Chapter 3- Amount of substance Flashcards

1
Q

what is 1 mole

A

The amount of substance that contains 6.02 * 10^23 particles.

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2
Q

What is the Avogadro’s constant

A

N a-

It is 6.02 * 10 ^23 mol-1, the number of particles in each mole of carbon-12

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3
Q

Why is carbon used?

A

Carbon-12 is the standard for the measurement of relative atomic masses. 12g of carbon-12 contains 6.02 * 10 ^23 atoms. Therefore, the mass of one mole of atoms of any element is its relative atomic mass in grams.

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4
Q

What is the molar mass

A

The mass in grams in each mole of the substance. (the mass per mole of a substance)

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5
Q

equation for amount of substance and molar mass etc.

A

Molar mass = mass (grams)/ amount in moles.

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6
Q

Equation to find the number of particles in a certain mass of a substance

A

no. of particles = (mass(g)/ molar mass (g/mol-1) ) * 6.02 *10^23 mol-1.

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7
Q

equation to find the specific number of particles of an element in a substance

A

particles= g * (Avogadro / Mr) * (number of atoms wanted / number of entire compound (usually 1))

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8
Q

% abundance from a spectrometer

A

% abundance = (peak height)/ total height of all peaks *100

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9
Q

the ideal gas equation

A
Pv = n RT 
p-pressure (Pa)
V- volume in m3
n- mols of molecules 
R- 8.31 
T temperature (kelvin)
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10
Q

how to turn degrees Celsius into kelvin

A

add 273.15

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11
Q

dm3 to m3

A

x 10^-3

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12
Q

cm3 to m3

A

x 10^-6

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13
Q

how to calculate % yield

A

actual yield/ theoretical x 100%

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14
Q

What affects % yield

A

The reaction didn’t go to completion
Other reactions may have occurred
The purification of the product may have resulted in the loss of some products.

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15
Q

What does atom economy tell us

A

Its a measure of how well atoms have been utilised

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16
Q

how to calculate atom economy

A

sum of desired products’ Mr/ sum of all products’ Mr x 100%

17
Q

why are reactions with a high atom economy good?

A

Produces more wanted products
less wasted unwanted products
important for sustainability