Lecture 25 Flashcards

1
Q

Selective agents on Adh:

A
  • Alcohol
  • Temperature
  • Alcohol and temperature
  • Something else?
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2
Q

Clarke Protocol:

A
  1. Difference in molecular function must be reflected in fitness differences in postulated selective regime
  2. Natural populations must be re-examined to seek a comprehensive explanation for observed allele frequency distributions in space and time
  3. Test your hypothesis by perturbing (changing) allele frequencies in a natural population
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3
Q

Fitness in the presence of ethanol:

A
  • Population cages AdhF frequency increases to fixation when select with lower concentrations of ethanol
  • Mixed success
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4
Q

Fitness in the absence of ethanol:

A
  • Population cages frequencies converge on an intermediate frequency
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5
Q

Chateau Tahbilk Winery:

A
  • Populations of dros. in the cellar and outside are separate for most of the year
  • Once a year there is massive unidirectional gene flow from outside via the fermentation area in the cellar
  • This replenishes cellar population
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6
Q

What are the conditions in the Tahilk winery?

A
  • Range from 8 - 22 degrees
  • The population is temperature dependent, and stop breeding at 15 degrees
  • Most flies die over winter and there are tiny sub-populations on each vat
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7
Q

Evidence for natural selection:

A
  • Parallel clines over 5 continents of the S allele decreasing further away from the equator
  • Selection for the fast allele in low alcohol environments in cages, selection for a polymorphism even in the absence of alcohol
  • Lack of fluctuation in allele frequencies when population size crashes
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8
Q

Chateau Tahbilk Overview:

A
  • Returned to the pre-perturbation levels

- Returned at a rate which was proportional to temperature/ADH activity relationship

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9
Q

Perturbation Experiment 1:

A
  • Release a large population of flies into the cellar 1 with an increased frequency of Adh-F
  • Same thing done in cellar 2 with a decreased frequency of Adh-F
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10
Q

Balancing selection maintains F/S polymorphism:

A
  • Lack of noise in allele frequencies in face of potential for drift
  • Perturbation experiments
  • Parallel clines
  • Environmental heterogeneity
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11
Q

Problems with the conclusions drawn:

A

Unable to generate consistent fitness estimates for the three genotypes

  • Type of balancing selection unclear
  • Cannot define the selective agent
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12
Q

For other systems:

A
  • Parallel clines can be found
  • Selective agents are generally unidentified
  • Fitness differences between genotypes are extremely difficult to demonstrate
  • Detailed studies of inividual populations has not been done
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13
Q

Clarke approach:

A
  1. Choose gene

2. Attempt to find the selective agent

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14
Q

The reverse to the Clark approach may be more useful:

A
  1. Choose a selective agent which has an impact on viability eg) heat stress, insecticides, ethanol tolerance
  2. Identify gene(s) responsible for adaptation (mapping/DNA seq, candidate gene approach)
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15
Q

Benefits of using bacteria for studies:

A
  • Allozymic variation exists
  • Short generation time
  • Population size is near infinite (drift effects are minor)
  • Defined cultural medium, so the environment is controlled and manipulated
  • Different alleles can be introduces into an identical background using transduction
  • Haploid, no heterozygotes
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16
Q

Chemostat:

A
  • Volume of 30ml, this is a big population size
  • 600 generations
  • Strains with different alleles are competed pairwise
  • T5 bacteriophage resistance is used as a genetic marker
  • Nutrient medium enters at top, the same amount of bacteria drip out the bottom, allowing us to sample a population through time (lacz1 and lacz2)
17
Q

Growth rate = fitness:

In(pn/qn) = ln(po/q0)+n x Inw

A
  • Growth rate of two strains in chemostat is a measure of relative fitness: This formula is used to work out the relative fitness of two strains
  • po = initial proportion of strain A
  • qo = initial proportion of strain B
  • n = number of generations
  • pn = proportion of Strain A after n generations
    qn = proportion of strain B after n generations
  • w = w/1 = relative fitness of strain A (relative to strain B)
18
Q

Five pgi alleles were compared pairwise:

A
  • Activity of PGI allozymes differed when measured under chemostat conditions
  • pgi converts glucose-6-p to fructose-6-p and reverse
19
Q

Observations from pgi experiment:

A
  • within the limits of detection but no selection

- one allele promotes decreased growth with limiting factors

20
Q

Comparisons in fitness between different types of sugars:

A
  • Strains with different ‘natural’ lac operons were competed for lactose or one of three different B-galactosidase substrates which were not normally encountered
  • Very small fitness differences when the substrate was lactose
  • Very big fitness differences when different B-gal substrates were used.