Mosby QA Flashcards

1
Q

The mathematical correction for the effect of temperature and pressure on ionization is based on a standardized barometric pressure of:

A

The correction is based on barometric pressure of 760 mm Hg.

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2
Q

Which of the following is true regarding beam filtration?

A

Beam filtration removes lower energy photons, making the beam “harder” due to an increased proportion of high-energy photons.

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3
Q

The rationale for using a half-beam block in a treatment field is based on:

A. the absence of beam divergence at the central axis
B. the reduction of scatter dose at the central axis
C. the increased accuracy of dose calculation at the central axis
D. the depth of Dmax increased due to the block
A

There is no beam divergence at the central axis. Thus, the half-beam block creates a sharp field edge with no divergence.

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4
Q

How many atoms are in one gram atomic weight of I-125?

A

The number of atoms in one gram atomic weight is given by Avogadro’s number (6.0228 x 1023). Dividing this number by the gram atomic weight of any element will give the number of atoms per gram atomic weight.

4.81 x 10^21 atoms

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5
Q

Which of the following radiation measuring devices is appropriate for verifying dose calculations in specific areas of a treated field?

A. ion chamber
B. film badge
C. pocket dosimeter
D. thermoluminescent dosimeter

A

thermoluminescent dosimeter (TLDs are most appropriate for verifying dose in tissue since the lithium fluoride crystals absorb radiation similar to tissue.)

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6
Q

If heavy charged particles have a quality factor (Q) of 20, what is the absorbed dose equivalent for 100 cGy?

A. 10 Sv
B. 2 Sv
C. 2000 Sv
D. 20 Sv

A

D. 20 Sv

1 sievert (Sv) is equal to 1 Gy. The absorbed dose equivalent is found by multiplying Q by the absorbed dose.

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7
Q

Light field and radiation field congruence should be checked:

A

According to AAPM Task Group 40, light field and radiation field congruence should be checked monthly.

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8
Q

The three basic principles that guide radiation protection are:

A

In order to keep exposures low, three basic principles should be followed: limit time, increase distance, and shield from exposure.

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9
Q

The room temperature is 21.5°C, and the barometric pressure is 745mmHg. Calculate the temperature and pressure correction.

A

A. 1.018

Formula needed Use the correction formula ((273.2+T)/295.2)) x (760/P).

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10
Q

Which theory of radiation interaction is illustrated by the operating principles of an ionization chamber?

A

Bragg-Gray cavity theory states that ionization in an air cavity can be related to ionization in a medium.

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11
Q

Which of the following should be checked on a linac daily?

A. light/radiation field coincidence
B. beam flatness and symmetry
C. field size indicators
D. none of the above

A

D. none of the above

All of the above parameters are to be checked monthly.

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12
Q

Which is not true of the electromagnetic spectrum? All photons in the spectrum have the same:

A. velocity
B. energy
C. mass
D. charge

A

B. energy

Notes: All photons in the spectrum have the same velocity, mass, and charge—none.

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13
Q

Which of the following best describes an isodose curve?

A. Points within the patient receiving the same dose are joined together forming a curve.
B. Points on the patient's skin surface receiving dose relative to Dmax are connected forming a curve.
C. Points within the patient receiving the same dose equidistant from the maximum dose point are joined together forming a curve.
D. none of the above
A

A. Points within the patient receiving the same dose are joined together forming a curve.

Notes: Several dose points of the same value are joined together forming a curve. The curve can be specified in either absolute dose or dose relative to the maximum dose in the treatment plan.

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14
Q

The probability of bremsstrahlung production:

A. decreases with atomic number
B. increases with atomic number
C. is independent of atomic number
D. decreases with the square of the atomic number

A

B. Increase with atomic number

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15
Q

Obliquely incident photon beams that “flash” over the patient surface such as in the treatment of a chestwall can result in:

A. increasing of the skin sparing effect
B. inaccurate dose delivery
C. neutron dose scatter to the patient
D. decrease of the skin-sparing effect

A

D. decrease of the skin-sparing effect

Notes: Obliquely incident photon beams that “flash” over the patient surface, such as in treating a chestwall, can shift the depth of Dmax closer to the skin surface, resulting in a reduction of the skin sparing effect.

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16
Q

Half-value layer (HVL) is equal to:

A. ln2/μ
B. 0.693/μ
C. a and b
D. none of the above

A

C. a and b

17
Q

Which of the forces of nature is the weakest?

A. strong nuclear force
B. gravitational force
C. electromagnetic force
D. weak nuclear force

A

B. gravitational force

18
Q

The annual dose limit for occupational exposure to the hands is ________annually.

A. 5 rem
B. 15 rem
C. 30 rem
D. 50 rem

A

D. 50 rem or 500 mSv

19
Q

Ionizing radiation can disrupt chemical_______in biological material.

A. balance
B. distribution
C. energy
D. bonds

A

D. Bonds

Notes: Ionizing radiation has the ability to break chemical bonds in living tissue.

20
Q

Which of the following is the definition of linear attenuation coefficient (μ)?

A. fraction of photons attenuated per unit density
B. fraction of photons attenuated per unit thickness
C. fraction of photons attenuated per unit mass
D. fraction of photons attenuated per unit absorbed dose

A

B. fraction of photons attenuated per unit thickness

Notes: The linear attenuation coefficient is dependent on the density of absorbing material and is the fraction of photons attenuated per unit thickness. It has a dimensionless unit of 1/cm.

21
Q

A joule is a unit of:

A. absorbed dose
B. charge
C. mass
D. energy

A

D. energy

Notes: The joule is a basic unit of energy.

22
Q

Which of the following isotopes are commonly used in low-dose rate brachytherapy for the treatment of prostate cancer?

A. Cs-137
B. Ir-192
C. I-125
D. I-131

A

C. I-125

Notes: Feedback Iodine 125 is commonly used in LDR brachytherapy for prostate cancer.

23
Q

Which of the following is true of Beta+ decay?

A. A proton is converted to a neutron.
B. A neutron is converted to a proton.
C. An electron is captured outside the nucleus and a neutron is converted to a proton.
D. It requires a transition energy of 0.511 MV.

A

A. A proton is converted to a neutron.

Notes: Beta+ decay occurs in nuclides that are neutron deficient. Thus the neutron/proton ratio is increased by converting a proton to a neutron and emitting excess energy in the form of a positron.

24
Q

As the wavelength of light is decreased, its speed is:

A. increased linearly
B. decreased linearly
C. unchanged
D. increased exponentially

A

C. Unchanged

Note:
See electromagnetic spectrum. The wavelength decreases but the speed remains the same.

25
Q

In a diagnostic X-ray tube, A/C is converted to D/C by means of:

A. A/D converter
B. rectification circuits
C. Step-up transformer
D. step-down transformer

A

B. rectification circuits

Notes: Rectification circuits (also known as diodes) restrict the flow of current to one direction. Therefore, current does not flow in the opposite direction when the polarity reverses, resulting in a single direction of current flow so that the electrons constantly move from the cathode to the anode.

26
Q

167 monitor units were calculated to deliver 100 cGy to a treatment field that included a wedge. After the first treatment, however, it was discovered that the wedge was omitted but 167 monitor units was still used. If the wedge factor was 0.752 and the TMR for the field was 0.796, what was the actual dose delivered to this field?

A. 126 cGy
B. 133 cGy
C. 167 cGy
D. 204 cGy

A

The dose delivered is calculated by MU x TMR x WF x 1cGy/MU. If there were other factors in addition to the TMR, WF, and linac output, then those would be multiplied as well. In this case the wedge was omitted. 167 x 0.796 = 132.9.

27
Q

How many joules are in 1 electron volt?

A. 1.6 x 10-13 J
B. 1.6 x 10-19 J
C. 1.6 x 1013 J
D. 1.6 x 1019 J

A

B. 1.6 x 10^-19 J

28
Q

The tolerance for variation in collimator rotation around the point of isocenter is:

A. 2 mm diameter
B. 3 mm diameter
C. 2 cm diameter
D. 1 cm diameter

A

A 2mm diameter

29
Q

The thickness of material needed to reduce the intensity of the beam to one half its initial value is known as the:

A. half-value layer
B. half-life
C. atomic number
D. electron density

A

A. half-value layer

Notes: A half-value layer is the thickness of material needed to reduce the intensity of the beam to one half its initial value.