Chapter 17 Practice Test Flashcards
Calculate the equilibrium constant for the reaction below given that Ka for sulfurous acid is 1.5 × 10−2.
H2SO3(aq) + OH-(aq) H2O(l) + HSO3^-(aq)
1.5 × 10^12
Suppose you begin with 100 mL each of 0.10 M acetic acid and 0.1 M sodium hydrogen sulfate and 0.10 M hydrochloric acid. If you add to each of these solutions 0.005 moles of sodium hydroxide, which one of the resulting solutions will have the lowest pH?
hydrochloric acid
In the following reaction,
HCl(aq) + NH3(aq) NH4Cl(aq)
the first intermediate reaction is the result of the strong acid, HCl(aq), and the weak base, NH3, interacting with the aqueous solution (i.e., water). This is also the final reaction.
First intermediate reaction:
H3O^+(aq) + Cl^-(aq) + NH3(aq) NH4^+(aq) + Cl^-(aq) + H2O(l)
Second intermediate reaction:
Nh3(aq) + H2O(l) NH4^+(aq) + OH-(aq)
Third intermediate reaction:
H3O^+(aq) + OH^-(aq) 2H2O(l)
Final reaction:
H3O^+(aq) + NH3(aq) NH4^+(aq) + H2O(l)
If all the reactants and products in the two intermediate reactions are added, the result is the final reaction. If Kb is the equilibrium constant for the second intermediate reaction and (1 / Kw ) is the equilibrium constant for the third intermediate reaction, what is the equilibrium constant for the final reaction, KFinal?
KFinal = Kb (1 / Kw ) = Kb / Kw
Look at the reaction of hydrochloric acid, a strong acid, and ammonia, a weak base, to (potentially) yield ammonium chloride.
HCl(aq) + NH3(aq) NH4Cl(aq)
One of the ions created by the dissociation of HCl in water is Cl −. What is the charge on the ammonium ion before it bonds with the Cl − ion?
+1
If 1.0 M solution of HNO2 is added to a solution that was already 0.2 M in NO2−, what is the pH of the solution for HNO2Ka = 5.6 x 10–4?
2.6
Look at the following reaction:
PCl5(g) PCl3(g) + Cl2(g)
Which of the following events would not cause the equilibrium to shift to the left?
Remove some Cl2(g).
A conjugate pair consists of two substances that are exclusively related by the gain or loss of a single hydrogen ion (H + ). Which of the following substance pairs is not a conjugate pair?
H3O and OH −
Suppose that you have an acidic buffer (pH < 7) that is formed by adding 1.12 moles of formic acid (HCOOH, Ka = 1.77 × 10−4 ) and 0.89 moles of sodium formate (NaHCOO) to water to make 1 L of solution. The weak acid in this reaction is formic acid, HCOOH. Its conjugate base, derived by removing a H + ion, is HCOO−. What is the pH of the acidic buffer solution?
3.65
Suppose that you add 0.35 M HCl to a buffer solution that consists of 0.95 M HCOOH and 0.53 M HCOO−. You have 1 L of the final solution. In this particular event, what is the acid buffer capacity of the solution?
0.18 M
1 L of an acidic buffer solution is made up of 1.53 M HCOOH and 1.53 M HCOO− is mixed with 0.03 mol HCl. What is the pH of the buffer solution (Ka = 1.77 × 10−4 )?
3.74
Suppose that we do a partial neutralization of 0.48 moles of NH3 by adding 0.18 moles of HCl to make 1.0 L of a basic buffer solution. What is the equilibrium pH of the buffer solution? Ka = 5.6 × 10−10 and Kw = 1.0 × 10−14.
9.48
Suppose that we do a partial neutralization of 0.25 moles of NH3 by adding 0.15 moles of HCl to make 1.0 L of a basic buffer solution. If x = [OH − ], which of the following gives the correct theoretical equilibrium concentrations for OH −, NH3, and NH4+?
[OH − ] = x; [ NH3 ] = 0.10 − x; [ NH4+ ] = 0.15 + x
Suppose that you want to prepare a buffer solution with a pH of 4.58. What is the correct value of [A− ] / [HA] for the correct buffer solution for this event?
0.692
The Henderson-Hasselbalch equation is based on the following equation:
Ka = [H3O+ ] [A− ] / [HA].
Which of the following correctly identifies the components of this equation?
Ka is the acid dissociation constant. [H3O+ ] is the hydronium ion concentration. [A− ] is the concentration of the conjugate base. [HA] is the concentration of the conjugate acid.
Suppose you have a 59 mL solution of 0.14 M HCl that is being titrated with 0.19 M NaOH. Before the equivalence point, you stop the titration. At this point, 25 mL of NaOH have been added. What is the change in pH at this point?
0.59