 PSI
The heat resulting from improperly insulated or faulty electrical materials. This is particularly evident where the insulation is required to handle high-voltage or loads near maximum capacity. This statement best describes:
A. Electric Heating.
B. Resistance Heating.
C. Leakage current heating.
D. Arching.
C. Leakage current heating.
Determine the friction loss in a 1 3/4 inch hose line 100 feet long, flowing 200 GPM.
FL = (C)(GPM/100)sq(HL/100) FL = (15.5)(200/1)sq(100/100) FL = (15.5)(2)sq(1) FL = (15.5)(4)(1) FL = 62 PSI
Water has a number of characteristics that make it an excellent extinguishing agent. The following statements are disadvantages to using water… the exceptions:
A. A relatively large amount of heat is required to change water into steam.
B. Water has a high surface tension.
C. Low viscosity.
D. Electrical conductivity.
A. A relatively large amount of heat is required to change water into steam. (Advantage)
There are some disadvantages to using water as a fire extinguishing agent. These disadvantages are due to some additional properties that water possesses. One disadvantage of water is that it has a high surface _____ :
A. Viscosity
B. Tension
C. Reflectivity
D. Opacity
B. Tension
- ) _____ feet of water column exerts 1 PSI.
2. ) Therefore, water under pressure of 55 PSI will move water _____ feet up a standpipe.
- ) 2.304 feet
2. ) ~ 125 feet
What is the elevation pressure required to move water up to the top of a 150 foot hill?
EP = (0.5)(feet) EP = (0.5)(150) EP = 75 PSI
If 300 GPM is flowing from a nozzle on a 2 1/2 inch hose 200 feet long, the friction loss will be:
FL = (C)(GPM/100)sq(HL/100) FL = (2)(300/100)sq(200/100) FL = (2)(3)sq(2) FL = (2)(9)(2) FL = 36 PSI
If 200 GPM is flowing from a nozzle, what is the total pressure loss due to friction for 100 feet of 2 1/2 inch hose?
FL = (C)(GPM/100)sq(HL/100) FL = (2)(200/100)sq(100/100) FL = (2)(2)sq(1) FL = (2)(4)(1) FL = 8 PSI
- ) The weight of one cubic foot of water is approximately _____ lbs.
- ) Water weighs approximately _____ lbs per gallon.
- ) 62.5 lbs
2. ) 8.33 lbs
4 Principles of Friction Loss:
Which principle can be illustrated by: One hose that is 100 feet long, and another that is 200 feet long, both flowing 200 GPM. The 100 foot hose has a friction loss of 10 PSI and the 200 foot long has a friction loss twice as much, 20 PSI.
A. 1st Principle: If all other conditions are the same, friction loss of varies directly with the length of the hose or pipe.
B. 2nd Principle: When hoses are the same size, friction loss varies approximately with the square of the increase in the velocity of the flow.
C. 3rd Principle: For the same discharge, friction loss varies inversely as the fifth power of the diameter of the hose.
D. 4th Principle: For a given flow velocity, friction loss is approximately the same, regardless of the pressure on the water.
A. 1st Principle: If all other conditions are the same, friction loss of varies directly with the length of the hose or pipe.
4 Principles of Friction Loss:
Which principle can be illustrated by: That friction loss develops much faster than the change in velocity.
A. 1st Principle: If all other conditions are the same, friction loss of varies directly with the length of the hose or pipe.
B. 2nd Principle: When hoses are the same size, friction loss varies approximately with the square of the increase in the velocity of the flow.
C. 3rd Principle: For the same discharge, friction loss varies inversely as the fifth power of the diameter of the hose.
D. 4th Principle: For a given flow velocity, friction loss is approximately the same, regardless of the pressure on the water.
B. 2nd Principle: When hoses are the same size, friction loss varies approximately with the square of the increase in the velocity of the flow.
4 Principles of Friction Loss:
Which principle can be illustrated by: The advantage of larger size hose.
A. 1st Principle: If all other conditions are the same, friction loss of varies directly with the length of the hose or pipe.
B. 2nd Principle: When hoses are the same size, friction loss varies approximately with the square of the increase in the velocity of the flow.
C. 3rd Principle: For the same discharge, friction loss varies inversely as the fifth power of the diameter of the hose.
D. 4th Principle: For a given flow velocity, friction loss is approximately the same, regardless of the pressure on the water.
C. 3rd Principle: For the same discharge, friction loss varies inversely as the fifth power of the diameter of the hose.
4 Principles of Friction Loss:
Which principle can be illustrated by: Why friction loss is the same when hoses or pipes at different pressures flow the same amount of water.
A. 1st Principle: If all other conditions are the same, friction loss of varies directly with the length of the hose or pipe.
B. 2nd Principle: When hoses are the same size, friction loss varies approximately with the square of the increase in the velocity of the flow.
C. 3rd Principle: For the same discharge, friction loss varies inversely as the fifth power of the diameter of the hose.
D. 4th Principle: For a given flow velocity, friction loss is approximately the same, regardless of the pressure on the water.
D. 4th Principle: For a given flow velocity, friction loss is approximately the same, regardless of the pressure on the water.
What is the total pressure loss due to friction in 500 feet of 2 1/2 inch hose when 400 GPM is flowing?
FL = (C)(GPM/100)sq(HL/100) FL = (2)(400/100)sq(500/100) FL = (2)(4)sq(5) FL = (2)(16)(5) FL = 160 PSI
A hoseline operating on a 10th floor structure fire is connected to the building standpipe system. What is the total pressure loss due to elevation at the base of the standpipe system?
EP = (5)(stories-1) EP = (5)(10-1) EP = (5)(9) EP = 45 PSI
Determine the total pressure loss in the hose assembly when a fire department pumper is supplying two 3 inch lines with 2 1/2 inch couplings, each 200 feet long. These hose lines are connected to a siamese appliance that is in turn supplying a pre-pipe elevating platform. The platform is elevated 70 feet and is discharging 1500 GPM.
FL=(c)(GPM/100)sq(HL/100)+EP+AP FL=(0.2)(15)sq(2) +EP+AP FL=(0.2)(225)(2) + (0.5)(70) + AP FL=90+35+10siamese+25applianceFL=90+35+35 FL = 160 PSI
(Exam’s answer is 150 PSI)
Using the percentage method, if the static pressure is 50 PSI and the residual pressure is 43 PSI how much water can be delivered?
PD=(Static-Residual)(100)/Static PD=(50-43)(100)/50 PD=(7)(100)/50 PD=700/50 PD= 14% = 2 more lines
Two statewide studies on collisions involving EMS vehicles provide keen insight into the collision problem. According to these two studies, when did most collisions occur?
A. While responding to emergency calls.
B. Broad daylight on dry roads.
C. Snow, ice, or rain conditions.
D. At night time.
B. Broad daylight on dry roads.
Drafting operations are required when a pumper is going to be supplied from a static water supply source such as a pond, lake, stream or cistern. The best drafting locations are all of the following; the exception is:
A. Bridges over water source.
B. Boat ramps adjacent to the water source.
C. Banks along a river or stream.
D. Large docks next to the water source.
C. Banks along a river or stream.
Calculate the total pressure loss due to elevation pressure for a hoseline operating at the top of a 200 foot hill.
EP = (0.5)(200) EP = 100 PSI
Calculate the total pressure loss due to elevation pressure for a hoseline operating at the top of a 300 foot hill.
EP = (0.5)(300) EP = 150 PSI
A hoseline is operating on the 8th floor of twenty story building connected to the buildings standpipe system. What is the pressure loss due to elevation at the base of the standpipes system?
EP = 5(8-1) EP = 5(7) EP = 35 PSI
Foam Proportioning: 4 Basic Methods:
This method of proportioning foam uses the pressure energy in the stream of water to draft foam concentrate into the fire stream. This is achieved by passing the stream of water through a venturi device called an eductor, and a pickup tube from the eductor is inserted into the foam concentrate container. In-line eductors and foam nozzle eductors are examples of foam proportioners that work by this method.
A. Induction.
B. Injection.
C. Batch mixing.
D. Premixing.
A. Induction.
Foam Proportioning: 4 Basic Methods:
This method of proportioning foam uses an external pump or head pressure to force foam concentrate into the fire stream at the correct ratio in comparison to the flow. These systems are commonly employed in apparatus-mounted or fixed fire protection system applications.
A. Induction.
B. Injection.
C. Batch mixing.
D. Premixing.
B. Injection.
Foam Proportioning: 4 Basic Methods:
This is the simplest method of mixing foam concentrate in water. This occurs when the appropriate amount of foam concentrate is poured directly into a tank of water.
A. Induction.
B. Injection.
C. Batch mixing.
D. Premixing.
C. Batch mixing.
Exam question ^
Foam Proportioning: 4 Basic Methods:
This is one of the more commonly use methods of proportioning. With this method, premeasured portions of water and foam concentrate are mixed in a container. Typically, this method is used with portable extinguishers, wheeled-extinguishers, skid-mounted twin agent units, and vehicle mounted tank system. These systems are limited to a one-time application.
A. Induction.
B. Injection.
C. Batch mixing.
D. Premixing.
D. Premixing.
Determine the total pressure loss for a fire Department pumper that is using two 3 inch hose lines with 2 1/2 inch couplings to supply an elevated master device with fixed piping 200 feet away. The elevated master stream is discharging 2000 GPM. Through a fog nozzle that is elevated 80 feet.
FL=(c)(GPM/100)sq(HL/100)+EP+AF FL=(0.2)(20)sq(2) +0.5x80+AF FL=(0.2)(400)(2) +40+25(MS) FL=160+40+25 FL=225 PSI (For Master Streams - piped "attached" or "fixed" water ways the Siamese is not calculated, in "detachable" ladder pipe the Siamese fiction loss is used.)
- Siamese connections require adding _____ PSI appliance friction loss when flowing 350GPM or more.
- Master Stream add _____ PSI appliance pressure loss.
- Aerial Devices using piped or fixed waterways add _____ PSI appliance loss (Siamese connection need not to be calculated when using fixed aerial devices).
- If traditional detachable ladder pipe hose assembly are used, the friction loss with the Siamese (if used), hose, and ladder pipe must be accounted for.
- 10 PSI
- 25 PSI
- 25 PSI
- 25 PSI + Siamese 10 PSI (if used)
What will be the total pressure loss due to friction when 300 GPM is being discharged from a nozzle that is attached to 100 feet of 3 inch hose?
(Using condensed Q formula: Developed for fire ground operations in which friction loss can be determined for 3, 4, & 5 inch hose. Note the amount of friction loss calculated using this formula will be 20% greater than if the same situation is calculated using FL=CQsqL)
GPM=discharged GPM/100
FL=(GPM)sq
GPM=300/100
GPM=3
FL=(3)sq
FL= 9 PSI
A pumpers supplying one line with 250 GPM flowing. The static pressure was 60 PSI, and the residual pressure reading is 54 psi. Determine how many additional lines may be added.
PD = (static-residual)(100)/static PD = (60-54)(100)/60 PD = 600/60 PD = 10% - 3 more additional lines
Class A foam concentrates are mixed in proportioner’s of 0.1% to 3%; However, most commonly used concentrates are mixed in proportioners of 0.2% to 1%. When used in the ratio of 0.5% to 1%, this concentration would be used for:
A. Enclosed spaces such as coal mines or basements with standard foam nozzles.
B. On liquid hydrocarbon fires with standard foam nozzles.
C. Exposure protection with standard fog nozzles.
D. Polar solvent fires with smooth bore nozzles.
C. Exposure protection with standard fog nozzles.
- 0.5% to 1% foam concentrate
Starting the Vehicle: 5 Steps:
The first this the driver/operator needs to know is where the apparatus is going. Then 5 steps:
Step 1: Step 2: Step 3: Step 4: Step 5:
Step 1: Disconnect all ground shore lines. (Step 1 is an Exam question)
Step 2: Turn on the vehicle battery.
Step 3: Start engine.
Step 4: Observe the apparatus gauges.
Step 5: Adjust the seat, mirrors, and steering wheel.
A pumper is supplying a 500 foot of 2 1/2 inch hose with a 300 GPM fog nozzle. Determine the pump discharge pressure required to supply the hoseline.
FL = (C)(GPM/100)sq(HL/100) + NP FL = (2)(300/100)sq(500/100) + NP FL = (2)(3)sq(5) + 100 FL = (2)(9)(5) + 100 FL = 90 + 100 FL = 190 PSI
What will be the total friction loss due to friction when 200 GPM is is being discharged from a nozzle that is attached to 100 feet of 3 inch hose?
GPM=discharged GPM/100
FL=(GPM)sq
GPM=200/100
GPM=2
FL=(2)sq
FL= 4 PSI
NFPA 1002 specifies a number of practical driving exercises that the driver/operator candidate should be able to successfully complete before being certified to drive the apparatus. The practical exercise that is described as: (4)
Tests the driver/operator’s ability to back the apparatus while turning; move the vehicle backward within a restricted area without striking the walls and to bring the vehicle to a smooth stop close to the rear wall.
A. Alley Dock Exercise.
B. Serpentine Course Exercise.
C. Confined Space Turnaround Exercise.
D. Diminishing Clearance Exercise.
A. Alley Dock Exercise.
NFPA 1002 specifies a number of practical driving exercises that the driver/operator candidate should be able to successfully complete before being certified to drive the apparatus. The practical exercise that is described as: (4)
Simulates backing around parked vehicles and other obstacles. Simulates maneuvering around parked/stopped vehicles and tight corners.
At least 3 markers are placed an equal distance apart in a line; the driver/operator is required to maneuver the vehicle first backward through the coarse and the forward. Must be traveled in each direction in one continuous motion without touching any of the coarse markers.
A. Alley Dock Exercise.
B. Serpentine Course Exercise.
C. Confined Space Turnaround Exercise.
D. Diminishing Clearance Exercise.
B. Serpentine Course Exercise.
NFPA 1002 specifies a number of practical driving exercises that the driver/operator candidate should be able to successfully complete before being certified to drive the apparatus. The practical exercise that is described as: (4)
Simulates the need to reverse directions with little room to maneuver; tests the driver/operator’s ability to turn the vehicle 180 degrees with limited space.
A. Alley Dock Exercise.
B. Serpentine Course Exercise.
C. Confined Space Turnaround Exercise.
D. Diminishing Clearance Exercise.
C. Confined Space Turnaround Exercise.
NFPA 1002 specifies a number of practical driving exercises that the driver/operator candidate should be able to successfully complete before being certified to drive the apparatus. The practical exercise that is described as: (4)
Measures the driver/operator’s ability to steer the apparatus in a straight line, to judge distances from wheel to object, and to stop at a finish line. Tests the ability to steer the apparatus in very narrow spaces.
A. Alley Dock Exercise.
B. Serpentine Course Exercise.
C. Confined Space Turnaround Exercise.
D. Diminishing Clearance Exercise.
D. Diminishing Clearance Exercise.
^ exam question
Determine the pump discharge pressure for fire Department pumper that is using two 3 inch hoselines with 2 1/2 couplings to supply an elevated master device with fixed piping 200 feet away. The elevated master stream is discharging 1000 GPM through a fog nozzle that is elevated 60 feet.
FL=(C)(GPM/100)sq(HL/100)+EP+MS+NP FL=(0.2)(10)sq(2)+EP+MS+NP FL=40+EP+MS+NP FL=40+30+25+100 FL= 195 PSI
What will be the total pressure loss in 500 feet of 4 inch hose flowing 1000GPM?
GPM = GPM Discharged/100 FL = (GPM)sq
GPM = 10
FL = (10)sq FL = 100 PSI
A pumper is flowing one line with 250 GPM flowing. The static pressure was 70 PSI, and the residual pressure is reading 63 PSI. Determine how many additional lines can be added.
PD = (static-residual)(100)/static PD = (70-63)(100) / 70 PD = (7)(100) / 70 PD = 700 / 70 PD = 7% - 3 additional lines
Altitude affects the production of fire streams because atmospheric pressure drops as height above sea level increases. This pressure drop is of little consequence to about _____ feet. Above this height, though, the lessened atmospheric pressure can be of concern.
A. 500 feet.
B. 1000 feet.
C. 2000 feet.
D. 2500 feet.
C. 2,000 feet.
At high altitudes, fire department pumpers must work harder to produce effective fire stream pressures. Above sea level, atmospheric pressure decreases approximately:
A. 5 psi for every 500 feet.
B. 5 psi for every 1000 feet.
C. 10 psi every 500 feet.
D. 10 psi every 1000 feet.
B. 5 psi for every 1000 feet.
Two 2 1/2 inch hoselines, one 500 feet long and the other 300 feet long, are equipped with 250 GPM fog nozzles. Determine the pump discharge required to supply the hoselines.
(Only need to calculate longest HL since the second HL can be gated back) FL = (C)(GPM/100)sq(HL/100)+NP FL = (2)(250/100)sq(500/100)+NP FL = (2)(2.5)sq(5) + NP FL = (2)(6.25)(5) + 100 FL = 62.5 + 100 FL = 162.5 PSI
What will be the total pressure loss in 600 feet of 4 inch hose flowing 1000 GPM?
GPM = discharged GPM/100 GPM = 1000/100 GPM = 10
FL = (GPM)sq FL = (10)sq FL = 100 PSI
(Exam says 120 PSI?)
A pumper is supplying one line with 250 GPM flowing. The static pressure was 70 PSI, and the residual pressure is reading 63 PSI. Determine how many additional lines can be added:
PD = (static-residual)(100)/static PD = (70-63)(100) / 70 PD = (7)(100) / 70 PD = 700 / 70 PD = 10% - 3 additional lines
Determine the pump discharge pressure for fire Department pumper that is using two 3 inch hoselines with 2 1/2 inch couplings to supply an elevated master device with fixed piping 250 feet away. The elevated master stream is discharging 1000 GPM through a fog nozzle that is elevated 70 feet.
FL=(C)(GPM/100)sq(HL/100)+MS+EP+NP FL=(0.2)(1000/100)sq(250/100)+MS+EP+NP FL=(0.2)(100)(2.5)+25+35+100 FL= 50 + 160 FL = 210 PSI
What will be the total pressure loss in 600 feet of 4 inch hose flowing 1000 GPM?
GPM = (GPM discharge) / 100 FL = (GPM)sq / 5
GPM = 10 FL = (10)sq / 5 FL = 100 / 5 FL = 20 per 100 feet FL = (20)(6) FL = 120 PSI
Equation F:
Formula for 3 inch hose:
FL per 100 ft = (Q)sq
- (Q = GPM/100)
Equation G:
Formula for 4 inch hose:
FL per 100 ft = (Q)sq / 5
Equation A:
1) FL Formula in PSI is:
Must know “coefficient” # for:
Single Hose Lines:
2)- 1 3/4 with 1 1/2 inch couplings
3)- 2 1/2 inch hose
Siamesed Lines of Equal Length:
4) - Two 2 1/2 inch
5) - Two 3 inch 2 1/2 inch couplings
1) FL = (C)(GPM/100)sq(HL/100)
2) 15.5
3) 2
4) 0.5
5) 0.2
Equation B:
Formula for Elevation Pressure in feet:
EP = (0.5)(height in feet)
Equation C:
Formula for elevation pressure in a multistoried building:
EP = 5 PSI x (# of stories - 1)
Equation D:
Formula for Pump Discharge Pressure:
PDP = NP + TFL
TFL = FL + AP + EP
Nozzle Pressures:
1) Solid stream nozzle (handling) = ____ PSI
2) Soild stream nozzle (master stream) = _____ PSI
3) Standard fog nozzle = ____ PSI
4) Low pressure fog nozzle = ___ to ___ PSI
1) 50 PSI
2) 80 PSI
3) 100 PSI
4) 50 to 75 PSI
Equation I:
Formula to find Percent Drop:
%D= (Static - Residual)(100) / Static
0-10% Drop = 3 additional lines
11-15% Drop = 2 additional lines
16-25% Drop = 1 additional line
25% or more = 0 more lines of equal flow
A pumper is supplying one line with 250 GPM flowing. The static pressure was 60 PSI, and the residual pressure reading is 53 PSI. Determine how many more additional lines can be added:
PD = (Static - Residual)(100) / Static PD = (60-53)(100) / 60 PD = (7)(100) / 60 PD = 700 / 60 PD = ~ 12% - 2 additional lines
According to NFPA 1901, the apparatus must carry at least (1)_____ to be considered a mobile water supply apparatus. The weight distribution and load requirements generally limit tank capacity to (2)_____ for single rear axle vehicles; and tank capacities of (3)_____ tandem rear axles, tri-axles, or tractor-trailer design should be considered.
A. 1000 gallons. B. 1000 gallons or less. C. 1000 gallons or more. D. 1500 gallons. E. 1500 gallons or less. F. 1500 gallons or more.
1) A. 1000 gallons.
2) E. 1500 gallons or less.
3) F. 1500 gallons or more.
Types of Pressure: (6)
_____ pressure is greatest at low altitudes and least at very high altitudes. At sea level, the atmosphere exerts a pressure of 14.7 psi, which is considered standard _____ pressure.
A. Atmospheric pressure. B. Head pressure. C. Static pressure. D. Residual pressure. E. Normal operating pressure. F. Flow pressure.
A. Atmospheric pressure.
Types of Pressure: (6)
_____ pressure in the fire service refers to the height of a water supply over the discharge orifice.
A. Atmospheric pressure. B. Head pressure. C. Static pressure. D. Residual pressure. E. Normal operating pressure. F. Flow pressure.
B. Head pressure.
Exam question ^
Types of Pressure: (6)
The water flow definition of _____ pressure is stored potential energy available to force water through pipe, fittings, fire hose, and adapters. Means at rest or without motion.
A. Atmospheric pressure. B. Head pressure. C. Static pressure. D. Residual pressure. E. Normal operating pressure. F. Flow pressure.
C. Static pressure.
Types of Pressure: (6)
_____ pressure is that pressure found in a water distribution system during normal consumption demands.
A. Atmospheric pressure. B. Head pressure. C. Static pressure. D. Residual pressure. E. Normal operating pressure. F. Flow pressure.
E. Normal operating pressure.
Types of Pressure: (6)
_____ pressure is that part of the total available pressure not used to overcome friction loss or gravity while forcing water through pipe, fittings, fire hose, and adapters. Means a remainder or that which is left.
A. Atmospheric pressure. B. Head pressure. C. Static pressure. D. Residual pressure. E. Normal operating pressure. F. Flow pressure.
D. Residual pressure.
Types of Pressure: (6)
_____ pressure is that forward velocity pressure at a discharge opening while water is flowing. Because a stream of water emerging from a discharge opening is not encased within a tube, it exerts forward pressure but not lateral pressure. Can be measured by using a pitot tube and gauge.
A. Atmospheric pressure. B. Head pressure. C. Static pressure. D. Residual pressure. E. Normal operating pressure. F. Flow pressure.
F. Flow pressure.
Keep in mind that all fire department pumpers are rated to flow their maximum volume 100% at (1)_____ PSI, 70% of their maximum volume at (2)_____ PSI, and 50% of their maximum volume at (3)_____ PSI at draft.
1) 150 PSI (exam question)
2) 200 PSI
3) 250 PSI
What is the total pressure loss due to friction in 250 feet of 1 3/4 inch hose when 150 GPM is flowing?
FL = (C)(GPM/100)sq(HL/100) FL = (15.5)(1.5)sq(2.5) FL = (15.5)(2.25)(2.5) FL = ~ 87.2 PSI
A pumper is supplying 500 feet of 2 1/2 inch hose that is flowing 300 GPM through a fog stream nozzle. Determine the pump discharge pressure required to supply the hoseline.
FL = (C)(GPM/100)sq(HL/100)+NP FL = (2)(3)sq(5)+NP FL = (2)(9)(5)+100 FL = 190 PSI
All fire department pumpers should be capable of pumping water from a static water supply. The entire priming action typically requires 10 to 15 seconds from start to finish, but when using no more than 20 feet of hard intake hose lifting a maximum of 10 vertical feet, It should not take more than _____ seconds in pumps larger than 1,250 GPM.
A. 25 seconds.
B. 30 seconds.
C. 45 seconds.
D. 60 seconds.
C. 45 seconds. (in pumps larger than 1,250 GPM.)
*30 seconds in pumps smaller than 1,250 GPM
- A) In residential areas, the recommended size for fire hydrant supply mains is at least _____ inches in diameter. B) There should be ____ inch cross connecting mains at intervals of not more than 600 feet.
- In the business and industrial districts, the minimum recommended size is an ____ inch main with cross connecting mains every 600 feet.
- ____ inch mains may be used on principal streets and in long mains not crossed connected at frequent intervals.
- Water mains as large as ____ inches maybe found in major cities.
- A) 6 inches (exam question)
B) 8 inches / 600 ft - 8 inch / 600 ft
- 12 inches
- 48 inches
If 300 GPM is flowing from a nozzle, what is the total pressure loss due to friction for 400 feet of 2 1/2 inch hose?
FL = (C)(GPM/100)sq(HL/100) FL = (2)(3)sq(4) FL = 72 PSI
A hoseline operating on a ninth-floor structure fire is connected to a building standpipe system. What is the total pressure loss due to elevation?
9-1=8
8x5 = 40 PSI
The foam nozzle eductor operates on the same basic principle as the in-line eductor. The self-educting master stream foam nozzle is used where flows in excess of _____ GPM are required.
A. 250 GPM.
B. 350 GPM.
C. 500 GPM.
D. 1000 GPM.
B. 350 GPM.
Class B foams are mixed in proportions of 1% - 6%. Some multipurpose foams designed for use on both hydrocarbon and polar solvent fuels can be used at different concentrations, depending on the fuel they are used on. Concentrations of _____ are normally used on hydrocarbons depending on manufactures recommendations.
A. 1% - 3%.
B. 3% - 6%.
C. 1.5%, 2%, or 3%.
D. 6% or more.
A. 1% - 3%. (Hydrocarbon fuels) \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ B. 3% - 6%. (Polar solvent fuels) C. 1.5%, 2%, or 3%. (Typical % used for Class B Medium-expansion foams) D. 6% or more. (N/A)
* 3% Class B Medium expansion foam typically used for flammable or combustible liquids**
1) Statistics compiled annually by the NFPA historically show that ____ to ____% of all firefighter injuries and deaths in the US are caused by vehicle collisions while responding to returning from emergency calls.
2) The data translate into as many as ____ firefighter deaths per year caused by vehicle collisions and rollovers.
3) The data shows that collisions at _____ are by far the most frequent and most severe.
1) 20 - 25% (exam question)
2) 25 deaths per year
3) intersections
In general, fire apparatus collisions can be grouped into the following five basic causes. The following are TRUE… the exception is:
A. Improper backing of the apparatus.
B. Reckless driving by the operator.
C. Excessive speed by the fire apparatus driver/operator.
D. Lack of driving skill and experience by the fire apparatus driver-operator.
E. Poor apparatus design or maintenance.
B. Reckless driving by the “operator”. (FALSE - “public”)
In general, fire apparatus collisions can be grouped into five basic causes… The exception is:
A. Improper backing of the apparatus.
B. Excessive speed by the fire apparatus driver/operator.
C. Failure to obey posted traffic regulations or directions.
D. Lack of driving skill and experience by the fire apparatus driver/operator.
(^ exam question)
C. Failure to obey posted traffic regulations or directions.
^ would be an example of reckless driving by the public.
Sound defensive driving skills are one of the most important aspects of safe driving. Every driver/operator should be familiar with the basic concepts of defensive driving. They include it… The exception is:
A. Anticipating other drivers actions. B. Backing the fire apparatus when possible. C. Estimating visual lead time. D. Knowing breaking and reaction times. E. Combating skids. F. Knowing evasive tactics. G. Having knowledge of weight transfer.
B. Backing fire apparatus when possible.
Exam question with added defensive driving techniques as stated in p.76
- At speeds above _____ mph, and emergency vehicle may “out-run” the effective range of it’s audible warning device.
- A study conducted by the staff of Driver’s Reaction Course concluded that a siren operating on an emergency vehicle moving at 40 mph can project (A)____ feet in front of the vehicle. At a speed of 60 mph, however, the siren is only audible (B)____ feet or less in front of the vehicle.
Driver/operators must drive within the effective range of their audible warning devices.
- 50 mph (exam question)
- A) 300 feet
B) 12 feet
Extinguishing Properties of Water:
_____ heat - The ratio between the amount of heat needed to raise the temperature of a specified quantity of a material and the amount of heat needed to raise the temperature of an identical quantity of water by the same number of degrees (exam definition).
A measure of the heat-absorbing capacity of a substance (book definition p.136).
A. Latent Heat of Vaporization.
B. Specific gravity.
C. Specific heat.
D. Water (H2O).
C. Specific heat.
Extinguishing Properties of Water:
The _____ is the quantity of heat absorbed by a substance when it changes from a liquid to a vapor.
A. Latent Heat of Vaporization.
B. Specific gravity.
C. Specific heat.
D. Water (H2O).
A. Latent Heat of Vaporization.
Extinguishing Properties of Water:
Specific Heat and Latent Heat of Vaporization govern the heat-absorbing ability of _____ .
A. Latent Heat of Vaporization.
B. Specific gravity.
C. Specific heat.
D. Water (H2O).
D. Water (H2O).
____ is a compound of hydrogen and oxygen formed when two parts of hydrogen combined with one part of oxygen.
A. Latent Heat of Vaporization.
B. Specific gravity.
C. Specific heat.
D. Water (H2O).
D. Water (H2O).
Extinguishing Properties of Water:
_____ is the density of liquids in relation to water. Water is given a value of 1. Liquids with a _____ less than one are lighter than water and therefore float on water. Those with a _____ greater than one are heavier than water and sink to the bottom. If the other liquid also has a _____ of one, it mixes evenly with the water.
A. Latent Heat of Vaporization.
B. Specific gravity.
C. Specific heat.
D. Water (H2O).
B. Specific gravity.
1) Water exists in a liquid state between ____ and ____°F.
2) Below ____F, water converts to a solid matter called ice.
3) Above ____°F (the boiling point of water), it converts into a gas called water vapor or steam.
4) When converted to steam, water expands approximately ____ times its original volume.
5) One gallon of water weighs ____ pounds.
6) A pound of water requires approximately ____ BTU’s of heat to completely convert into steam.
1) 32°F to 212°F
2) 32°F
3) 212°F
4) 1,700 times
5) 8.33 pounds
6) 970 BTU’s
Amount of heat transfer is measured in:
1) A _____ is the amount of heat required to raise the temperature of 1 pound of water 1°F.
2) The ____ has taken the place of the calorie in the SI (International System of Units). 1 calorie = 4.19 ____ .
- BTU (British thermal unit)
2. Joule (1 cal = 4.19 joules)
In changing water to steam, the least true statement is:
A. Steam expansion is rapid. If the room is already filled with smoke and gases, the steam generated will displace the gases.
B. Water can smother fire when it floats on liquids that are heavier than water.
C. Water can smother fire by forming an emulsion over the surface of certain combustible liquids.
D. Water can also smother fire when it floats on liquids that are lighter than water.
D. Water can also smother fire when it floats on liquids that are lighter than water.
(Not a true statement)
_____ is the tendency of a liquid to possess an internal resistance to flow. For example, water has a low _____ , while molasses has high _____ .
A. Viscosity.
B. Velocity.
C. Friction loss.
D. Flow Pressure.
A. Viscosity.
Velocity - speed at which fluid travels.
The speed with which a fluid travels through hose or pipe is determined by the pressure upon that fluid. The speed at which this fluid travels is often referred to as _____ .
A. Viscosity.
B. Velocity.
C. Friction loss.
D. Flow Pressure.
B. Velocity.
A water supply in a tank is 200 feet above a hydrant. The pressure at the hydrant would be most nearly:
A. 50 PSI C. 70 PSI
B. 60 PSI D. 80 PSI
(Exam question)
Head Pressure = Feet / 2.304
Head Pressure = 200 / 2.3
Head Pressure = 86.9 PSI
Answer = ~ 80 PSI
(Exam question)
A water supply in a tank is 100 feet above a hydrant. The water source has a head pressure of ____ PSI.
(Book question, p144)
Head Pressure = Feet / 2.304
Head Pressure = 100 / 2.304
Head Pressure = 43.4 PSI
_____ is the # of feet that 1 PSI will raise a 1-sq inch column of water. (Used to find Head Pressure by dividing number of feet by this #)
Ex: Head Pressure = Feet / ____
A. 2.304
B. 62.5
C. 8.33
D. 14.7
A. 2.304 feet. \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ B. 62.5 lbs. = 1 cubic foot of water C. 8.33 lbs. = 1 gallon of water D. 14.7 psi. = Atmospheric pressure at sea level
Pressure in a water system before water flows from a hydrant is considered _____ pressure.
A. Head pressure. B. Nozzle pressure. C. Flow pressure. D. Static pressure. E. Residual pressure.
D. Static pressure.
A waterflow definition of _____ pressure is that forward velocity pressure at a discharge opening while water is flowing.
A. Head pressure. B. Nozzle pressure. C. Flow pressure. D. Static pressure. E. Residual pressure.
C. Flow pressure.
There are four basic principles that govern friction loss in fire hose and pipes… The exception is:
A. If all other conditions are the same, friction loss varies directly with the length of hose or pipe.
B. When hoses are the same size, friction loss varies approximately with the square of the increase in velocity of the flow.
C. For the same discharge, friction loss varies inversely as the fifth power of the diameter, of the hose.
D. For a given flow velocity, friction loss is governed by the pressure of the water.
D. For a given flow velocity friction loss is governed by the pressure of the water. (False statement)
Correct 4th Principle:
4th Principle - For a given flow velocity, friction loss is approximately the same, “regardless” of the pressure on the water.
A. = 1st Principle B. = 2nd Principle C. = 3rd Principle
Friction loss in a system will _____ as the length of hose/pipe increases.
A. Increase.
B. Decrease.
C. Stay the same.
D. Implode.
A. Increase.
It is important to remember that there are practical limits to the velocity or speed at which a stream can travel. If the velocity is increased beyond the limits, the friction loss becomes so great that the entire stream is agitated by resistance. This agitation caused by a degree of turbulence is called _____ . Beyond this point, it becomes necessary to parallel or Siamese hoselines to increase the flow and reduce friction.
A. Maximum velocity.
B. Critical velocity.
C. Crucial velocity.
D. Extreme velocity.
B. Critical velocity.
Water Distribution System:
A Grid System should consist of the following components:
- _____ feeders -Large pipes (mains), with relatively widespread spacing, that convey large quantities of water to various points of the system for local distribution to the smaller mains.
- _____ feeders - Network of intermediate sized pipes that reinforce the grid within the various loops of the primary feeder system and aid the concentration of the required fire flow at any point.
- _____ - Grid arrangement of smaller mains serving individual fire hydrants and blocks of consumers.
- Primary feeders
- Secondary feeders
- Distributors
Water Distribution System:
- A fire hydrant that receives water from only one direction is known as a _____ hydrant.
- When a fire hydrant receives water from two or more directions, it is said to have a _____ feed or a _____ line.
- A distribution system that provides circulating feed from several mains constitutes a _____ system. This system consists of primary feeders, secondary feeders, and distributors.
- Dead-end hydrant
- “Circulating feed” or “looped line”
- Grid system
Water System Capacity:
Average daily consumption is -
A. The average of the total amount of water used in a water distribution system over the period of one year.
B. The maximum total amount of water that was used during any 24-hour interval within a 3-year period.
C. The maximum amount of water used in any 1-hour interval over the course of a day.
A. The average of the total amount of water used in a water distribution system over the period of one year. (Average daily consumption)
________________________________
B. The maximum total amount of water that was used during any 24-hour interval within a 3-year period. (Maximum daily consumption)
C. The maximum amount of water used in any 1-hour interval over the course of a day. (Peak hourly consumption)
Water System Capacity:
- The _____ is normally about 1 1/2 times the average daily consumption.
- The _____ rate normally varies from 2 to 4 times the normal hourly rate.
A. Average daily consumption.
B. Maximum daily consumption.
C. Peak hourly consumption.
- B. Maximum daily consumption.
2. C. Peak hourly consumption.
What is the total pressure loss due to friction in 400 feet of 2 1/2 inch hose when 200 GPM is flowing:
FL = (C)(GPM/100)sq(HL/100) FL = (2)(200/100)sq(400/100) FL = (2)(2)sq(4) FL = (2)(4)(4) FL = 32 PSI
Friction loss can be caused by a number of factors: hose conditions, coupling conditions, or kinks. The “primary” determinant, however, is the:
A. Volume of water flowing per minute.
B. Elevation pressure.
C. Appliance pressure.
D. Nozzle pressure.
A. Volume of water flowing per minute. (GPM)
A hoseline operating on the 8th floor structural fire is connected to the buildings standpipe system. What is the total pressure loss due to elevation at the base of the Standpipe?
EP = 5 PSI x (Stories - 1) EP = 5 x (8-1) EP = 5 x 7 EP = 35 PSI
A structure located at the top of a 75 foot hill has a fire on the 4th floor. Determine the total loss of pressure due to elevation.
EP = (feet)(0.5) EP = 5(stories-1) EP = (75)(0.5) EP = (5)(3) EP = 32.5 PSI + EP = 15
EP = 47.5 PSI
(Exam answer is 52.5 PSI meaning the simply added the 4 stories as an additional 40 feet for equation)
Subbasement = ____ below ground
2 stories below ground
A fire is discovered in the subbasement of a structure. An arriving engine Company proceeds to the basement of the structure and connects 100 feet of 2 1/2 inch hose to the Standpipe outlet. Determine the total pressure loss due to friction and elevation pressure at the standpipe system fire department connection when 250 GPM is flowing. Disregard friction loss in the standpipe.
FL=(c)(GPM/100)sq(HL/100)+EP FL=(2)(250/100)sq(100/100)+EP FL=(2)(2.5)sq(1)+EP FL=(2)(6.25)(1)+EP FL= 12.5 + EP (5PSI per floor) FL = 12.5 + (-10) FL = 2.5 PSI
In most cases, fire departments have predetermined pressures that the driver/operator is expected to pump into the fire department connection (FDC) at the scene of a standpipe system. Treat the FDC like any other hose appliance. If the flow in the system exceeds 350 GPM, add ____PSI of friction loss for the FDC.
10 PSI
Using the hand method, what will be the total pressure loss due to friction when 300 GPM is being discharged from a nozzle that is attached to 200 feet of 2 1/2 inch hose?
Hand method p.258
T I M R P
2 3 4 5 6 7 8 9 10
100 200 300 400 500
150 250 350 450
Find the GPM finger then multiply the tip number by the first number of the GPM = PSI per 100 feet of hose