CL 12- alkanes Flashcards

1
Q

saturated

definition

A

single C-C bonds only

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2
Q

sigma bond

formation and rotation

A

formed by the direct overlap of two orbitals
can rotate freely

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3
Q

explain the tetrahedral shape + bond angle around each C atom in alkanes

A
  • each C bonded to 4 other atoms
  • 4 bonded pairs of electrons around carbon, which repel each other
  • bond angle of 109.5°
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4
Q

explain the variations in boiling points of alkanes with increased C chain length

A
  • boiling point increases
  • more electrons and therefore stronger london forces
  • which require more energy to overcome
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5
Q

explain the variations in boiling points of alkanes with increased branching

A
  • boiling point decreases
  • fewer points of contact between branched molecules compared to straight chains
  • which leads to weaker london forces which require less energy to overcome
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6
Q

why are alkanes unreactive

2 reasons

A
  1. saturated
  2. non-polar
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7
Q

complete combustion of propane

A

C₃H₈ + 5O₂ –> 3CO₂ + 4H₂O

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8
Q

incomplete combustion of propane

A

C₃H₈ + 3.5O₂ –> 3CO + 4H₂O

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9
Q

C₂H₆ + Br₂ –> C₂H₅Br +HBr
what are the three steps called for this mechanism?

A
  1. initiation
  2. propagation
  3. termination
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10
Q

C₂H₆ + Br₂ –> C₂H₅Br +HBr
what is the name of this mechanism?

A

free radical substitution

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11
Q

C₂H₆ + Br₂ –> C₂H₅Br +HBr
what are the conditions required for this mechanism?

A

UV light

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12
Q

C₂H₆ + Br₂ –> C₂H₅Br +HBr
what would the initiation step be for this mechanism?

A

Br₂ –> 2Br.

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13
Q

C₂H₆ + Br₂ –> C₂H₅Br +HBr
what would the propagation steps be for this mechanism?

A

C₂H₆ + Br. –> .C₂H₅ +HBr
.C₂H₅ + Br₂ –> C₂H₅Br + Br.

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14
Q

C₂H₆ + Br₂ –> C₂H₅Br +HBr
what would the three termination steps be for this mechanism?

A
  1. 2.C₂H₅ –> C₄H₁₀
  2. 2Br. –> Br₂
  3. Br. + .C₂H₅ –> C₂H₅Br
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15
Q

limitations of radical substitution in synthesis

A
  • not a good way to synthesise a haloalkane as the yield of the product is low, due to additional products formed from termination steps
  • substitution of the halogen can occur anywhere along the alkane chain, forming lots of different isomers
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