Chapter 9: Semiconductors Flashcards

You may prefer our related Brainscape-certified flashcards:
1
Q

Semiconductors Basics

(3 points)

A
  • Conductivity highly dependent on T,E,B
  • Metallic or insulator like properties
  • Filled valence band, so technically an insulator
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

Semiconductor Classification

(4 points)

A
  • Intrinsic semiconductors are “naturally” occurring and have low conductivity
  • Extrinsic semiconductors are doped intrinsic semiconductors
  • A direct semiconductor has the minimum of the conduction and the maximum of the valence band at same k
  • An indirect semiconductor has the minimum of the conduction band and the maximum of the valence band at different k
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

Temperature Dependence of Band Gap

(5 points)

A
  • As temperature increases, band gap decreases
    • Because interatomic spacing increases with temperature, so potential felt by electron decreases
  • Described by Varhsni Equation (see below)
    • Parabolic at low T
    • Linear at high T
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

Temperature Dependence of Band Gap

(Graph)

A
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

Optical Absorption in Semiconductors

(4 points)

A
  • Photon delivers only energy
    • Optically transparent for (h-bar)ω < Eg
  • Phonon delivers momentum
    • Required for indirect band gap
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

Doped Semiconductors

(7 points)

A
  • Types:
    • Donor: Impurity that adds electron to conduction band
    • Acceptor: Impurity that adds hole to valence band
  • Binding energy can be estimated with Bohr model (meV
  • Classification:
    • Doped with more donors → n-type
    • Doped with more acceptors → p-type
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

Temperature Dependence of Chemical Potential

(Regimes: 4 points)

A
  1. Compensation Regime
  2. Impurity Reserve Regime
  3. Saturtion of Impurities
  4. Intrinsic Regime
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

Compensation Regime

(5 points)

A
  • kBT <<< Ed
    • ​Donors not ionized
  • For T → 0, then µ = Ed
  • As T increases, electrons excited into conduction band, because acceptors are saturated
  • µ shifts towards Ec and nC increases exponentially (−Ed/kBT)
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

Impurity Reserve Regime

(3 points)

A
  • kBT ≪ Ed
  • Donors start to contribute to conduction band, but not all
  • µ approximately in the middle of Ed and Ec
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

Saturation of Impurities

(3 points)

A
  • kBT ≥ Ed
  • Temperature ionizes all donors, but still too small to excited a large enough number of VB electrons
  • µ moves with increasing T towards middle of band gap
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

Intrinsic Regime

(3 points)

A
  • kBT >> Ed
  • VB excitations become important
  • µ moves to middle of band gap
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

pn-Junction in Thermal Equilibrium

(Before Contact: 2 points)

A
  • µn < Ed (n-type)
  • µp > Ea (p-type)
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

pn-Junction in Thermal Equilibrium

(After Contact: 5 points)

A
  • µn = µp
  • Diffusion of electrons in p-side (or holes into n-side)
  • Creates space charge separation
  • Creates electric field
  • Induces drift current in opposition to diffusion current
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

Schottky Approximation

(3 points)

A
  • Space charge approximated as step-functions
  • Electric field determined from E ∝ \int ρ dx
  • Potential determined from V ∝ − \int E dl
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

pn-Junction Under Forward Bias

(4 points)

A
  • Bands “squished” together (∆E = e(Vo − Vapp))
  • Electron Fermi energy raises
  • Induced electric field diminishes → Drift current weaker → diffusion current dominates
  • IV characteristic: forward bias region (below)
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

pn-Junction Under Reverse Bias

(4 points)

A
  • Band separated (∆E = e(Vo − (−Vapp)))
  • Electron Fermi energy lowered
  • Potential barrier becomes thin → Tunneling occurs → ”leakage current” (Reverse bias region below)
  • If reverse bias becomes to high, breakdown occurs (Reverse breadown region below)