lecture 13 - mass spectrometry Flashcards

1
Q

why is mass spectrometry useful?

3

A

(1) measure total mass
(2) measure mass of proteolytic fragments (often identify protein by matching this to a database of known sequences)
(3) sequence short peptides

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2
Q

what is mass spectromoetry actually measuring as total mass?

A

mass/charge ratio (m/z)

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3
Q

how does measuring mass by mass spectrometry work?

A
  • charged sample is run through an electric feild
  • (charge sample by adding H+ - varries for each molecule)
  • detector collects time of arrival of ions to get m/z
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4
Q

we can transform relative intensity and m/z to:

A
  • intensity and mass

- can detect differences due to isotopes

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5
Q

what are the benefits to mass spectrometry? (3)

A

(1) very sensetive and accurate measure of mass
(2) can detect post-translational modifications - determines changes in mass compared to protein sequence alone
(3) can count # of disulphide bonds - compare oxidized mass to that of reduced and blocked protein

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6
Q

how do we sequence proteolytic peptides?

A
  • using tandem MS (MS/MS)

- 2 linked MS’s

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7
Q

summarize how tandem MS works

A
  • start w pure protein
  • digest protein with proteases (e.g. trypsin for tryptic polypeptides)
  • analyze peptides with MS/MS
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8
Q

why is Tandem MS useful?

A

no need to purify or separate peptides

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9
Q

what are the parts of Tandem MS?

A
  • proteolytic mix travel through:
  • MS1
  • collision cell
  • MS2
  • to detector
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10
Q

what does MS1 do?

A

selects one peptide (one m/z)

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11
Q

what does the collision cell do?

A
  • collisions with the selected peptide result in fragmentation at certain bonds (moslty @ peptide bonds)
  • typically one peptide bond is broken per peptide molecule
  • this creates a mixture of all possible fragments
  • not hydrolysis ** no addition of h2o
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12
Q

what does MS2 do?

A
  • analyzes fragments

- gives m/z (masses)

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13
Q

example question: R1 R2 R3 R4 peptide undergoes collisions, what is the result?

A

R1 | R2 R3 R4
R1 R2 | R3 R4
R1 R2 R3 | R4
R1 R2 R3 R4

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14
Q

example question: Phe Pro Ser Ala Arg

Arg = 172 Da
Ala Arg = 243 Da
Ser Ala Arg = 330 Da
Pro Ser Ala Arg = 427 Da
Phe Pro Ser Ala Arg = 574 Da 

each individual protein in Da?

A
Ala = 71 Da
Ser = 87 Da 
Pro = 97
Phe = 147

Note: these differences are the residue mass (amino acid mass -18 Da)
Note: C-term res has OH added to residue mass

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15
Q

What amino acids cannot be distinguished by MS/MS?

Why?

A
  • Leu & Ile

- identical masses

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