Chapter 23 Flashcards
Reduction
Gain of electrons or decrease in oxidation number
Oxidation
Loss of electrons or increase in oxidation number
What are likely products of redox reactions?
H2O, H+ or OH-
Two common redox titrations?
Potassium manganate (VII) under acidic conditions
Sodium thiosulfate Na2S2O3 for determination of iodine (I2)
Manganate VII titrations
These ions are reduced and so the other chemical must be the reducing agent that is oxidised - a standard solution is added to the burette and using a pipette a measured volume of the solution being analysed is added to the conical flask with an excess of dilute Sulfuric Acid to provide H+ ions required for reduction of MnO4- (this is self indicating)
During the titration the manganate solution reacts and is decolourised as it is added - END POINT = first permanent pink colour - repeat until obtain concordant titres
What to note about the meniscus?
KMnO4 is a deep purple colour so it is very difficult to see the bottom of the meniscus through the intense colour ; thus burette readings are read from the top rather than the bottom - titre is still the same provided it is read the same way from burette
Different reducing agents for potassium permanganate?
Iron (ii) ions
Ethanedioic acid
Reduce from MnO4- to Mn2+
Iodine thiosulfate titrations?
Thiosulfate ions are oxidised
Iodine is reduced
Oxidation of thiosulfate
2S2O32- -> S4O62- + 2e-
Reduction
I2 + 2e- -> 2I-
Overall redox reaction
2S2O32- + I2 -> 2I- + S4O62-
How to carry out analysis of oxidising agent using iodine thiosulfate titration?
Na2S2O3 to burette
Solution of oxidising agent is added to the conical flask with excess of potassium iodide - oxidising agent reacts with iodide to produce iodine which turns the solution a yellow brown colour
Titrations this solution with Sodium thiosulfate in burette and iodine is reduced back to I- ions and brown colour fades quite gradually with no set end point - by using a starch indicator we can fix this as at the end point all iodine will have just reacted and blue black colour disappears (all iodine reduced to I-)
What two oxidising agents can be analysed using iodine thiosulfate titrations?
Chlorate (I) ions, ClO-
Copper (ii) ions, Cu2+
Voltaic cell?
Converts chemical energy into electrical energy - electrical energy results from movement of electrons so you need chemical reactions that transfer electrons from one species to another (these are redox reactions)
Half cell
Contains chemical species present in a redox half-equation - voltaic cell can be made by connecting together two different half cells which allows electrons to flow
What if chemicals in two half cells are allowed to mix?
Electrons would flow in an uncontrolled way and heat energy would be released rather than electrical energy
Simples half cell
Metal rod dipped into a solution of its aqueous metal ion with the vertical line representing a phase boundary between aqueous solution and the metal - (Zn2+IZn)