Differentation more techniques Flashcards

1
Q

What is the derative of f(x) = In(x)

A

1/x

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2
Q

What does the power law tells us for logs?

A
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3
Q
A
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4
Q

What yet dont we know how to differentatie?

A

In(x+k)

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5
Q

How can we use the change of base formula to find the derative of this function?

A
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6
Q

So what is the derative of this function again?

A
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7
Q
A
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8
Q

What is the derative of e^x? ( providing the base is an expoentital constant?

A

e^x

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9
Q

If we have a function where the base is not an expotential constant, when what do we do?

A

1) we take logs on both side ( when a doesnt equal 1)
2) then use power rule
3) we use that the our rules of logs ( logs

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10
Q

What functions can we not differentantiate without combination rules?

A
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11
Q

What are the 3 ways of combining functions other than what we saw in week 5?

A
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12
Q

What is the product rule?

A

f’g+fg’

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13
Q
A
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14
Q
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15
Q
A
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16
Q
A
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17
Q

What is the quotient rule?

A

The exact same line as product rule but divide by g(x) squared

18
Q
A
19
Q
A
20
Q
A
21
Q

When do we use the chain rule?

A

when differentiating a ‘function of a function’, like f(g(x)) in general.

22
Q

What is the formula for the chain rule?

A
23
Q
A

an alternative method is use power rule so

move the 2 down to get 2(x+1) times derative in the bracket which is 1

24
Q
A

alternatively you could do:

use power rule to get 3(2x+1)^2 X the derative in the bracket 2 to get 6(2x+1)^2

25
Q
A
26
Q

Why couldnt we differentiate these functions previously??

A

because they were a funciton of a function, but now we can using the chain rule.

27
Q

Differentatite using the chain rule these functions?

A

alternative for e^kx

i know that quickly i can got e^kx X the deraitve of the power which is k as k is a constant.

same for the last function, i can do these quickly

28
Q

Differentatie this, this is a rule i need to learn

A
29
Q

How would i find the derative of this difficult function?

A

I would use the product rule but within using product rule i have to use chain rule

30
Q
A

We are going to use the product rule but the chain rule within

31
Q

Whats the derative of 2e^x?

A

2e^x

32
Q
A

f(g) = 3/(this means sqaure root g) =gx^1/3

f’(g) = 1/3g^-1/3

g(x) = 2x-1

g’(x) = 2

f’(g) x g’(x) = 2/3(2x-1)^2/3

33
Q

How can we solve this using power rules instead of chain rule?

A
  • 1(x^4+3)^-2
  • 1(x^4+3)^-2 X 4x^3
  • 4x^3(x^4+3)^-2

then turn this into a fraction easy

34
Q
A

TBA

35
Q
A
36
Q
A

use chain rule and you should get 1

37
Q
A
38
Q

VERY HARD

A

1) Y = x^x
2) Take the natural log of both sides

InY = Inx^x( we can take expotent and move to the front)

InY = xInx

3) differentiate both sisdes with respect to x

1/y x dy/dx = ( On the RHS we use product rule) ( 1 In(x) + x times 1/x )

next step mutlple both sides by y

39
Q
A
40
Q
A