Cycle 2 - Molecular Evolution Flashcards

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1
Q

Compare the GlsA gene in volvox vs. chlamy

A
  • GslA in chlamy is very similar to the volvox gslA gene
  • When the gslA is knocked out in chlamy, nothing happens, but in volvox, the cell dies –> it is essential for asymmetric cell division
  • When the chlamy gene is extracted and put in volvox, it work well
  • Bioinformatics (blast) is used to confirm the idea that the gene originated from a common ancestor
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2
Q

Differences between global versus local sequences

A

Two types of algorithms are used by the computer

  1. Global: matches all sequences to form global alignment (attempts to align end to end)
    • Computationally more demanding, therefore slower
  2. Local: the computer uses small, local regions of matching (builds alignment out from local matches)
    • Still end up with a complete alignment
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3
Q

Distinguish between the BLAST score and the E-value

A
  • BLAST gives you the probability that the two proteins are similar purely by chance.
  • E value is how likely they are to be homologous
  • E < 0.00001 = homologous
  • E value for volvox and chlamy GslA gene = 0; they are related
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4
Q

Define synonymous vs nonsynonymous mutations

A
  • Synonymous mutations are point mutations that, like a synonym in grammar, still have the same meaning as the original codon and therefore does not change the amino acid
  • Non-synonymous mutations affect the amino acids that are coded for and change the resulting protein that is expressed
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5
Q

Describe neutral theory and selection theory

A
  • Selection theory: all mutations affect fitness, and most mutations cause bad things
  • Neutral theory: many changes to the gene sequence have no affect (gene evolution without any natural selection)
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6
Q

State the relationship between frequency of amino acid substitutions in given proteins vs. time since common ancestor (molecular clock)

A
  • If the neutral theory is correct, then the number of mutations acquired should be clocklike; i.e., they just enter the population at a constant rate.
  • So, the number of mutations (differences from common ancestor) would be proportional to the number of time since the species last diverged
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7
Q

Relative rates of accumulation of synonymous vs. non-synonymous mutations: why the difference?

A

Synonymous mutations have a higher rate because they are neutral, so they are always passed on and eventually become fixed in the population

Non-synonymous mutations have a lower rate because they are on average harmful, and so are less likely to be passed on due to lowering fitness

Exception: any type mutation in introns and pseudogenes has a high rate of accumulation because it can never affect the phenotype regardless

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8
Q

State the variables that affect the rate of evolution for a particular protein

A
  • Rates of evolution differ for proteins due to selection pressures
    • Ex., cytochrome C is very important, we don’t want a lot of mutations in this area
    • Thus, cytochrome C is more constrained in tis structure because mutations in this area are likely to be severely negative due to its critical function for respiration
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9
Q

Define contigency and convergence evolution

A
  • Contingency (Gould) states that each step in evolution is dependent on the step before it
  • Convergence (Morris) states that the evolutionary routes are many, but the destinations are limited.
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10
Q

Describe the two types of opsin

A

Type 1: ex., channelrhodopsin, homologous to bacterial opsin

Type 2: rhodopsin, functions in sight and smell as well (called GPCR G-protein coupled receptors)

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11
Q

State the characteristics of ruminant organisms that enable them to extract energy from cellulose

A
  • Ruminant organisms: mammals that are able to acquire energy from cellulose
  • They have lysozyme enzyme which functions to digest grass/cellulose
  • They have a rumen: section of the stomach where fermentation occurs
  • The rumen consist of microbes which release the cellulase
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12
Q

Distinguish between digestive lysozyme and non-digestive lysozyme.

A
  • Digestive lysozyme is more pH resistant than non-digestive forms, due to having amino acids at specific residues that are capable of protecting against degradation.
  • It can exist in the stomach
  • Non-digestive forms unfold at low urea/extreme pH
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