Chapter 24 Flashcards

(100 cards)

1
Q

Physical properties of d block elements

A

High melting points and boiling points
Shiny in appearance
Conduct both electricity and heat

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

Transition elements

A

D block elements that form at least one stable ion with a partially filled d-orbital

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

What two d block elements are not transition elements?

A

Scandium and zinc are d block elements but do not match the definition and are thus not classified as transition elements

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

Scandium

A

Only forms Sc3+ by loss of two 4s electrons and one 3d electron thus highest energy electron is in 3p subshell/orbital

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

Zinc

A

Only forms the Zn2+ ion by the loss of its two 4s electrons thus has a fully filled 3D subshell (full d-orbitals)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

Properties of transition metals?

A

They form compounds in which the transition element has different oxidation states
They form coloured compounds
The elements and their compounds can act as catalysts

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

Variable oxidation states

A

Transition elements form compounds with more than one oxidation state - number of oxidation states increases across the transition elements series to manganese and then decreases - all of the transition elements form compounds with an oxidation number of +2

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

Species containing transition metal in highest oxidation state?

A

A strong oxidising agent

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

Potassium dichromate (vi)

A

Bright orange

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

Cobalt (ii) chloride

A

Pink-purple

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

Nickel (ii) Sulfate

A

Green

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

Copper (ii) Sulfate

A

Blue

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

What is colour of transition element solution linked to?

A

Partially filled d-orbitals of the transition metal ion - colour varies with different oxidation states

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

Fe 2+

A

Pale green

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

Fe 3+

A

Yellow

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

Cr 3+

A

Green

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
17
Q

Cr +6

A

Yellow

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
18
Q

Haber process

A

Manufacture of ammonia from nitrogen and hydrogen
CATALYSED BY A FINELY DIVIDED IRON CATALYST

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
19
Q

Contact process

A

Sulfur trioxide from oxidation of sulfur dioxide - catalysed by vanadium oxide

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
20
Q

Hydrogenation of vegetable fats in manufacture of margarine?

A

Uses nickel as the catalyst

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
21
Q

Catalytic decomposition of hydrogen peroxide forming oxygen

A

Uses manganese oxide as the catalyst
2H2O2 -> 2H2O + O2

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
22
Q

Example of homogenous catalysts

A

Catalyst is in the same physical state as the reactants - reaction between iodide ions and peroxodisulfate ions is catalysed by Fe2+ (aq) ions

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
23
Q

Overall reaction homogenous catalyst

A

S2O82- (aq) + 2I- (aq) -> 2SO42- (aq) + I2 (aq)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
24
Q

When peroxodisulfate ions is carried out with a trace of starch

A

A blue-black colour forms ; if this experiment is repeated with a small a Fe2+ - blue black solution forms much more quickly demonstrating the catalytic action of transition metal ion

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
25
Fe2+ disulfate?
Forms Fe3+
26
Vital property of d-block elements?
Ability to form complex ions - blue solution is formed containing complex ion [Cu(H2O)6]2+
27
How can complex ions be formed?
Not restricted to d-block elements - other elements such as aluminium can also form complex ions
28
What is a ligand?
A molecule or ion that donates a pair of electrons to a central metal ion to form a coordinate bond or dative covalent bond
29
What is a ligand?
It is a molecule or ion that donates a pair of electrons to a central metal ion to form a coordinate bond or dative covalent bond
30
What is a dative covalent bond/coordinate bond?
Special kind of covalent bond which is formed when one of the bonded atoms provides both of the electrons for the shared pair - coordination number indicates the number of coordinate bonds attached to the central metal ion
31
Overall charge of complex ion
Sum of the charges on the central metal ion and any ligands present
32
Water acting as a ligand?
Each water molecule donating a lone pair of electrons from the oxygen atom to the central metal ion to form a coordinate bond
33
Monodentate ligand
A ligand that is able to donate one pair of electrons to a central metal ion
34
Examples of monodentate ligands
Water/ammonia/halides/cyanide
35
Bidentate ligands
Donate two lone pairs of electrons to the central metal ion forming two coordinate bonds
36
Common bidentate ligands?
1,2 - diaminoethane and ethanedioate
37
1,2-diaminoethane
Each nitrogen atom donates a pair of electrons to the central metal ion forming a coordinate bond
38
Ethanedioate ion
Each negatively charged oxygen atom donates a lone pair of electrons to the central metal ion
39
6 coordinate complexes?
With coordination number 6 an octahedral shape is produced - bond angles around central ion being 90 degrees
40
Complexes with coordination number 4
Either tetrahedral or square planar
41
Tetrahedral shape
Common of the two shapes with bond angles of 109.5 around the central metal ion
42
When does square planar shape occur?
Occurs in complex ions of transition metals with 8 d electrons in the highest energy d sub-shell ; platinum , palladium and gold fall in this category and tend to form square planar complexes
43
Square planar
Ligands are arranged with two going out and two going in 90 degrees bond angle
44
Platinum charge
2+
45
Palladium charge
2+
46
Gold charge
3+
47
For complex ions type of stereoisomerism?
Depends on number and type of ligands that are attached to central metal ion 4 and 6 coordinate complex ions containing two different monodentate ligands show cis-trans isomerism 6 coordinate complex ions containing monodentate and bidentate ligands can show both cis trans and optical isomerism
48
Cis trans isomerism in complex ions?
Cis-trans isomerism occurs in some square planar and octahedral complex ions
49
Cis-trans isomerism square planar
Simplest example of cis-trans isomerism is found in 4 coordinate square planar complexes that have no more than two identical ligands attached to the central metal ion
50
Cis square planar isomer?
Two identical groups are adjacent to each other - one going inside and one going outside (next to each other vertically)
51
Trans isomer
Two identical groups are diagonally opposite each other - coordinate bonds are 180 degrees apart
52
Cis-trans in monodentate ligands?
Octahedral complexes containing 4 of one type of ligand and two of another type of ligand also exist ast cis-trans isomers
53
Cis [Co(NH3)4Cl2]+
Chloride ligands are next to each other - 90 degrees apart (different bonds - one in the plane and the other going out)
54
Trans [Co(NH3)4Cl2]+
Chloride ligands are vertically opposite each other - 180 degrees apart - both ligands are in the same plane
55
Colours of [Co(NH3)4Cl2]+
Cis = violet Trans = green
56
Bidentate ligands cis-trans stereoisomerism
THERE SHOULD BE TWO OF THE SAME LIGANDS NEXT TO EACH OTHER (DIFFERENT PLANES) - 90 DEGREES APART FOR CIS AND 180 FOR TRANS (SAME PLANE)
57
Optical isomers
Non-superimposable mirror images of each other
58
Optical isomers of octahedral complexes?
Only occurs in octahedral complexes containing two or more bidentate ligands Can only form enantiomers of cis isomers
59
Optical isomers
Can also be seen in complexes containing 3 bidentate ligands
60
1,2-diaminoethane
Such a common bidentate ligand that it is often abbreviated to β€œen”
61
Ligand substitution reaction
One ligand in a complex ion is replaced by another ligand
62
Reactions of aqueous copper (ii) ions
Copper sulfate is dissolved in water and [Cu(H2O)6]2+ forms This is a pale blue solution which changes colour to form a dark blue solution when 4NH3 is added and replaces 4 of the H2O ligands producing 4H2O as a by-product
63
Breakdown of addition of 4NH3 to hexaaquacopper
Add the ammonia drop-wise to the solution - pale blue precipitate of Cu(OH)2 is formed in the first stage of the reaction - the precipitate then dissolves in excess ammonia to form a dark blue solution
64
Ligand substitution with chloride ions?
Concentrated HCl can be used as a source of chloride ions - excess is added - the pale blue solution changes colour to form a yellow solution which is another example of a ligand substitution reaction as 6 water ligands have been replaced with 4 chloride ligands
65
Observations of ligand substitution of chloride ions?
Intermediate green solution is formed but this is just the result of the yellow solution mixing with the blue solution to give a green colour as the reaction proceeds
66
Hexaaquacopper to tetrachlorocopper?
Change in coordination number : 6 to 4 Change in colour : pale blue to yellow solution Change in shape : octahedral to tetrahedral
67
Reasoning behind number of chloride ligands?
They are larger in size/bulkier than water ligands so fewer chloride ligands can fit around the central Cu2+ ion
68
What is chromium potassium Sulfate called?
Chrome alum
69
When chromium potassium Sulfate is dissolved in water?
Complex ion [Cr(H2O)6]3+ is formed - this is pale purple solution
70
When chromium iii Sulfate is dissolved in water?
Green solution containing chromium iii is formed - in this case it is the complex ion [Cr(H2O)5SO4]+ where ONE OF THE WATER LIGANDS IS REPLACED WITH SO4
71
Oxidation state of chromium ions?
+3
72
Equation for chromium ligand substitution reaction with ammonia?
[Cr(H2O)6]3+ + 6NH3 -> [Cr(NH3)6]3+ + 6H2O Where hexaaquachromium is violet and turns purple
73
Breakdown of reaction of ammonia with (cr(H2O)6) 3+
When the ammonia is added drop-wise to the chromium iii solution it takes place in two steps STEP 1 : grey-green precipitate of cr(oh)3 is formed STEP 2 : precipitate dissolves in excess ammonia to form the complex ion (cr(NH3)6)3+
74
Carbon monoxide + Fe2+
Forms carboxyhaemoglobin - ligand substitution reaction takes place where the oxygen in haemoglobin is replaced by carbon monoxide as carbon monoxide binds to haemoglobin more strongly than oxygen so a small concentration of carbon monoxide can prevent a large proportion of haemoglobin molecules from carrying oxygen
75
Carboxyhaemoglobin?
Bond is so strong that this process is irreversible
76
Precipitation reaction
When two aqueous solutions containing ions react together to form an insoluble ionic solid called a precipitate
77
Cu2+ reaction with NaOH
Blue solution forms a blue precipitate of copper hydroxide and PRECIPITATE IS INSOLUBLE IN EXCESS NAOH
78
Fe2+ with NaOH
Pale green solution reacts to form a green precipitate of Iron (ii) hydroxide - precipitate is insoluble in excess sodium hydroxide but turns brown at its surface on standing in air as iron (ii) is oxidised to iron (iii)
79
Fe3+ with NaOH
Pale yellow solution reacts to form an orange-brown precipitate of iron(iii) hydroxide - precipitate is insoluble in excess sodium hydroxide
80
Mn2+ and NaOH
Pale pink solution reacts to form a light brown precipitate of manganese (ii) hydroxide which darkens on standing in air PRECIPITATE IS INSOLUBLE IN EXCESS NAOH
81
Reaction of Cr3+ with NaOH
Violet solution reacts to form a grey-green precipitate of chromium (iii) hydroxide Precipitate is SOLUBLE IN EXCESS NAOH forming a dark green solution
82
Chain of reaction Cr3+ and NaOH
Cr3+ -> Cr(OH)3 -> [Cr(OH)6]3-
83
Copper hydroxide precipitate and ammonia?
Dissolves in excess ammonia to form a deep blue solution with the formula [Cu(NH3)4(H2O)2]2+
84
Chromium hydroxide precipitate + ammonia
Chromium hydroxide is a green precipitate which dissolves in excess ammonia to form [Cr(NH3)6]3+ which is a purple solution
85
Fe2+/Fe3+/Mn2+ + ammonia
All react with an excess of aqueous ammonia in the same way as they react with aqueous sodium hydroxide - forming precipitates of iron (ii and iii) hydroxide and manganese hydroxide - no further reaction with aqueous ammonia so these precipitates do not dissolve
86
Fe2+ + MnO4- ions
Fe2+ is oxidised to Fe3+ MnO4- is reduced to Mn2+ Solution containing MnO4- is purple and is decolourised by Fe2+ ions to form a colourless solution containing Mn2+ ions
87
Fe3+ to Fe2+
When a solution of Fe3+ reacts with iodide ions the orange brown Fe3+ ions are reduced to pale green Fe2+ ; this colour change is obscured by the oxidation of iodide ions to form iodine which has a brown colour
88
2Fe3+ + 2I- -> 2Fe2+ + I2
2Fe3+ is orange brown Fe2+ is pale green I2 is brown
89
Electrode potential for redox reactions?
More positive the electrode potential value - the more likely the species to undergo reduction and shift to the right, gaining electrons
90
How are cr2o72- ions reduced to cr3+?
Orange to green colour - reduced by the addition of zinc - with an excess of zinc, chromium iii ions are reduced further to chromium ii which is pale blue colour
91
Oxidation of cr3+ to cro42-
Hot alkaline hydrogen peroxide h2o2 is a powerful oxidising agent and can be used to oxidise chromium iii to chromium 6
92
Overall equation for oxidation of cr3+ to cro42-
3H2O2 + 2Cr3+ + 10OH- -> 2CrO42- + 8H2O
93
Reduction of Cu2+ to Cu+
When they react with excess iodide ions a redox reaction occurs and I- is oxidised to brown I2 while a white precipitate of copper iodide is also created
94
Equation for reduction of cu2+ to cu+
2Cu2+ + 4I- -> 2CuI + I2 (s) Pale blue Copper iodide is a white precipitate Iodine is brown
95
Disproportionation of Cu+ ions
Solid copper (I) oxide reacts with hot dilute H2SO4 - a brown precipitate of copper is formed together with a blue solution of copper (ii) Sulfate
96
Disproportionation of Cu+ ions equation
Cu2O + H2SO4 -> Cu + CuSO4 + H2O Copper goes from +1 to + 2 -1 to 0
97
Copper solid
Brown solid
98
Copper Sulfate
Blue solution
99
Ammonium ions + OH-
NH4- + OH- -> NH3 + H2O Ammonia is evolved it will turn damp red litmus paper blue
100
Halide ions solubility in NH3
Cl- soluble in dilute NH3 Br- soluble in concentrated nh3 I- insoluble in NH3