Depreciation Questions Straight Line – With Salvage Flashcards

1
Q
  1. Diggers Inc. bought a new backhoe for $100,000. After 5 years, the salvage value was $10,000. How much was depreciated each year? Assume straight line depreciation.

A. $10,000
B. $12,000
C. $18,000
D. $20,000

A
  1. C
    (Cost Basis/Purchase Price – Salvage value = Depreciable total)
    100,000 -10,000 = 90,000
    (Depreciable total ÷ years of depreciation = depreciation per year)
    90,000 ÷ 5 = 18,000
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2
Q
  1. ABC Paints bought a new truck for $25,000. After 5 years, the salvage value was $5,000. How much was total depreciation in years 2 and 3? Assume straight line depreciation.

A. $2,000
B. $8,000
C. $9,200
D. $10,250

A
  1. B
    (Cost Basis/Purchase Price – Salvage value = Depreciable total)
    25,000 -5,000 = 20,000
    (Depreciable total ÷ years of depreciation = depreciation per year) 20,000 ÷ 5 = 4,000
    4,000 x 2 = 8,000 (Years 2 and 3, totaled)
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3
Q
  1. Joe’s Landscaping bought a new truck for $65,000. After 5 years, the salvage value was $5,000. What was the total depreciation? Assume straight line depreciation.

A. $60,000
B. $62,000
C. $72,000
D. $76,000

A
  1. A (Cost Basis/Purchase Price – Salvage value = Depreciable total)
    65,000 -5,000 = 60,000
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4
Q
  1. Super Builders, LLC bought a new crane for $350,000. After 7 years, the salvage value was $30,000. How much was depreciated each year? Assume straight line depreciation.

A. $42,890
B. $45,714
C. $46,209
D. $46,248

A
  1. B
    (Cost Basis/Purchase Price – Salvage value = Depreciable total)
    350,000 - 30,000 = 320,000
    (Depreciable total ÷ years of depreciation = depreciation per year)
    320,000 ÷ 7 = 45,714
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5
Q
  1. Cloud Airlines bought a new airplane for $520,000. After 10 years, the salvage value was $100,000. What was the total amount depreciated in years 1 and 2? Assume straight line depreciation.

A. $84,000
B. $144,000
C. $168,000
D. $198,000

A
  1. A
    (Cost Basis/Purchase Price – Salvage value = Depreciable total)
    520,000 – 100,000 = 420,000
    (Depreciable total ÷ years of depreciation = depreciation per year) 520,000 is Cost Basis or
    Purchase Price or Depreciable Total 420,000 ÷ 10 = 42,000
    42,000 x 2 = 84,000 (Years 1 and 2, totaled)
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6
Q
  1. Blackbeard Salvage bought a new boat for $212,000. After 7 years, the salvage value was $14,000. How much was depreciated in year 1? Assume straight line depreciation.

A. $19,400
B. $22,080
C. $27,560
D. $28,286

A
  1. D
    (Cost Basis/Purchase Price – Salvage value = Depreciable total)
    212,000 - 14,000 = 198,000
    (Depreciable total ÷ years of depreciation = depreciation per year)
    198,000 ÷ 7 = 28,286
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7
Q
  1. Deadwood Lumber bought a new truck for 94,000. After 5 years, the salvage value was $12,000. How much was depreciated each year? Assume straight line depreciation.

A. $16,000
B. $16,400
C. $17,000
D. $18,600

A
  1. B
    (Cost Basis/Purchase Price – Salvage value = Depreciable total)
    94,000 - 12,000 = 82,000
    (Depreciable total ÷ years of depreciation = depreciation per year)
    82,000 ÷ 5 = 16,400
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8
Q
  1. Northern Snowtown bought a new snow maker for $108,000. After 5 years, the salvage value was $5,000. How much was depreciated in year 5? Assume straight line depreciation.

A. $20,600
B. $21,400
C. $22,010
D. $28,200

A
  1. A
    (Cost Basis/Purchase Price – Salvage value = Depreciable total)
    108,000 - 5,000 = 103,000
    (Depreciable total ÷ years of depreciation = depreciation per year)
    103,000 ÷ 5 = 20,600
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9
Q
  1. Yellow Inc. bought a new school bus for $180,000. After 5 years, the salvage value was $20,000. How much was depreciated in total for all years? Assume straight line depreciation.

A. $150,000
B. $160,000
C. $170,000
D. $180,000

A
  1. B (Cost Basis/Purchase Price – Salvage value = Depreciable total)
    Answer B: 180,000 - 20,000 = 160,000
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10
Q
  1. Private Orbits Inc. bought a new rocket for $4,000,000. After 5 years, the salvage value was $400,000. How much was depreciated each year? Assume straight line depreciation.

A. $720,000
B. $800,000
C. $980,000
D. $1,000,000

A
  1. A
    (Cost Basis/Purchase Price – Salvage value = Depreciable total)
    4,000,000 - 400,000 = 3,600,000
    (Depreciable total ÷ years of depreciation = depreciation per year)
    3,600,000 ÷ 5 = 720,000
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