colours for transition elements Flashcards
ligand substitution reactions for adding NH₃ to Cu²⁺ (in water)
first precipitation reaction, then ligand substitution with excess NH₃
- [Cu (H₂O)₆ ] ₍ₐ₎+ 2NH₃ ₍ₐ₎ –> [Cu (OH)₂ (H₂O)₄ ] ₍ₛ₎ +2NH₄⁺₍ₐ₎
- pale blue solution to pale blue precipitate (initially)
- [Cu (H₂O)₆ ] ₍ₐ₎ + 4NH₃ ₍ₐ₎ –> [Cu (NH₃)₄ (H₂O)₂ ] ²⁺₍ₐ₎ + 4H₂O₍ₗ₎
- pale blue solution to dark blue solution
ligand substitution reactions for adding HCl to Cu²⁺ (in water)
- [Cu (H₂O)₆ ] + 4Cl⁻ –> [CuCl₄]²⁻ + 6H₂O
- pale blue solution to yellow solution
ligand substitution reactions for adding with NH₃ with Cr³⁺
first precipitation reaction, then ligand substitution with excess NH₃
- [Cr (H₂O)₆ ] ³⁺ + 3NH₃ –> [Cr (H₂O)₃ (OH)₃ ] + 3NH₄⁺
- violet solution to grey precipitate
- [Cr (H₂O)₆ ] ³⁺ + 6NH₃ –> [Cr (NH₃) ₆ ] ³⁺ + 6H₂O
- violet solution to purple solution
precipitation reaction with NaOH/NH₃
Cu²⁺
- Cu²⁺ + 2OH⁻ –> Cu (OH)₂
- blue solution to blue precipitate
- Cu also reacts with excess NH₃ (ligand substitution reaction)
precipitation reaction with NaOH/NH₃
Fe²⁺
- Fe²⁺ + 2OH⁻ –> Fe (OH) ₂
- pale green solution to green precipitate
precipitation reaction with NaOH/NH₃
Fe³⁺
- Fe³⁺ + 3OH⁻ –> Fe (OH)₃
- yellow solution to orange precipitate
precipitation reaction with NaOH/NH₃
Mn²⁺
- Mn²⁺ + 2OH⁻ –> Mn (OH) ₂
- pale pink solution to pale brown solution
precipitation reaction with NaOH/NH₃
Cr³⁺
- Cr³⁺ + 3OH⁻ –> Cr (OH)₃
- violet solution to grey precipitate
- Cr reacts with excess NH₃ in a ligan substitution reaction
oxidation of Fe²⁺/Fe³⁺ and reduction of MnO₄⁻/Mn²⁺
form overall equation and state colour changes
- 5Fe²⁺ + MnO₄⁻ + 8H⁺ –> Mn²⁺ + 5Fe³⁺ + 4H₂O
- purple solution to colourless solution (Mn)
oxidation of I⁻/I₂ and reduction of Fe³⁺/Fe²⁺
form overall equation and state colour changes
- 2Fe³⁺ + 2I⁻ –> 2Fe²⁺ + I₂
- orange solution to pale green solution (Fe) and I₂ is brown
oxidation of Zn/Zn²⁺ and reduction of Cr₂O₇²⁻/Cr³⁺
form overall equation and state colour changes
explain what happens when excess Zn added
- 3Zn + Cr₂O₇²⁻ + 14H⁺ –> 3Zn²⁺ + 2Cr³⁺ + 7H₂O
- orange solution to green solution (Cr)
- when excess Zn is added, Cr³⁺ ions are reduced further to Cr²⁺
Zn + 2Cr³⁺ –> Zn²⁺ + 2Cr²⁺
green solution to blue solution (Cr)
write an equation for the reaction of Cu²⁺ with I⁻
state colour changes associated with this reaction
- 2Cu²⁺ + 4I⁻ –> 2CuI + I₂
- pale blue solution to white precipitate (Cu) and I₂ is brown