lecture 2 - amino acids Flashcards
glycine (3 letter)
gly
glycine (1 letter)
G
gly
glycine
G
glycine
alanine (3 letter)
ala
alanine (1 letter)
A
ala
alanine
A
alanine
proline (3 letter)
pro
proline (1 letter)
P
pro
proline
P
proline
valine (3 letter)
val
valine (1 letter)
V
val
valine
V
valine
leucine (3 letter)
leu
leucine (1 letter)
L
leu
leucine
L
leucine
isoleucine (3 letter)
ile
isoleucine (1 letter)
I
ile
isoleucine
I
isoleucine
methionine (3 letter)
met
methionine (1 letter)
M
met
methionine
M
methionine
phenylalanine (3 letter)
phe
phenylalanine (1 letter)
F
phe
phenylalanine
F
phenylalanine
tyrosine (3 letter)
tyr
tyrosine (1 letter)
Y
tyr
tyrosine
Y
tyrosine
tryptophan (3 letter)
trp
tryptophan (1 letter)
W
trp
tryptophan
W
tryptophan
serine (3 letter)
ser
serine (1 letter)
S
ser
serine
S
serine
threonine (3 letter)
thr
theronine (1 letter)
T
thr
theronine
T
theronine
cystine (3 letter)
cys
cystine (1 letter)
C
Cys
cystine
C
cystine
asparagine (3 letter)
asn
asparagine (1 letter)
N
asn
asparagine
N
asparagine
glutamine (3 letter)
gln
glutamine (1 letter)
Q
gln
glutamine
Q
glutamine
lysine (3 letter)
lys
lysine (1 letter)
K
lys
lysine
K
lysine
histidine (3 letter)
his
histidine (1 letter)
H
his
histidine
H
histidine
arginine (3 letter)
arg
arginine (1 letter)
R
arg
arginine
R
arginine
asparate (3 letter)
asp
asparate (1 letter)
D
asp
asparate
D
asparate
glutamate (3 letter)
glu
glutamate (1 letter)
E
glu
glutamate
E
glutamate
non-polar, aliphatic
glycine, alanine, proline, valine, leucine, isoleucine, methionine
-glycine =predominantly in zwitterion (nh3 = +, coo = -)
polar, uncharged
serine, threonine, cystine, asparagine, glutamine
-can form Hbonds, both donors and acceptors
aromatic
phenylalanine, tyrosine, tryptophan
-tyr and trp have some hbonding ability
positively charged
lysine, arginine, histidine
- lys & arg = predominantly positively charged
- his can be pos or neutral (pkr=6), at ph=7 = 9% pos (protonated) and 91% neutral (deprotonated)
negatively charged
asparate, glutamate
-both predominantly negatively charged
isoelectric point:
pH where net charge = 0
pH < pI
positive charge bc excess protons in solution
pH > pI
negative charge because protonated
pH = pI
neutral
at pH = pKa
equal amounts of protonated and deprotonated
at pH = pKa + 1
91% deprotonated
at pH = pKa - 1
91% protonated