aromatic compounds and amines Flashcards

1
Q

what electron system does benzene have

A

delocalised electron ring

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2
Q

what is the formula for benzene

A

C6H6

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3
Q

what are the problems with Kerkules structure

A
  1. carbon carbon bonds are all the same length in the structure but we know double bonds are shorter
  2. benzene does not undergo addition reactions easily even though the structure has double bonds present
  3. we don’t get the expected isomers when we react benzene
  4. the hydrogenation of benzene is 152kjmol-1 less than expected if the structure was correct
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4
Q

why does benzene not undergo addition reaction easily

A

the delocalised electron ring is very stable and by removing these electrons to make another bond you make a less stable product

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5
Q

what is the expected enthalpy of hydrogenation of cyclohexatriene and how do you know

A

-360 as it is 3x -120 and -120 is the enthalpy of hydrogenation of one double bond in cyclohexatriene

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6
Q

why do we know benzene is more stable than cyclohexatriene

A

it requires more energy to hydrogenate benzene and therefore we know it requires more energy to break the delocalised system of electrons as less energy is given out when you break the bonds

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7
Q

why is cyclohexatriene so stable

A

it has alternating double and single bonds causing delocalised electrons which can overlap in the p orbitals meaning the electrons can move between them and this partial delocalisation causes stability in a compound

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8
Q

what type of reaction is nitration of benzene

A

nitration

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9
Q

what are the reactants needed in nitration of benzene

A

concentrated H2SO4 and HNO3

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10
Q

what is the mechanisms of nitration of benzene

A

electrophilic substitution

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11
Q

what are the equation to make the electrophile needed in the nitration of benzene

A
  1. HNO3 + H2SO4 –> H2N+O3 + HSO4-
  2. H2N+O3 —–> H2O + +NO2
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12
Q

what is the overall equation in forming the electrophile needed for nitration of benzene

A

HNO3 + H2SO4 —-> +NO3 + H2O + HSO-4

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13
Q

what is an amine

A

a lone pair on a nitrogen with 3 single bonds

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14
Q

what is the intermolecular bonding like between amines

A

hydrogen bonding between 1 and 2 amines

tertiary amines have dipole- dipole

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15
Q

what is an aromatic amine

A

when you have a N joined to a benzene ring with a lone pair

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16
Q

what is a cationic surfactant

A

quaternary ammonium salts with at least one long hydrocarbon tail which are partly soluble and insoluble in water

17
Q

what are uses of cationic surfactants

A

fabric softeners and hair products

18
Q

how do we measure the strength of a base

A

by how well it accepts protons

19
Q

what does a high electron density mean for a base

A

the higher the electron density of a lone pair the stronger the base will be

20
Q

what is a weaker base ammonia or ethylamine and why

A

Ammonia is a weaker base as there are no electron donating groups to cause the positive inductive effect whereas ethylamine has a positive inductive effect as the alkyl groups donate electron density to the N and its lone pair to become more available for protons

21
Q

what is a weaker base ammonia or phenylamine and why

A

phenylamine is a weaker base as it has a benzene ring that causes the nitrogen’s lone pair to become partially delocalised in the ring and is therefore less available to form a dative bond with a H+

22
Q

if the conditions for nucleophilic substitution of amines and halogenoalkanes is excess ammonia what is the main product

A

primary amines

23
Q

if the conditions for nucleophilic substitution of amines and halogenoalkanes is excess halogenoalkane what is the main product

A

quaternary salts

24
Q

can ammonia act as an electrophile to benzene and explain why

A

no as the delocalised ring in benzene repel the lone pair on the N

25
Q

what are uses of aromatic amines

A

explosives and dyes

26
Q

what are the two ways to make amines

A
  1. React nitrobenzene with a reducing agent under reflux with tin and conc. HCL followed by NaOH
  2. Reacting a nitrile with a reducing agent with LiAlH4 followed by dilute HCL
27
Q
A