GEOMETRIC ISOMERS AND MAJOR MINOR CODES

Question 1

markovnikov’s rule

Answer 1

there are 2 products because…

1. the reagent is asymmetric and the alkene is asymmetric due to the position of the double bond.
2. there are 2 carbons forming a double bond that the H and the X can bond to so that there are 2 possible combinations.
3. the carbon with the most hydrogens will gain more hydrogens
4. therefore blah is the major product since the carbon at the end has 2 carbons and the middle carbon only has 1 hydrogen. therefore the H will preferentially bond to the end carbon
5. blah will be the minor product.