Not Content Based Questions - Any Topic

Question 1

Explain why the data in the table above are described as processed results.

Answer 1

Calculations have been made from raw data

Question 2

Describe how you would use a 1.0 mol dm−3 solution of sucrose to produce 30 cm3 of a 0.15 mol dm−3 solution of sucrose.

Answer 2

1. 0.15/1.0 x 30 = 4.5
2. 30-4.5 = 25.5
3. You take 4.5cm3 of the original 1.0 mol dm-3 solutions of sucrose
4. Add it to 25.5 cm3 of water
5. Makes 30 cm3 of a 15 mol dm-3 solution of sucrose

Question 3

Describe how you would use the student’s results in the table above to find the water potential of the potato tissue.

Answer 3

Plot a graph with concentration on the x-axis and percentage change in mass on the y-axis

2. Find concentration where curve crosses the x-axis / where percentage change is zero
3. Use (another) resource to find water potential of sucrose concentration (where curve crosses x-axis)