Cycle 12: Molecular Evolution Flashcards

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1
Q

State the characteristics of model systems that can be used for experimental evolution

A
  • Organisms that have a small generation time and can have their ancestors frozen/viewed in some way are good model systems
  • These include viruses, bacteria, chlamydomonas, drosophila, yeast
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2
Q

Describe how the relative fitness of E. coli can be measured

A
  1. Split a culture of bacteria into two
    • One we label with a neutral gene that turns the cells red which we call the evolved culture, and the other one is left blank
  2. Subject the evolved culture to a condition (ex., low pH for 2000 generations)
    • Allow them to replicate
    • Then we mix them and allow them to grow for a short time at low pH
  3. Calculate w = relative fitness = the growth rat of the evolved strain / the growth rate of the ancestral strain
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3
Q

Assess what it means for W to be <,> or = to 1

A
  • If w > 1, suggests adaptation has taken place
  • If w = 1, then there is no adaptation taking place
  • If w < 1, this suggests maladaptation
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4
Q

Describe the design of Lenski’s long term evolutionary experiment (LEE) with E. coli

A
  • Lenski grows 12 large, identical populations of E. coli and seeks to observe spontaneous mutations that occur from asexual recombination
  • Every we day we take an aliquot of each population and put it into fresh medium
    • The medium contains reduced glucose as well as Fe-citrate (to main aqueous state of iron)
  • Every 75 days we take an aliquot of each population and freeze them to allow us to go “back in time” and look at the ancestral populations later
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5
Q

Where does citrate enter metabolism?

A
  • Present in the citric acid cycle
  • Acetyl-CoA can combine with oxaloacetate to produce citrate, or citrate can be directly taken up
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6
Q

Describe the role of glucose limitation in the experiment and the effects on the role of citrate

A
  • Glucose resources run out after about 8 hours of growth, stopping growth
  • Citrate can only be taken up in E. coli under anaerobic conditions, which are non-existent in the lab
  • Gives rise to an ecological opportunity! If a cell line could access the citrate under aerobic conditions, it would enable growth only until it runs out of citrate!
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7
Q

What is the Cit+ phenotype…that is what did the researchers detect that was different in the Ara-3 line?

A
  • Cit+ phenotype enables cells to grow on citrate under aerobic conditions, giving them a growth advantage once glucose resources run out
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8
Q

Describe the actualisation mutation that occured

A
  • In a normal Cit- population, the citrate gene exists under an operon whose promoter is repressed in the presence of oxygen
  • In the Cit+ population, actualisation occurred: part of the citrate operon was duplicated and inserted further down the gene, in front of a constitutive promoter!
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9
Q

Describe the refinement process of the Cit+ phenotype

A
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10
Q

What is meant by the term potentiation and what is the evidence that a potentiation event occurred after 20,000 generations?

A
  • Contingency believes that each step in evolution is dependent on all the steps before it
    • This mutation 1 is called a potentiation mutation: a silent mutation that has no effect on the phenotype but enables mutation 2 (actualisation) to occur
  • It was observed that a potentiation event occurred at the 20,000 mark
    • Species removed from freezing at the 10,000 mark never developed Cit+, but species thawed after the 20,000 mark did!
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11
Q

Is the Ara-3 line a new species?

A

By definition, E. coli can’t grow on citrate aerobically, so some argue that this is a new species

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12
Q

Explain why Cit+ lines do not drive Cit- lines to extinction

A

Cit+ lines do not drive Cit- lines to extinction because Cit- lines are more effective at using glucose while supplies last, so it is not completely unfavoured

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13
Q

What is trichromatic vision?

A
  • Three different types of rhodopsin
  • SW, MW, LW
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14
Q

What accounts for the differences in absorption characteristics of the different rhodopsins?

A
  • The pigment retinal remains the same in each cone cell, but the protein (opsin) varies slightly
  • Each type of opsin is folded slightly differently, and so absorbs slightly different wavelengths by straining the structure of the retinal
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15
Q

Describe the major similarities and differences as revealed in protein alignment of SW, MW and LW opsins

A
  • MW and LW opsins are found on the X chromosome (likely originated by duplication) while SW is on chromosome 7 (likely originated via translocation)
  • Have the same counterion glutamic acid and same retinal binding sequence lysine
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16
Q

Describe the importance of lysine at position 296 and glutamic acid at position 113 of opsins

A
  • Highly conserved amino acids in the different types of opsins
  • Lysine at position 296 binds to retinal
  • Glutamic acid at position 113 stabilises the interaction between lysine and retinal (it is a counterion)
17
Q

Describe the association between trichromacy, dichromacy, old world monkeys and new world monkeys

A
  • Old world monkeys are found in Africa and Asia and are trichromats
    • Originally started as dichromats, evolved to be trichromats
  • New world monkeys are dichromats found in South America
    • Separation arose from the splitting of Pangea 50 mya
18
Q

State the general distribution of di vs. tri vs. tetrachromacy among vertebrates

A
  • Dichromats: dogs, goats, new world
  • Trichromats: humans, old world
  • Tetrachromats: reptiles, birds, dinosaurs, common ancestor of vertebrates
19
Q

Mechanisms to explain how and why, over evolutionary time, lineages may lose and regain opsin

A
  • Dichromacy is advantageous if you need to break camouflage or if you have a nocturnal lifestyle where colour vision isn’t necessary
    • Ex., early mammals, where 2 opsins are lost
  • Trichromacy is advantageous if you need to determine ripeness of food
  • in genes
    • Ex., old world monkeys, where 1 opsin is gained back
  • Thus, complexity is not always better
20
Q

State the mechanism to explain why some new world monkey females have better colour discrimination than any males

A

Females have 2X chromosomes, so 2 alleles making slightly different opsins that strain retinal in different ways to absorb different wavelengths, therefore better colour discrimination